#489358 (C++17) No.1069 電柱 / Pole (Hard)

提出ソース

結果

問題	No.1069 電柱 / Pole (Hard)
ユーザー	👑 hitonanode
提出日時	2020-05-30 00:45:00
言語	C++17 (gcc 13.2.0 + boost 1.83.0)
結果	AC
実行時間	789 ms / 2,000 ms
コード長	9,223 bytes
コンパイル時間	2,924 ms
コンパイル使用メモリ	240,696 KB
実行使用メモリ	9,212 KB
最終ジャッジ日時	2023-09-30 21:20:05
合計ジャッジ時間	12,443 ms
ジャッジサーバーID （参考情報）	judge14 / judge15

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	1 ms 4,376 KB
testcase_01	AC	2 ms 4,376 KB
testcase_02	AC	1 ms 4,376 KB
testcase_03	AC	2 ms 4,380 KB
testcase_04	AC	545 ms 8,360 KB
testcase_05	AC	789 ms 9,080 KB
testcase_06	AC	73 ms 4,424 KB
testcase_07	AC	19 ms 4,384 KB
testcase_08	AC	515 ms 6,856 KB
testcase_09	AC	63 ms 4,380 KB
testcase_10	AC	18 ms 4,376 KB
testcase_11	AC	2 ms 4,380 KB
testcase_12	AC	4 ms 4,376 KB
testcase_13	AC	23 ms 4,384 KB
testcase_14	AC	11 ms 4,376 KB
testcase_15	AC	522 ms 9,212 KB
testcase_16	AC	153 ms 4,516 KB
testcase_17	AC	18 ms 4,380 KB
testcase_18	AC	162 ms 4,676 KB
testcase_19	AC	396 ms 6,404 KB
testcase_20	AC	18 ms 4,380 KB
testcase_21	AC	17 ms 4,376 KB
testcase_22	AC	7 ms 4,376 KB
testcase_23	AC	53 ms 4,380 KB
testcase_24	AC	469 ms 5,080 KB
testcase_25	AC	444 ms 4,884 KB
testcase_26	AC	401 ms 4,744 KB
testcase_27	AC	402 ms 4,696 KB
testcase_28	AC	402 ms 4,688 KB
testcase_29	AC	4 ms 4,376 KB
testcase_30	AC	2 ms 4,380 KB
testcase_31	AC	1 ms 4,380 KB
testcase_32	AC	1 ms 4,380 KB
testcase_33	AC	2 ms 4,376 KB
testcase_34	AC	2 ms 4,380 KB
testcase_35	AC	2 ms 4,376 KB
testcase_36	AC	2 ms 4,380 KB
testcase_37	AC	58 ms 4,720 KB
testcase_38	AC	10 ms 4,376 KB
testcase_39	AC	3 ms 4,376 KB
testcase_40	AC	71 ms 5,760 KB
testcase_41	AC	49 ms 4,380 KB
testcase_42	AC	79 ms 5,940 KB
testcase_43	AC	4 ms 4,376 KB
testcase_44	AC	54 ms 4,380 KB
testcase_45	AC	33 ms 4,376 KB
testcase_46	AC	220 ms 4,848 KB
testcase_47	AC	133 ms 4,376 KB
testcase_48	AC	126 ms 4,564 KB
testcase_49	AC	34 ms 4,384 KB
testcase_50	AC	3 ms 4,380 KB
testcase_51	AC	225 ms 4,588 KB
testcase_52	AC	3 ms 4,376 KB
testcase_53	AC	42 ms 4,376 KB
testcase_54	AC	1 ms 4,376 KB
testcase_55	AC	3 ms 4,376 KB
testcase_56	AC	2 ms 4,376 KB
testcase_57	AC	4 ms 4,376 KB
testcase_58	AC	1 ms 4,380 KB
testcase_59	AC	3 ms 4,376 KB
testcase_60	AC	2 ms 4,376 KB
testcase_61	AC	7 ms 4,376 KB
testcase_62	AC	2 ms 4,376 KB
testcase_63	AC	1 ms 4,376 KB
testcase_64	AC	5 ms 4,376 KB
testcase_65	AC	2 ms 4,380 KB
testcase_66	AC	2 ms 4,376 KB
testcase_67	AC	2 ms 4,380 KB
testcase_68	AC	2 ms 4,380 KB
testcase_69	AC	11 ms 4,376 KB
testcase_70	AC	3 ms 4,376 KB
testcase_71	AC	8 ms 4,376 KB
testcase_72	AC	5 ms 4,380 KB
testcase_73	AC	11 ms 4,376 KB
testcase_74	AC	12 ms 4,380 KB
testcase_75	AC	12 ms 4,380 KB
testcase_76	AC	68 ms 4,392 KB
testcase_77	AC	69 ms 4,384 KB
testcase_78	AC	7 ms 4,380 KB
testcase_79	AC	19 ms 4,376 KB
testcase_80	AC	48 ms 4,376 KB
testcase_81	AC	64 ms 4,376 KB
testcase_82	AC	16 ms 4,380 KB

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ソースコード

raw source code

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(6); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
using namespace __gnu_pbds; // find_by_order(), order_of_key()
template<typename TK> using pbds_set = tree<TK, null_type, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename TK, typename TV> using pbds_map = tree<TK, TV, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;
*/

template<typename T>
struct ShortestPath
{
    int V, E;
    int INVALID = -1;
    std::vector<std::vector<std::pair<int, T>>> to;
    ShortestPath() = default;
    ShortestPath(int V) : V(V), E(0), to(V) {}
    void add_edge(int s, int t, T len) {
        assert(0 <= s and s < V);
        assert(0 <= t and t < V);
        to[s].emplace_back(t, len);
        E++;
    }

    std::vector<T> dist;
    std::vector<int> prev;
    // Dijkstra algorithm
    // Complexity: O(E log E)
    void Dijkstra(int s) {
        assert(0 <= s and s < V);
        dist.assign(V, 1e18);
        dist[s] = 0;
        prev.assign(V, INVALID);
        using P = std::pair<T, int>;
        std::priority_queue<P, std::vector<P>, std::greater<P>> pq;
        pq.emplace(0, s);
        while(!pq.empty()) {
            T d;
            int v;
            std::tie(d, v) = pq.top();
            pq.pop();
            if (dist[v] < d) continue;
            for (auto nx : to[v]) {
                T dnx = d + nx.second;
                if (dist[nx.first] > dnx) {
                    dist[nx.first] = dnx, prev[nx.first] = v;
                    pq.emplace(dnx, nx.first);
                }
            }
        }
    }

    // Bellman-Ford algorithm
    // Complexity: O(VE)
    bool BellmanFord(int s, int nb_loop) {
        assert(0 <= s and s < V);
        dist.assign(V, std::numeric_limits<T>::max());
        dist[s] = 0;
        prev.assign(V, INVALID);
        for (int l = 0; l < nb_loop; l++) {
            bool upd = false;
            for (int v = 0; v < V; v++) {
                if (dist[v] == std::numeric_limits<T>::max()) continue;
                for (auto nx : to[v]) {
                    T dnx = dist[v] + nx.second;
                    if (dist[nx.first] > dnx) {
                        dist[nx.first] = dnx, prev[nx.first] = v;
                        upd = true;
                    }
                }
            }
            if (!upd) return true;
        }
        return false;
    }
    // Warshall-Floyd algorithm
    // Complexity: O(E + V^3)
    std::vector<std::vector<T>> dist2d;
    void WarshallFloyd() {
        dist2d.assign(V, std::vector<T>(V, std::numeric_limits<T>::max()));
        for (int i = 0; i < V; i++) {
            dist2d[i][i] = 0;
            for (auto p : to[i]) dist2d[i][p.first] = min(dist2d[i][p.first], p.second);
        }
        for (int k = 0; k < V; k++) {
            for (int i = 0; i < V; i++) {
                if (dist2d[i][k] = std::numeric_limits<T>::max()) continue;
                for (int j = 0; j < V; j++) {
                    if (dist2d[k][j] = std::numeric_limits<T>::max()) continue;
                    dist2d[i][j] = min(dist2d[i][j], dist2d[i][k] + dist2d[k][j]);
                }
            }
        }
    }
};

using BS = bitset<4000>;
int serial;
struct P_
{
    double first;
    BS second;
    BS third;
    int id_;
    P_() = default;
    P_(double a, BS b, BS path) : first(a), second(b), third(path), id_(serial++) {}
    // bool operator<(const P_ &x) const { return first < x.first; }
    bool operator>(const P_ &x) const {
        if (first != x.first) return first > x.first;
        return id_ > x.id_;
    }
};



int main()
{
    int N, M, K;
    int X, Y;
    cin >> N >> M >> K >> X >> Y;
    X--, Y--;
    vector<lint> P(N), Q(N);
    REP(i, N) cin >> P[i] >> Q[i];
    vector<double> e(M * 2);
    vector<int> from(M * 2), to(M * 2);

    ShortestPath<double> graph(N);

    map<pint, int> e2id;
    REP(i, M)
    {
        int s, t;
        cin >> s >> t;
        s--, t--;
        double dx = P[s] - P[t];
        double dy = Q[s] - Q[t];
        e[i] = e[i + M] = sqrt(dx * dx + dy * dy);
        from[i] = to[i + M] = s;
        from[i + M] = to[i] = t;
        graph.add_edge(s, t, e[i]);
        graph.add_edge(t, s, e[i]);
        e2id[pint(s, t)] = i;
        e2id[pint(t, s)] = i + M;
    }
    graph.Dijkstra(X);
    BS path;
    path.reset();
    int now = Y;
    while (now != X)
    {
        int prv = graph.prev[now];
        path[e2id[pint(prv, now)]] = 1;
        now = prv;
    }
    vector<BS> checked;
    priority_queue<P_, vector<P_>, greater<P_>> pq;
    vector<BS> alivebs;
    vector<BS> pathbs;
    vector<double> ret;

    BS state_;
    REP(i, M * 2) state_[i] = 1;
    checked.emplace_back(state_);
    alivebs.emplace_back(state_);
    pathbs.emplace_back(path);
    ret.emplace_back(graph.dist[Y]);

    while (ret.size() < K)
    {
        REP(eban, M * 2) if (pathbs.back()[eban])
        {
            BS b = alivebs.back();
            b[eban] = 0;
            ShortestPath<double> graph(N);
            REP(i, M * 2) if (b[i])
            {
                graph.add_edge(from[i], to[i], e[i]);
            }
            graph.Dijkstra(X);
            if (graph.dist[Y] > 1e16) continue;
            BS path;
            int now = Y;
            while (now != X)
            {
                int prv = graph.prev[now];
                path[e2id[pint(prv, now)]] = 1;
                now = prv;
            }
            pq.emplace(graph.dist[Y], b, path);
        }

        bool flg_conti = true;
        while (true)
        {
            if (pq.empty())
            {
                flg_conti = false;
                break;
            }
            bool bad = false;
            for (auto x : pathbs)
            {
                if (x == pq.top().third) bad = true;
            }
            if (!bad)
            {
                ret.emplace_back(pq.top().first);
            }
            alivebs.emplace_back(pq.top().second);
            pathbs.emplace_back(pq.top().third);
            pq.pop();
            break;
        }
        if (!flg_conti) break;
    }

    if (ret.size() < K) ret.resize(K, -1);
    REP(i, K)
    {
        if (ret[i] >= 0) cout << ret[i] << '\n';
        else cout << -1 << '\n';
    }
}

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結果

テストケース

ソースコード