結果

問題 No.1283 Extra Fee
ユーザー fine
提出日時 2020-11-07 03:16:04
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 213 ms / 2,000 ms
コード長 2,382 bytes
コンパイル時間 2,108 ms
コンパイル使用メモリ 184,380 KB
実行使用メモリ 39,956 KB
最終ジャッジ日時 2024-11-16 06:58:44
合計ジャッジ時間 6,057 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
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ファイルパターン 結果
other AC * 30
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr char newl = '\n';
constexpr int dh[] = {1, -1, 0, 0};
constexpr int dw[] = {0, 0, 1, -1};
struct State {
int at;
ll cost;
bool used;
//int prev;
State(int at, ll cost, bool used) : at(at), cost(cost), used(used) {}
bool operator>(const State& s) const {
return cost > s.cost;
}
};
struct Edge {
int to;
ll cost;
Edge(int to, ll cost) : to(to), cost(cost) {}
};
using Graph = vector< vector<Edge> >; //
const ll INF = 1e15;
//const int NONE = -1;
//smincprevs
void dijkstra(int s, const Graph& graph, vector< vector<ll> >& minc){
minc.assign(2, vector<ll>(graph.size(), INF));
priority_queue<State, vector<State>, greater<State> > pq;
pq.emplace(s, 0, false);
minc[false][s] = 0;
while(!pq.empty()) {
State cur = pq.top();
pq.pop();
if (minc[cur.used][cur.at] < cur.cost) continue;
for(const Edge& e : graph[cur.at]) {
if (!cur.used) {
ll cost = cur.cost + 1;
if (minc[true][e.to] > cost) {
minc[true][e.to] = cost;
pq.emplace(e.to, cost, true);
}
}
ll cost = cur.cost + e.cost;
if (minc[cur.used][e.to] <= cost) continue;
minc[cur.used][e.to] = cost;
pq.emplace(e.to, cost, cur.used);
}
}
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int n, m;
cin >> n >> m;
vector< vector<ll> > memo(n, vector<ll>(n, 0));
for (int i = 0; i < m; i++) {
int h, w;
ll c;
cin >> h >> w >> c;
--h; --w;
memo[h][w] = c;
}
Graph g(n * n);
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
for (int k = 0; k < 4; k++) {
int nh = i + dh[k], nw = j + dw[k];
if (nh < 0 || nh >= n || nw < 0 || nw >= n) continue;
g[i * n + j].emplace_back(nh * n + nw, memo[nh][nw] + 1);
}
}
}
vector< vector<ll> > minc;
dijkstra(0, g, minc);
int goal = (n - 1) * n + (n - 1);
cout << min(minc[0][goal], minc[1][goal]) << newl;
return 0;
}
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