結果

問題 No.1179 Quadratic Equation
ユーザー soraie_
提出日時 2020-11-02 20:59:13
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 4,990 bytes
コンパイル時間 1,804 ms
コンパイル使用メモリ 176,856 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-07-22 08:02:09
合計ジャッジ時間 2,373 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 11
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
using namespace std;
/*--------------------------------------------------------------------*/
#define all(a) (a).begin(),(a).end()
#define rall(a) (a).rbegin(),(a).rend()
#define vecin(a) rep(i,a.size())cin >> a[i]
#define overload4(_1,_2,_3,_4,name,...) name
/*#define rep1(n) for(int i=0;i<(int)n;++i)
#define rep2(i,n) for(int i=0;i<(int)n;++i)
#define rep3(i,a,b) for(int i=(int)a;i<(int)b;++i)
#define rep4(i,a,b,c) for(int i=(int)a;i<(int)b;i+=(int)c)*/
#define rep1(n) for(ll i=0;i<(ll)n;++i)
#define rep2(i,n) for(ll i=0;i<(ll)n;++i)
#define rep3(i,a,b) for(ll i=(ll)a;i<(ll)b;++i)
#define rep4(i,a,b,c) for(ll i=(ll)a;i<(ll)b;i+=(ll)c)
#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)
#ifdef _DEBUG
#define debug1(a) cerr << #a << ": " << a << "\n"
#define debug2(a,b) cerr << #a << ": " << a << ", " << #b << ": " << b << "\n"
#define debug3(a,b,c) cerr << #a << ": " << a << ", " << #b << ": " << b << ", " << #c << ": " << c << "\n"
#define debug4(a,b,c,d) cerr << #a << ": " << a << ", " << #b << ": " << b << ", " << #c << ": " << c << ", " << #d << ": " << d << "\n"
#define debug(...) overload4(__VA_ARGS__,debug4,debug3,debug2,debug1)(__VA_ARGS__)
#define vecout(a) cerr << #a << ": [";rep(i,a.size()){cerr << a[i];cerr << (i == a.size() - 1 ? "":",");}cerr << "]\n"
#else
#define debug(...)
#define vecout(a)
#endif
#define mp make_pair
#define fi first
#define se second
//struct doset{doset(int n){cout << fixed << setprecision(n);cerr << fixed << setprecision(n);}};
//struct myset{myset(){ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);}};
void myset(){ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);}
void doset(int n){cout << fixed << setprecision(n);cerr << fixed << setprecision(n);}
void koko(){cerr << "koko\n";}
using ll = long long;
using ld = long double;
using dou = double;
const int inf = 1 << 30;
const ll INF = 1LL << 61;
const ld pi = 3.14159265358;
const ll mod1 = 1000000007LL;
const ll mod2 = 998244353LL;
typedef pair<ll,ll> P;
template<class T, class U> inline bool chmin(T& a, const U& b){ if(a > b){ a = b; return 1; } return 0; }
template<class T, class U> inline bool chmax(T& a, const U& b){ if(a < b){ a = b; return 1; } return 0; }
//nmMODO(logm)
ll modpow(ll n,ll m,ll MOD){
if(m == 0)return 1;
if(m < 0)return 0;
ll res = 1;
n %= MOD;
while(m){
if(m & 1)res = (res * n) % MOD;
m >>= 1;
n *= n;
n %= MOD;
}
return res;
}
ll mypow(ll n,ll m){
if(m == 0)return 1;
if(m < 0)return -1;
ll res = 1;
while(m){
if(m & 1)res = (res * n);
m >>= 1;
n *= n;
}
return res;
}
//O(sqrt(N))
template<class T>
inline bool isp(T n){
bool res = true;
if(n == 1 || n == 0)return false;
else{
for(ll i = 2;i * i <= n;i++){
if(n % i == 0){
res = false;
break;
}
}
return res;
}
}
inline bool Yes(bool b = 1){cout << (b ? "Yes\n":"No\n");return b;}
inline bool YES(bool b = 1){cout << (b ? "YES\n":"NO\n");return b;}
map<ll,ll> primefactor(ll n){
map<ll,ll> ma;
if(n <= 1)return ma;
ll m = n;
for(ll i = 2;i * i <= n;i++){
while(m % i == 0){
ma[i]++;
m /= i;
}
}
if(m != 1)ma[m]++;
return ma;
}
ll __lcm(ll a,ll b){
return a / __gcd(a,b) * b;
}
inline void in(){return;}
template<class First,class...Other>inline void in(First& F,Other&...O){cin >> F;in(O...);}
template<ll MOD = mod1>
struct fac_solver{
private:
ll cmax;
vector<ll> fac,finv,inv;
public:
fac_solver(ll n = 100000):cmax(n),fac(n),finv(n),inv(n){
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for (ll i = 2; i < cmax; i++){
fac[i] = fac[i - 1] * i % MOD;
inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
finv[i] = finv[i - 1] * inv[i] % MOD;
}
}
//nCk
ll COM(ll n, ll k){
if (n < k) return 0;
if (n < 0 || k < 0) return 0;
return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}
ll PER(ll n,ll k){
if(n < k || n < 0 || k < 0)return 0;
return fac[n] * finv[n - k] % MOD;
}
ll stair_pow(ll n){return fac[n];}
};
/*--------------------------------------------------------------------*/
int main(){
myset();
doset(10);
int A,B,C;
cin >> A >> B >> C;
if(A < 0){
A = -A;B = -B;C = -C;
}
int D = B * B - 4 * A * C;
if(D < 0){
cout << "imaginary\n";
}
else if(D == 0){
cout << ld(-B) / ld(2 * A) << "\n";
}
else{
cout << (ld(-B) - sqrtl(ld(D))) / ld(2 * A) << " " << (ld(-B) + sqrtl(ld(D))) / ld(2 * A) << "\n";
}
}
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