結果
| 問題 |
No.1017 Reiwa Sequence
|
| ユーザー |
satashun
|
| 提出日時 | 2020-05-15 01:53:08 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,527 bytes |
| コンパイル時間 | 4,403 ms |
| コンパイル使用メモリ | 193,844 KB |
| 最終ジャッジ日時 | 2025-01-10 11:02:03 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 WA * 1 |
| other | AC * 36 WA * 14 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
template <class T>
using V = vector<T>;
template <class T>
using VV = V<V<T>>;
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define rep(i, n) rep2(i, 0, n)
#define rep2(i, m, n) for (int i = m; i < (n); i++)
#define ALL(c) (c).begin(), (c).end()
constexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n - 1); }
template <class T, class U>
void chmin(T& t, const U& u) {
if (t > u) t = u;
}
template <class T, class U>
void chmax(T& t, const U& u) {
if (t < u) t = u;
}
template <class T, class U>
ostream& operator<<(ostream& os, const pair<T, U>& p) {
os << "(" << p.first << "," << p.second << ")";
return os;
}
template <class T>
ostream& operator<<(ostream& os, const vector<T>& v) {
os << "{";
rep(i, v.size()) {
if (i) os << ",";
os << v[i];
}
os << "}";
return os;
}
#ifdef LOCAL
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
cerr << " " << H;
debug_out(T...);
}
#define debug(...) \
cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl
#else
#define debug(...) (void(0))
#define dump(x) (void(0))
#endif
const int B = 150000 * 11 + 5;
const int SZ = B * 2;
bool dp[24][SZ];
int pre[24][SZ];
int main() {
dp[0][B] = 1;
int N;
cin >> N;
V<int> A(N), ans(N);
rep(i, N) { cin >> A[i]; }
int now = 0;
rep(i, min(N, 23)) {
rep(j, SZ) {
if (dp[i][j]) {
if (j + A[i] < SZ) {
dp[i + 1][j + A[i]] = 1;
pre[i + 1][j + A[i]] = j;
}
dp[i + 1][j] = 1;
pre[i + 1][j] = j;
if (j - A[i] >= 0) {
dp[i + 1][j - A[i]] = 1;
pre[i + 1][j - A[i]] = j;
}
}
}
now++;
}
if (!dp[now][B]) {
puts("No");
return 0;
}
int p = now, v = B;
rep(t, now) {
int nx = pre[p][v];
--p;
if (nx < v) {
ans[p] = 1;
} else if (nx > v) {
ans[p] = -1;
} else {
ans[p] = 0;
}
v = nx;
}
puts("Yes");
rep(i, N) { printf("%d%c", ans[i] * A[i], i == N - 1 ? '\n' : ' '); }
return 0;
}
satashun