結果

問題 No.1206 OR, OR, OR......
ユーザー uchiiii
提出日時 2020-08-30 16:30:38
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 41 ms / 2,000 ms
コード長 4,706 bytes
コンパイル時間 11,980 ms
コンパイル使用メモリ 279,468 KB
最終ジャッジ日時 2025-01-14 00:00:16
ジャッジサーバーID
(参考情報)
judge5 / judge1
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ファイルパターン 結果
sample AC * 1
other AC * 8
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ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("03")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std; typedef long double ld; typedef long long ll;
typedef unsigned long long ull;
#define endl "\n"
#define FOR(i,a,b) for(int i=(a);i<=(b);i++)
#define rep(i,n) for(int i=0;i<(n);i++)
#define PII pair<int, int>
#define PLL pair<ll, ll>
#define ALL(x) (x).begin(), (x).end()
constexpr int INF=1<<30; constexpr ll LINF=1LL<<60; constexpr ll mod=998244353; constexpr int NIL = -1;
template<class T>vector<T> vec(int len, T elem) { return vector<T>(len, elem); } // auto dp = vec(52, vec(103, vec(103, INF)));
template<class T>inline bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>inline bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
template<class T>inline int popcount(T a) {return __builtin_popcount(a);}
template<class T>inline T emod(T a, T p) { return (a%p + p) % p;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {os << '\n'; for (auto v : vec) os << v << ' '; os << '\n'; return os;}
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os;
    }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return
    os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os;
    }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}';
    return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')';
    return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v
    .second << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first <<
    "=>" << v.second << ','; os << '}'; return os; }
//----------------
struct mint {
ll x;
mint(ll x=0):x(x%mod){}
bool operator==(const mint a)const{return x==a.x;}
bool operator!=(const mint a)const{return x!=a.x;}
bool operator>=(const mint a){return (x >= a.x)? 1: 0;}
bool operator<(const mint a){return !(*this>=a);}
bool operator>(const mint a){return (x > a.x)? 1:0;}
bool operator<=(const mint a){return !(*this>a);}
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) {
(x *= a.x) %= mod;
return *this;
}
mint& operator/=(const mint a) {
return (*this) *= a.inv();
}
mint operator+(const mint a) const {
mint res(*this);
return res+=a;
}
mint operator-(const mint a) const {
mint res(*this);
return res-=a;
}
mint operator*(const mint a) const {
mint res(*this);
return res*=a;
}
mint operator/(const mint a) const {
mint res(*this);
return res/=a;
}
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t>>1);
a *= a; //2 square
if (t&1) a *= *this;
return a;
}
// for prime mod
mint inv() const {
return pow(mod-2);
}
friend ostream& operator<<(ostream& os, const mint& m){
os << m.x;
return os;
}
};
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
return fact[n]*ifact[k]*ifact[n-k];
}
} comb(100005);
mint f(int n, int k) {
if (n < 0) return 0;
// nPk = nCk * k!
mint res = comb(n,k);
res *= comb.fact[k];
return res;
}
void solve() {
int n,k; cin >> n >> k;
mint all = mint(2).pow(n).pow(k);
mint nt = mint(2).pow(n-1).pow(k);
mint ans = (all-nt) * n;
cout << ans << endl;
}
int main() {
cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(15);
int t; cin >> t;
while(t--) solve();
return 0;
}
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