結果
問題 |
No.1017 Reiwa Sequence
|
ユーザー |
![]() |
提出日時 | 2020-05-15 01:57:21 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 548 ms / 2,000 ms |
コード長 | 2,710 bytes |
コンパイル時間 | 2,668 ms |
コンパイル使用メモリ | 193,868 KB |
最終ジャッジ日時 | 2025-01-10 11:03:38 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 50 |
ソースコード
#include <bits/stdc++.h> using namespace std; using ll = long long; using pii = pair<int, int>; template <class T> using V = vector<T>; template <class T> using VV = V<V<T>>; #define pb push_back #define eb emplace_back #define mp make_pair #define fi first #define se second #define rep(i, n) rep2(i, 0, n) #define rep2(i, m, n) for (int i = m; i < (n); i++) #define ALL(c) (c).begin(), (c).end() constexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n - 1); } template <class T, class U> void chmin(T& t, const U& u) { if (t > u) t = u; } template <class T, class U> void chmax(T& t, const U& u) { if (t < u) t = u; } template <class T, class U> ostream& operator<<(ostream& os, const pair<T, U>& p) { os << "(" << p.first << "," << p.second << ")"; return os; } template <class T> ostream& operator<<(ostream& os, const vector<T>& v) { os << "{"; rep(i, v.size()) { if (i) os << ","; os << v[i]; } os << "}"; return os; } #ifdef LOCAL void debug_out() { cerr << endl; } template <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << " " << H; debug_out(T...); } #define debug(...) \ cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__) #define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl #else #define debug(...) (void(0)) #define dump(x) (void(0)) #endif const int B = 150000 * 11 + 5; const int SZ = B * 2; bool dp[24][SZ]; int pre[24][SZ]; int main() { dp[0][B] = 1; int N; cin >> N; V<int> A(N), ans(N); rep(i, N) { cin >> A[i]; } int now = 0; rep(i, min(N, 23)) { rep(j, SZ) { if (dp[i][j]) { if (j + A[i] < SZ) { dp[i + 1][j + A[i]] = 1; pre[i + 1][j + A[i]] = j; } if (dp[i + 1][j] == 0) { dp[i + 1][j] = 1; pre[i + 1][j] = j; } if (j - A[i] >= 0) { dp[i + 1][j - A[i]] = 1; pre[i + 1][j - A[i]] = j; } } } now++; } if (!dp[now][B]) { puts("No"); return 0; } int p = now, v = B; bool ok = 0; rep(t, now) { int nx = pre[p][v]; --p; if (nx < v) { ans[p] = 1; ok = 1; } else if (nx > v) { ans[p] = -1; ok = 1; } else { ans[p] = 0; } v = nx; } if (!ok) { puts("No"); return 0; } puts("Yes"); rep(i, N) { printf("%d%c", ans[i] * A[i], i == N - 1 ? '\n' : ' '); } return 0; }