結果
| 問題 | No.1208 anti primenumber game | 
| コンテスト | |
| ユーザー |  | 
| 提出日時 | 2020-08-30 15:43:20 | 
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 125 ms / 2,000 ms | 
| コード長 | 3,802 bytes | 
| コンパイル時間 | 2,563 ms | 
| コンパイル使用メモリ | 206,316 KB | 
| 最終ジャッジ日時 | 2025-01-13 22:54:56 | 
| ジャッジサーバーID (参考情報) | judge5 / judge2 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 44 | 
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define ALL(obj) (obj).begin(),(obj).end()
template<class T> using priority_queue_reverse = priority_queue<T,vector<T>,greater<T>>;
constexpr long long MOD = 1'000'000'000LL + 7;
constexpr long long MOD2 = 998244353;
constexpr long long HIGHINF = (long long)1e18;
constexpr long long LOWINF = (long long)1e15;
constexpr long double PI = 3.1415926535897932384626433L;
template <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}
template <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}
template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}
template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}
template <class T> void chmax(T& a, const T b){a=max(a,b);}
template <class T> void chmin(T& a, const T b){a=min(a,b);}
vector<string> split(const string &str, const char delemiter) {vector<string> res;stringstream ss(str);string buffer; while( getline(ss, buffer, delemiter) ) res.push_back(buffer); return res;}
int msb(int x) {return x?31-__builtin_clz(x):-1;}
void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;}
void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;}
void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;}
auto dp = multivector(200001,2,2,HIGHINF);
vector<ll> A(200001);
ll N,M;
ll rec(int idx,int trn,int res) {
    if(idx == N) return 0;
    if(dp[idx][trn][res] != HIGHINF) return dp[idx][trn][res];
    //最大化
    if(trn == 0 && res == 0) {
        dp[idx][trn][res] = -LOWINF;
        chmax(dp[idx][trn][res],rec(idx+1,trn^1,1)-M+1);
    }
    if(trn == 0 && res == 1) {
        dp[idx][trn][res] = -LOWINF;
        if(A[idx] > 1) {
            chmax(dp[idx][trn][res],rec(idx,trn^1,0)+A[idx]-1);
            chmax(dp[idx][trn][res],rec(idx+1,trn^1,1)+A[idx]-M);
        }
        else {
            chmax(dp[idx][trn][res],rec(idx,trn,0));
        }
    }
    //最小化
    if(trn == 1 && res == 0) {
        dp[idx][trn][res] = LOWINF;
        chmin(dp[idx][trn][res],rec(idx+1,trn^1,1)+M-1);
    }
    if(trn == 1 && res == 1) {
        dp[idx][trn][res] = LOWINF;
        if(A[idx] > 1) {
            chmin(dp[idx][trn][res],rec(idx,trn^1,0)-(A[idx]-1));
            chmin(dp[idx][trn][res],rec(idx+1,trn^1,1)-(A[idx]+M));
        }
        else {
            chmin(dp[idx][trn][res],rec(idx,trn,0));
        }
    }
    return dp[idx][trn][res];
}
int main() {
    cin.tie(0);ios::sync_with_stdio(false);
    cin >> N >> M;
    for(int i = 0; i < N; ++i) cin >> A[i];
    ll cnt = rec(0,0,1);
    cout << (cnt>0?"First":"Second") << endl;
    return 0;
}
            
            
            
        