結果

問題 No.1068 #いろいろな色 / Red and Blue and more various colors (Hard)
ユーザー otamay6otamay6
提出日時 2020-05-29 22:29:19
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 4,113 bytes
コンパイル時間 2,066 ms
コンパイル使用メモリ 179,236 KB
実行使用メモリ 359,316 KB
最終ジャッジ日時 2024-11-06 05:53:31
合計ジャッジ時間 32,230 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 13 RE * 1 TLE * 15
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define ll long long
#define INF 1000000005
#define EPS 1e-10
#define rep(i,n) for(int i=0;i<(int)(n);++i)
#define rrep(i,n) for(int i=(int)(n)-1;i>=0;--i)
#define srep(i,s,t) for(int i=(int)(s);i<(int)(t);++i)
#define each(a,b) for(auto& (a): (b))
#define all(v) (v).begin(),(v).end()
#define len(v) (int)(v).size()
#define zip(v) sort(all(v)),v.erase(unique(all(v)),v.end())
#define cmx(x,y) x=max(x,y)
#define cmn(x,y) x=min(x,y)
#define fi first
#define se second
#define pb push_back
#define show(x) cout<<#x<<" = "<<(x)<<endl
#define spair(p) cout<<#p<<": "<<p.fi<<" "<<p.se<<endl
#define sar(a,n) cout<<#a<<":";rep(pachico,n)cout<<" "<<a[pachico];cout<<endl
#define svec(v) cout<<#v<<":";rep(pachico,v.size())cout<<" "<<v[pachico];cout<<endl
#define svecp(v) cout<<#v<<":";each(pachico,v)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl
#define sset(s) cout<<#s<<":";each(pachico,s)cout<<" "<<pachico;cout<<endl
#define smap(m) cout<<#m<<":";each(pachico,m)cout<<" {"<<pachico.first<<":"<<pachico.second<<"}";cout<<endl
using namespace std;
typedef pair<int,int> P;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vl;
typedef vector<vl> vvl;
typedef vector<double> vd;
typedef vector<P> vp;
typedef vector<string> vs;
const int MAX_N = 200005;
#define MOD 998244353
#define root 5
unsigned int add(const unsigned int x, const unsigned int y)
{
return (x + y < MOD) ? x + y : x + y - MOD;
}
unsigned int sub(const unsigned int x, const unsigned int y)
{
return (x >= y) ? (x - y) : (MOD - y + x);
}
unsigned int mul(const unsigned int x, const unsigned int y)
{
return (unsigned long long)x * y % MOD;
}
unsigned int mod_pow(unsigned int x, unsigned int n)
{
unsigned int res = 1;
while(n > 0){
if(n & 1){ res = mul(res, x); }
x = mul(x, x);
n >>= 1;
}
return res;
}
unsigned int inverse(const unsigned int x)
{
return mod_pow(x, MOD - 2);
}
void ntt(vector<int>& a, const bool rev = false)
{
unsigned int i, j, k, l, p, q, r, s;
const unsigned int size = a.size();
if(size == 1) return;
vector<int> b(size);
r = rev ? (MOD - 1 - (MOD - 1) / size) : (MOD - 1) / size;
s = mod_pow(root, r);
vector<unsigned int> kp(size / 2 + 1, 1);
for(i = 0; i < size / 2; ++i) kp[i + 1] = mul(kp[i], s);
for(i = 1, l = size / 2; i < size; i <<= 1, l >>= 1){
for(j = 0, r = 0; j < l; ++j, r += i){
for(k = 0, s = kp[i * j]; k < i; ++k){
p = a[k + r], q = a[k + r + size / 2];
b[k + 2 * r] = add(p, q);
b[k + 2 * r + i] = mul(sub(p, q), s);
}
}
swap(a, b);
}
if(rev){
s = inverse(size);
for(i = 0; i < size; i++){ a[i] = mul(a[i], s); }
}
}
vector<int> convolute(const vector<int>& a, const vector<int>& b)
{
const int size = (int)a.size() + (int)b.size() - 1;
int t = 1;
while (t < size) { t <<= 1; }
vector<int> A(t, 0), B(t, 0);
for (int i = 0; i < (int)a.size(); i++) { A[i] = a[i]; }
for (int i = 0; i < (int)b.size(); i++) { B[i] = b[i]; }
ntt(A), ntt(B);
for (int i = 0; i < t; i++) { A[i] = mul(A[i], B[i]); }
ntt(A, true);
A.resize(size);
return A;
}
bool used[MAX_N];
int inv[MAX_N],fac[MAX_N],finv[MAX_N];
void make()
{
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for(int i=2;i<MAX_N;i++){
inv[i] = MOD - (ll)inv[MOD%i] * (MOD/i) % MOD;
fac[i] = (ll)fac[i-1] * i % MOD;
finv[i] = (ll)finv[i-1] * inv[i] % MOD;
}
}
int comb(int a,int b)
{
if(a<b){
return 0;
}
return fac[a] * ((ll)finv[b] * finv[a-b] % MOD) % MOD;
}
int main()
{
int N,Q;
cin>>N>>Q;
vector<int> A(N);
for(int i=0;i<N;++i) cin>>A[i];
vector<vector<vector<int>>> f(30,vector<vector<int>>(N+1,vector<int>(1,1)));
rep(i,N) f[0][i] = {A[i]-1,1};
int dan = 0,cnt = N;
while(cnt>=2){
int l = 0;
while(2*l<cnt){
f[dan+1][l] = convolute(f[dan][2*l], f[dan][2*l+1]);
l++;
}
dan++;
cnt = (cnt+1)/2;
}
rep(_,Q){
int B;cin>>B;
cout<<f[dan][0][B]<<"\n";
}
}
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