結果

問題 No.1077 Noelちゃんと星々4
ユーザー k_tsushima
提出日時 2020-06-13 05:35:49
言語 Java
(openjdk 23)
結果
AC  
実行時間 166 ms / 2,000 ms
コード長 2,186 bytes
コンパイル時間 2,088 ms
コンパイル使用メモリ 77,508 KB
実行使用メモリ 89,112 KB
最終ジャッジ日時 2024-06-24 09:42:16
合計ジャッジ時間 5,613 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
private static class FastScanner {
private BufferedReader reader = null;
private StringTokenizer tokenizer = null;
public FastScanner(InputStream in) {
reader = new BufferedReader(new InputStreamReader(in));
tokenizer = null;
}
public String next() {
if (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public String nextLine() {
if (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
return reader.readLine();
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken("\n");
}
public long nextLong() {
return Long.parseLong(next());
}
public int nextInt() {
return Integer.parseInt(next());
}
public double nextDouble() {
return Double.parseDouble(next());
}
public int[] nextIntArray(int n) {
int[] a = new int[n];
for (int i = 0; i < n; i++)
a[i] = nextInt();
return a;
}
public long[] nextLongArray(int n) {
long[] a = new long[n];
for (int i = 0; i < n; i++)
a[i] = nextLong();
return a;
}
}
public static void main(String[] args) {
FastScanner sc = new FastScanner(System.in);
int n = sc.nextInt();
int[] y = sc.nextIntArray(n);
int[][] dp = new int[n + 1][10001];
for (int i = 0; i < n; i++) {
for (int j = 0; j <= 10000; j++) {
if (j == 0) {
dp[i + 1][j] = dp[i][j] + Math.abs(y[i] - j);
} else {
dp[i + 1][j] = Math.min(dp[i][j] + Math.abs(y[i] - j), dp[i + 1][j - 1]);
}
}
}
int result = Integer.MAX_VALUE;
for (int j = 0; j <= 10000; j++) {
result = Math.min(result, dp[n][j]);
}
System.out.println(result);
}
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0