結果

問題 No.1120 Strange Teacher
ユーザー Konton7
提出日時 2020-07-24 13:42:45
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 4,808 bytes
コンパイル時間 2,103 ms
コンパイル使用メモリ 200,624 KB
最終ジャッジ日時 2025-01-12 04:55:49
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 23 WA * 2 RE * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using VI = vector<int>;
using VL = vector<ll>;
using VS = vector<string>;
using VB = vector<bool>;
using VVB = vector<vector<bool>>;
using VVI = vector<VI>;
using VVL = vector<VL>;
using PII = std::pair<int, int>;
using VPII = std::vector<std::pair<int, int>>;
using PLL = std::pair<ll, ll>;
using VPLL = std::vector<std::pair<ll, ll>>;
using TI3 = std::tuple<int, int, int>;
using TI4 = std::tuple<int, int, int, int>;
using TL3 = std::tuple<ll, ll, ll>;
using TL4 = std::tuple<ll, ll, ll, ll>;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n)-1; i >= 0; i--)
#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)
#define rep3(i, s, n, d) for (int i = (s); i < (int)(n); i += (d))
#define allpt(v) (v).begin(), (v).end()
#define allpt_c(v) (v).cbegin(), (v).cend()
#define allpt_r(v) (v).rbegin(), (v).rend()
#define allpt_cr(v) (v).crbegin(), (v).crend()
const int mod1 = 1e9 + 7, mod2 = 998244353, mod3 = 1e9 + 9;
const int mod = mod1;
const ll inf = 1e18;
const string wsp = " ";
const string tb = "\t";
const string rt = "\n";
template <typename T>
void show1dvec(const vector<T> &v)
{
if (v.size() == 0)
return;
int n = v.size() - 1;
rep(i, n) cout << v[i] << wsp;
cout << v[n] << rt;
return;
}
template <typename T>
void show2dvec(const vector<vector<T>> &v)
{
int n = v.size();
rep(i, n) show1dvec(v[i]);
}
template <typename T, typename S>
void show1dpair(const vector<pair<T, S>> &v)
{
int n = v.size();
rep(i, n) cout << v[i].first << wsp << v[i].second << rt;
return;
}
template <typename T, typename S>
void pairzip(const vector<pair<T, S>> &v, vector<T> &t, vector<T> &s)
{
int n = v.size();
rep(i, n)
{
t.push_back(v[i].first);
s.push_back(v[i].second);
}
return;
}
template <typename T>
void maxvec(vector<T> &v)
{
T s = v[0];
int n = v.size();
rep(i, n - 1)
{
if (s > v[i + 1])
{
v[i + 1] = s;
}
s = v[i + 1];
}
}
template <typename T, typename S>
bool myfind(T t, S s)
{
return find(t.cbegin(), t.cend(), s) != t.cend();
}
bool check(int y, int x, int h, int w)
{
return 0 <= y && y < h && 0 <= x && x < w;
}
bool iskadomatsu(int a, int b, int c)
{
return (a != b && b != c && c != a) && ((a > b && b < c) || (a < b && b > c));
}
VS split(string s, char c)
{
VS ret;
string part;
s += c;
rep(i, s.length())
{
if (s[i] == c)
{
ret.emplace_back(part);
part = "";
}
else if (s[i] != c)
{
part += s[i];
}
}
return ret;
}
template <typename T, typename S, typename R>
ll pow_mod(T p, S q, R mod = 1ll)
{
ll ret = 1, r = p;
while (q)
{
if (q % 2)
ret *= r, ret %= mod;
r = (r * r) % mod, q /= 2;
}
return ret % mod;
}
template <typename T, typename S>
ll pow_no_mod(T p, S q)
{
ll ret = 1, r = p;
while (q)
{
if (q % 2)
ret *= r;
r = (r * r), q /= 2;
}
return ret;
}
void make_frac_tables(VL &frac_list, VL &frac_inv_list)
{
rep(i, frac_list.size() - 1)
{
frac_list[i + 1] *= frac_list[i] * (i + 1);
frac_list[i + 1] %= mod;
frac_inv_list[i + 1] *= frac_inv_list[i] * pow_mod(i + 1, mod - 2, mod);
frac_inv_list[i + 1] %= mod;
}
}
ll comb(int a, int b, const VL &frac_list, const VL &frac_inv_list)
{
if (a < b)
return 0;
if (b < 0)
return 0;
ll ret = frac_list[a];
ret *= frac_inv_list[b];
ret %= mod;
ret *= frac_inv_list[a - b];
ret %= mod;
return ret;
}
int main()
{
// cin.tie(0);
// ios::sync_with_stdio(false);
#ifdef DEBUG
cout << "DEBUG MODE" << endl;
ifstream in("input.txt"); //for debug
cin.rdbuf(in.rdbuf()); //for debug
#endif
int n;
cin >> n;
VL a(n), b(n);
rep(i, n) cin >> a[i];
rep(i, n) cin >> b[i];
ll sa, sb, k, d;
sa = accumulate(allpt(a), 0ll);
sb = accumulate(allpt(b), 0ll);
if (sa < sb || (sa - sb) % (n - 2) != 0)
{
cout << -1 << rt;
return 0;
}
if (n == 2 && sa == sb)
{
cout << abs(a[0] - b[0]) << rt;
return 0;
}
if (n == 2)
{
cout << -1 << rt;
return 0;
}
k = (sa - sb) / (n - 2);
d = 2 * k;
rep(i, n)
{
a[i] -= k;
}
rep(i, n)
{
if ((b[i] - a[i]) % 2 == 1)
{
cout << -1 << rt;
return 0;
}
else
{
d -= (b[i] - a[i]);
a[i] = b[i];
}
}
cout << (d == 0 ? k : -1) << rt;
return 0;
}
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