結果
問題 | No.1253 雀見椪 |
ユーザー | iiljj |
提出日時 | 2020-10-09 22:25:12 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 50 ms / 2,000 ms |
コード長 | 9,402 bytes |
コンパイル時間 | 2,244 ms |
コンパイル使用メモリ | 204,360 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-20 12:33:01 |
合計ジャッジ時間 | 3,438 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 3 ms
6,940 KB |
testcase_03 | AC | 5 ms
6,944 KB |
testcase_04 | AC | 50 ms
6,944 KB |
testcase_05 | AC | 50 ms
6,944 KB |
testcase_06 | AC | 49 ms
6,944 KB |
testcase_07 | AC | 50 ms
6,940 KB |
testcase_08 | AC | 50 ms
6,940 KB |
testcase_09 | AC | 50 ms
6,944 KB |
testcase_10 | AC | 50 ms
6,944 KB |
testcase_11 | AC | 50 ms
6,940 KB |
testcase_12 | AC | 50 ms
6,944 KB |
testcase_13 | AC | 50 ms
6,944 KB |
testcase_14 | AC | 2 ms
6,940 KB |
ソースコード
/* #region Head */ // #define _GLIBCXX_DEBUG #include <bits/stdc++.h> using namespace std; using ll = long long; using ull = unsigned long long; using ld = long double; using pll = pair<ll, ll>; template <class T> using vc = vector<T>; template <class T> using vvc = vc<vc<T>>; using vll = vc<ll>; using vvll = vvc<ll>; using vld = vc<ld>; using vvld = vvc<ld>; using vs = vc<string>; using vvs = vvc<string>; template <class T, class U> using um = unordered_map<T, U>; template <class T> using pq = priority_queue<T>; template <class T> using pqa = priority_queue<T, vc<T>, greater<T>>; template <class T> using us = unordered_set<T>; #define REP(i, m, n) for (ll i = (m), i##_len = (ll)(n); i < i##_len; ++(i)) #define REPM(i, m, n) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; ++(i)) #define REPR(i, m, n) for (ll i = (m), i##_min = (ll)(n); i >= i##_min; --(i)) #define REPD(i, m, n, d) for (ll i = (m), i##_len = (ll)(n); i < i##_len; i += (d)) #define REPMD(i, m, n, d) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; i += (d)) #define REPI(itr, ds) for (auto itr = ds.begin(); itr != ds.end(); itr++) #define ALL(x) begin(x), end(x) #define SIZE(x) ((ll)(x).size()) #define PERM(c) \ sort(ALL(c)); \ for (bool c##p = 1; c##p; c##p = next_permutation(ALL(c))) #define UNIQ(v) v.erase(unique(ALL(v)), v.end()); #define endl '\n' #define sqrt sqrtl #define floor floorl #define log2 log2l constexpr ll INF = 1'010'000'000'000'000'017LL; constexpr int IINF = 1'000'000'007LL; constexpr ll MOD = 1'000'000'007LL; // 1e9 + 7 // constexpr ll MOD = 998244353; constexpr ld EPS = 1e-12; constexpr ld PI = 3.14159265358979323846; template <typename T> istream &operator>>(istream &is, vc<T> &vec) { // vector 入力 for (T &x : vec) is >> x; return is; } template <typename T> ostream &operator<<(ostream &os, vc<T> &vec) { // vector 出力 (for dump) os << "{"; REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "" : ", "); os << "}"; return os; } template <typename T> ostream &operator>>(ostream &os, vc<T> &vec) { // vector 出力 (inline) REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "\n" : " "); return os; } template <typename T, typename U> istream &operator>>(istream &is, pair<T, U> &pair_var) { // pair 入力 is >> pair_var.first >> pair_var.second; return is; } template <typename T, typename U> ostream &operator<<(ostream &os, pair<T, U> &pair_var) { // pair 出力 os << "(" << pair_var.first << ", " << pair_var.second << ")"; return os; } // map, um, set, us 出力 template <class T> ostream &out_iter(ostream &os, T &map_var) { os << "{"; REPI(itr, map_var) { os << *itr; auto itrcp = itr; if (++itrcp != map_var.end()) os << ", "; } return os << "}"; } template <typename T, typename U> ostream &operator<<(ostream &os, map<T, U> &map_var) { return out_iter(os, map_var); } template <typename T, typename U> ostream &operator<<(ostream &os, um<T, U> &map_var) { os << "{"; REPI(itr, map_var) { auto [key, value] = *itr; os << "(" << key << ", " << value << ")"; auto itrcp = itr; if (++itrcp != map_var.end()) os << ", "; } os << "}"; return os; } template <typename T> ostream &operator<<(ostream &os, set<T> &set_var) { return out_iter(os, set_var); } template <typename T> ostream &operator<<(ostream &os, us<T> &set_var) { return out_iter(os, set_var); } template <typename T> ostream &operator<<(ostream &os, pq<T> &pq_var) { pq<T> pq_cp(pq_var); os << "{"; if (!pq_cp.empty()) { os << pq_cp.top(), pq_cp.pop(); while (!pq_cp.empty()) os << ", " << pq_cp.top(), pq_cp.pop(); } return os << "}"; } // dump #define DUMPOUT cerr void dump_func() { DUMPOUT << endl; } template <class Head, class... Tail> void dump_func(Head &&head, Tail &&... tail) { DUMPOUT << head; if (sizeof...(Tail) > 0) DUMPOUT << ", "; dump_func(move(tail)...); } // chmax (更新「される」かもしれない値が前) template <typename T, typename U, typename Comp = less<>> bool chmax(T &xmax, const U &x, Comp comp = {}) { if (comp(xmax, x)) { xmax = x; return true; } return false; } // chmin (更新「される」かもしれない値が前) template <typename T, typename U, typename Comp = less<>> bool chmin(T &xmin, const U &x, Comp comp = {}) { if (comp(x, xmin)) { xmin = x; return true; } return false; } // ローカル用 #define DEBUG_ #ifdef DEBUG_ #define DEB #define dump(...) \ DUMPOUT << " " << string(#__VA_ARGS__) << ": " \ << "[" << to_string(__LINE__) << ":" << __FUNCTION__ << "]" << endl \ << " ", \ dump_func(__VA_ARGS__) #else #define DEB if (false) #define dump(...) #endif #define VAR(type, ...) \ type __VA_ARGS__; \ cin >> __VA_ARGS__; template <typename T> istream &operator,(istream &is, T &rhs) { return is >> rhs; } template <typename T> ostream &operator,(ostream &os, const T &rhs) { return os << ' ' << rhs; } struct AtCoderInitialize { static constexpr int IOS_PREC = 15; static constexpr bool AUTOFLUSH = false; AtCoderInitialize() { ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr); cout << fixed << setprecision(IOS_PREC); if (AUTOFLUSH) cout << unitbuf; } } ATCODER_INITIALIZE; void Yn(bool p) { cout << (p ? "Yes" : "No") << endl; } void YN(bool p) { cout << (p ? "YES" : "NO") << endl; } /* #endregion */ // #include <atcoder/all> // using namespace atcoder; /* #region mint */ // 自動で MOD を取る整数 struct mint { ll x; mint(ll x = 0) : x((x % MOD + MOD) % MOD) {} mint &operator+=(const mint a) { if ((x += a.x) >= MOD) x -= MOD; return *this; } mint &operator-=(const mint a) { if ((x += MOD - a.x) >= MOD) x -= MOD; return *this; } mint &operator*=(const mint a) { (x *= a.x) %= MOD; return *this; } mint operator+(const mint a) const { mint res(*this); return res += a; } mint operator-(const mint a) const { mint res(*this); return res -= a; } mint operator*(const mint a) const { mint res(*this); return res *= a; } // O(log(t)) mint pow_rec(ll t) const { if (!t) return 1; mint a = pow(t >> 1); // ⌊t/2⌋ 乗 a *= a; // ⌊t/2⌋*2 乗 if (t & 1) // ⌊t/2⌋*2 == t-1 のとき a *= *this; // ⌊t/2⌋*2+1 乗 => t 乗 return a; } mint pow(ll t) const { mint a(*this); mint res = 1; while (t) { if (t & 1) res *= a; t >>= 1, a *= a; } return res; } // for prime mod mint inv_prime() const { return pow(MOD - 2); // オイラーの定理から, x^(-1) ≡ x^(p-2) } mint inv() const { ll a = this->x, b = MOD, u = 1, v = 0, t; mint res; while (b) { t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } if (u < 0) u += MOD; res = u; return res; } mint &operator/=(const mint a) { return (*this) *= a.inv(); } mint operator/(const mint a) const { mint res(*this); return res /= a; } bool operator==(const mint a) const { return this->x == a.x; } bool operator==(const ll a) const { return this->x == a; } // mint 入力 friend istream &operator>>(istream &is, mint &x) { is >> x.x; return is; } // mint 出力 friend ostream &operator<<(ostream &os, mint x) { os << x.x; return os; } }; /* #endregion */ // Problem void solve() { VAR(ll, t); REP(i, 0, t) { VAR(ll, n, ag, bg, ac, bc, ap, bp); // // あいこ <->(全員同じ or 3種類揃う)<-> 1 - (2種類で構成) mint X0 = mint(ag) / bg; mint X1 = mint(ac) / bc; mint X2 = mint(ap) / bp; // sum nCk(n,k)*x^k*y^(n-k), k=0 to n == (x+y)^n // sum nCk(n,k)*x^k*y^(n-k), k=1 to (n-1) == (x+y)^n - (x^n + y^n) mint P01 = (X0 + X1).pow(n) - (X0.pow(n) + X1.pow(n)); mint P12 = (X1 + X2).pow(n) - (X1.pow(n) + X2.pow(n)); mint P20 = (X2 + X0).pow(n) - (X2.pow(n) + X0.pow(n)); mint P = P01 + P12 + P20; // mint ans = P - 1; mint ans = mint(1) - P; // dump(X0, X1, X2, P01, P12, P20, P, ans); cout << ans << endl; } } // entry point int main() { solve(); return 0; }