結果

問題 No.1226 I hate Robot Arms
ユーザー 沙耶花沙耶花
提出日時 2020-09-11 22:41:50
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,027 ms / 2,000 ms
コード長 4,694 bytes
コンパイル時間 2,025 ms
コンパイル使用メモリ 198,332 KB
最終ジャッジ日時 2025-01-14 11:02:42
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <stdio.h>
#include <algorithm>
#ifdef _MSC_VER
#include <intrin.h>
#endif
namespace atcoder {
namespace internal {
// @param n `0 <= n`
// @return minimum non-negative `x` s.t. `n <= 2**x`
int ceil_pow2(int n) {
int x = 0;
while ((1U << x) < (unsigned int)(n)) x++;
return x;
}
// @param n `1 <= n`
// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`
int bsf(unsigned int n) {
#ifdef _MSC_VER
unsigned long index;
_BitScanForward(&index, n);
return index;
#else
return __builtin_ctz(n);
#endif
}
} // namespace internal
} // namespace atcoder
#include <cassert>
#include <vector>
namespace atcoder {
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
public:
segtree() : segtree(0) {}
segtree(int n) : segtree(std::vector<S>(n, e())) {}
segtree(const std::vector<S>& v) : _n(int(v.size())) {
log = internal::ceil_pow2(_n);
size = 1 << log;
d = std::vector<S>(2 * size, e());
for (int i = 0; i < _n; i++) d[size + i] = v[i];
for (int i = size - 1; i >= 1; i--) {
update(i);
}
}
void set(int p, S x) {
assert(0 <= p && p < _n);
p += size;
d[p] = x;
for (int i = 1; i <= log; i++) update(p >> i);
}
S get(int p) {
assert(0 <= p && p < _n);
return d[p + size];
}
S prod(int l, int r) {
assert(0 <= l && l <= r && r <= _n);
S sml = e(), smr = e();
l += size;
r += size;
while (l < r) {
if (l & 1) sml = op(sml, d[l++]);
if (r & 1) smr = op(d[--r], smr);
l >>= 1;
r >>= 1;
}
return op(sml, smr);
}
S all_prod() { return d[1]; }
template <bool (*f)(S)> int max_right(int l) {
return max_right(l, [](S x) { return f(x); });
}
template <class F> int max_right(int l, F f) {
assert(0 <= l && l <= _n);
assert(f(e()));
if (l == _n) return _n;
l += size;
S sm = e();
do {
while (l % 2 == 0) l >>= 1;
if (!f(op(sm, d[l]))) {
while (l < size) {
l = (2 * l);
if (f(op(sm, d[l]))) {
sm = op(sm, d[l]);
l++;
}
}
return l - size;
}
sm = op(sm, d[l]);
l++;
} while ((l & -l) != l);
return _n;
}
template <bool (*f)(S)> int min_left(int r) {
return min_left(r, [](S x) { return f(x); });
}
template <class F> int min_left(int r, F f) {
assert(0 <= r && r <= _n);
assert(f(e()));
if (r == 0) return 0;
r += size;
S sm = e();
do {
r--;
while (r > 1 && (r % 2)) r >>= 1;
if (!f(op(d[r], sm))) {
while (r < size) {
r = (2 * r + 1);
if (f(op(d[r], sm))) {
sm = op(d[r], sm);
r--;
}
}
return r + 1 - size;
}
sm = op(d[r], sm);
} while ((r & -r) != r);
return 0;
}
private:
int _n, size, log;
std::vector<S> d;
void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
} // namespace atcoder
#include <bits/stdc++.h>
using namespace std;
using namespace atcoder;
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define modulo 1000000007
#define mod(mod_x) ((((long long)mod_x+modulo))%modulo)
#define Inf 10000000000000
long double eps = 1e-9;
struct Data{
long double r=0.0,theta=0.0;
long double stheta = 0.0;
};
Data op(Data a,Data b){
long double x = a.r * cos(a.theta) + b.r * cos(b.theta+a.stheta);
long double y = a.r * sin(a.theta) + b.r * sin(b.theta+a.stheta);
Data ret;
ret.r = hypot(x,y);
ret.theta = atan2(y,x);
ret.stheta = a.stheta + b.stheta;
return ret;
}
Data e(){
return Data();
}
int main(){
int N,Q;
cin>>N>>Q;
Data temp = {1.0,0.0};
vector<Data> T(N+1,temp);
T[0].r = 0.0;
segtree<Data,op,e> seg(T);
rep(_,Q){
int t;
cin>>t;
if(t==0){
int i,x;
cin>>i>>x;
Data D = seg.get(i);
D.theta = (acos(-1.0)/180.0)*(long double)x;
D.stheta = D.theta;
seg.set(i,D);
}
else if(t==1){
int i,x;
cin>>i>>x;
Data D = seg.get(i);
D.r = (long double)x;
seg.set(i,D);
}
else{
int i;
cin>>i;
Data D = seg.prod(0,i+1);
long double x = D.r * cos(D.theta);
long double y = D.r * sin(D.theta);
cout<<fixed<<setprecision(10)<<x<<' '<<y<<endl;
}
}
return 0;
}
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