結果

問題 No.298 話の伝達
ユーザー heno239heno239
提出日時 2020-08-23 12:40:02
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 3,607 bytes
コンパイル時間 1,424 ms
コンパイル使用メモリ 126,084 KB
実行使用メモリ 16,000 KB
最終ジャッジ日時 2024-10-15 18:08:06
合計ジャッジ時間 2,962 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 5 ms
7,680 KB
testcase_01 AC 6 ms
7,808 KB
testcase_02 AC 5 ms
7,808 KB
testcase_03 AC 5 ms
7,680 KB
testcase_04 AC 5 ms
7,680 KB
testcase_05 AC 58 ms
16,000 KB
testcase_06 AC 5 ms
7,936 KB
testcase_07 AC 5 ms
7,552 KB
testcase_08 AC 5 ms
7,680 KB
testcase_09 WA -
testcase_10 WA -
testcase_11 AC 23 ms
15,872 KB
testcase_12 AC 12 ms
11,648 KB
testcase_13 WA -
testcase_14 WA -
testcase_15 AC 6 ms
7,808 KB
testcase_16 AC 241 ms
15,872 KB
testcase_17 AC 7 ms
7,808 KB
testcase_18 AC 51 ms
9,856 KB
testcase_19 AC 5 ms
7,552 KB
testcase_20 AC 108 ms
11,776 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acosl(-1.0);

ll mod_pow(ll x, ll n, ll m) {
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
struct modint {
	ll n;
	modint() :n(0) { ; }
	modint(ll m) :n(m) {
		if (n >= mod)n %= mod;
		else if (n < 0)n = (n % mod + mod) % mod;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }

const int max_n = 1 << 18;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}

struct edge {
	int to; ld cost;
};

ld dp[1 << 20];
void solve() {
	int n, m; cin >> n >> m;
	vector<vector<edge>> G(n);
	rep(i, m) {
		int a, b; ld c; cin >> a >> b >> c;
		c /= 100.0;
		G[a].push_back({ b,c });
	}
	vector<bool> used(n);
	queue<int> q; q.push(0); used[0] = true;
	vector<pair<P, ld>> memo;
	while (!q.empty()) {
		int id = q.front(); q.pop();
		for (edge e : G[id]) {
			memo.push_back({ {id,e.to},e.cost });
			if (!used[e.to]) {
				used[e.to] = true; q.push(e.to);
			}
		}
	}
	dp[1] = 1;
	rep(i, memo.size()) {
		int a = memo[i].first.first;
		int b = memo[i].first.second;
		ld c = memo[i].second;
		per(j, (1 << n)) {
			if (j & (1 << b))continue;
			if (j & (1 << a)) {
				dp[j ^ (1 << b)] += dp[j] * c;
				dp[j] *= (1 - c);
			}
		}
		
	}
	ld ans = 0;
	rep(j, (1 << n))if(j&(1<<n-1))ans += dp[j];
	cout << ans << "\n";
}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout << fixed << setprecision(10);
	//init_f();
	//expr();
	//int t; cin >> t; rep(i, t)
	//while (cin >> n >> m>>s1>>s2>>t, n)
	solve();
	return 0;
}
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