結果
| 問題 |
No.1149 色塗りゲーム
|
| コンテスト | |
| ユーザー |
Coki628
|
| 提出日時 | 2020-11-27 15:11:01 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 183 ms / 2,000 ms |
| コード長 | 2,216 bytes |
| コンパイル時間 | 921 ms |
| コンパイル使用メモリ | 82,504 KB |
| 実行使用メモリ | 71,512 KB |
| 平均クエリ数 | 19.88 |
| 最終ジャッジ日時 | 2024-07-17 07:34:30 |
| 合計ジャッジ時間 | 10,207 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 50 |
ソースコード
import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for k in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for k in range(c)] for k in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10**9)
INF = 10**19
MOD = 10**9 + 7
EPS = 10**-10
# N = INT()
# S = '0' * N
# memo = {}
# def rec(S):
# if S in memo:
# return memo[S]
# if not S.count('0'):
# memo[S] = 0
# return 0
# S = list(S)
# res = 1
# for i in range(N):
# if S[i] == '0':
# S[i] = '1'
# res &= rec(''.join(S))
# S[i] = '0'
# for i in range(N-1):
# if S[i] == S[i+1] == '0':
# S[i] = S[i+1] = '1'
# res &= rec(''.join(S))
# S[i] = S[i+1] = '0'
# S = ''.join(S)
# memo[S] = 1-res
# return 1-res
# res = rec(S)
# win = []
# for k, v in memo.items():
# # 負け状態を列挙して調べる
# if not v:
# win.append(k)
# win.reverse()
# for s in win:
# if s.count('1') <= 4:
# print(s.count('1'), s)
N = INT()
S = ['0'] * N
# 真ん中で区切る
if N % 2 == 0:
print('{0} {1}'.format(2, N//2), flush=1)
S[N//2-1] = S[N//2] = '1'
else:
print('{0} {1}'.format(1, ceil(N, 2)), flush=1)
S[ceil(N, 2)-1] = '1'
cur = ['0'] * (ceil(N, 2)-1)
dist = N//2 + 1
while 1:
t = INT()
if t == 0:
break
k, x = MAP()
x -= 1
for i in range(x, x+k):
S[x] = '1'
if N % 2 == 0:
L, R = S[:N//2-1], S[N//2+1:]
else:
L, R = S[:ceil(N, 2)-1], S[ceil(N, 2):]
# 左右反対側で同じことをする
if L != cur:
x += dist
cur = L
else:
x -= dist
cur = R
for i in range(x, x+k):
S[x] = '1'
x += 1
print('{0} {1}'.format(k, x), flush=1)
Coki628