結果
| 問題 |
No.1048 Zero (Advanced)
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-05-15 17:30:19 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
RE
|
| 実行時間 | - |
| コード長 | 2,342 bytes |
| コンパイル時間 | 2,567 ms |
| コンパイル使用メモリ | 190,288 KB |
| 実行使用メモリ | 17,664 KB |
| 最終ジャッジ日時 | 2024-09-19 04:33:32 |
| 合計ジャッジ時間 | 3,697 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 14 RE * 1 |
ソースコード
//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops")
//#pragma GCC target("avx,avx2")
//#pragma GCC target("avx2")
//#pragma GCC optimize("O3")
//# include <x86intrin.h>
# include <bits/stdc++.h>
# include <ext/pb_ds/assoc_container.hpp>
# include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
template<typename T> using ordered_set = tree <T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define _USE_MATH_DEFINES_
#define ll long long
#define ld long double
#define Accepted 0
#define pb push_back
#define mp make_pair
#define sz(x) (int)(x.size())
#define every(x) x.begin(),x.end()
#define F first
#define S second
#define lb lower_bound
#define ub upper_bound
#define For(i,x,y) for (ll i = x; i <= y; i ++)
#define FOr(i,x,y) for (ll i = x; i >= y; i --)
#define SpeedForce ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
// ROAD to... Red
inline void Input_Output () {
//freopen(".in", "r", stdin);
//freopen(".out", "w", stdout);
}
const double eps = 0.000001;
const ld pi = acos(-1);
const int maxn = 1e7 + 9;
const int mod = 1e9 + 7;
const ll MOD = 1e18 + 9;
const ll INF = 1e18 + 123;
const int inf = 2e9 + 11;
const int mxn = 1e6 + 9;
const int N = 6e5 + 123;
const int M = 22;
const int pri = 997;
const int Magic = 2101;
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, -1, 0, 1};
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int n, m, k;
int cnt[N];
string s;
int a[N];
vector < int > g[N];
int u[N];
int ans, res;
int cur;
int main () {
SpeedForce;
int l, r, m, k;
cin >> l >> r >> m >> k;
if ((r/m) > (l-1)/m || !k) {
cout << "Yes\n";
return 0;
}
vector < int > d;
for (int i = 1; i * (ll)i <= m; ++i) {
if(m%i==0) {
d.pb(i);
d.pb(m/i);
}
}
for (int i : d) {
int dv = (l-1) / i;
ll cur = dv * (ll)i + i;
ll lcm = cur / __gcd(cur, (ll)m) * (ll)m;
if (cur >= l && cur <= r && k%(lcm / cur)==0) {
//cout << cur << ' ' << lcm << '\n';
cout << "Yes\n";
return 0;
}
}
cout << "No\n";
return Accepted;
}
// B...a