結果
問題 | No.1300 Sum of Inversions |
ユーザー |
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提出日時 | 2020-11-27 22:31:13 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 190 ms / 2,000 ms |
コード長 | 3,667 bytes |
コンパイル時間 | 2,313 ms |
コンパイル使用メモリ | 188,104 KB |
実行使用メモリ | 32,992 KB |
最終ジャッジ日時 | 2024-07-26 18:49:36 |
合計ジャッジ時間 | 8,546 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 34 |
ソースコード
#pragma GCC optimize("O3")#include <bits/stdc++.h>#define ll long long#define rep(i,n) for(ll i=0;i<(n);i++)#define pll pair<ll,ll>#define pii pair<int,int>#define pq priority_queue#define pb push_back#define eb emplace_back#define fi first#define se second#define endl '\n'#define ios ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0);#define lb(c,x) distance(c.begin(),lower_bound(all(c),x))#define ub(c,x) distance(c.begin(),upper_bound(all(c),x))using namespace std;inline int topbit(unsigned long long x){return x?63-__builtin_clzll(x):-1;}inline int popcount(unsigned long long x){return __builtin_popcountll(x);}inline int parity(unsigned long long x){//popcount%2return __builtin_parity(x);}template<class T> inline bool chmax(T& a,T b){if(a<b){a=b;return 1;}return 0;}template<class T> inline bool chmin(T& a,T b){if(a>b){a=b;return 1;}return 0;}const ll INF=1e18;const ll mod = 998244353;struct mint {ll x; // typedef long long ll;mint(ll x=0):x((x%mod+mod)%mod){}mint operator-() const { return mint(-x);}mint& operator+=(const mint a) {if ((x += a.x) >= mod) x -= mod;return *this;}mint& operator-=(const mint a) {if ((x += mod-a.x) >= mod) x -= mod;return *this;}mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}mint operator+(const mint a) const { return mint(*this) += a;}mint operator-(const mint a) const { return mint(*this) -= a;}mint operator*(const mint a) const { return mint(*this) *= a;}mint pow(ll t) const {if (!t) return 1;mint a = pow(t>>1);a *= a;if (t&1) a *= *this;return a;}// for prime modmint inv() const { return pow(mod-2);}mint& operator/=(const mint a) { return *this *= a.inv();}mint operator/(const mint a) const { return mint(*this) /= a;}};istream& operator>>(istream& is, mint& a) { return is >> a.x;}ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}// combination mod prime// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619struct combination {vector<mint> fact, ifact;combination(ll n):fact(n+1),ifact(n+1) {assert(n < mod);fact[0] = 1;for (ll i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;ifact[n] = fact[n].inv();for (ll i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;}mint operator()(ll n, ll k) {if (k < 0 || k > n) return 0;return fact[n]*ifact[k]*ifact[n-k];}mint p(ll n, ll k) {return fact[n]*ifact[n-k];}} c(1000005);template<typename T>struct BIT {int n;vector<T> d;BIT(int n=0):n(n),d(n+1) {}void add(int i, T x=1) {for (i++; i <= n; i += i&-i) {//「i += i&-i」は区間を表すindexに最下位ビットを足したもの//「-i = ~i-1」が成り立つd[i] += x;}//更新}T sum(int i) {T x = 0;for (i++; i; i -= i&-i) {x += d[i];}//iが0になったら終わり//取得return x;}};int main(){ll n;cin >> n;vector<ll> a(n),p(n),q(n);vector<pll> b(n);BIT<mint> s(n+1),v(n+1);BIT<mint> t(n+1),u(n+1);rep(i,n){cin >> a[i];b[i].fi=a[i];b[i].se=i;}sort(b.begin(),b.end());mint ans=0;rep(i,n){mint cnt=s.sum(n)-s.sum(b[i].se);mint sum1=t.sum(n)-t.sum(b[i].se);mint sum2=u.sum(n)-u.sum(b[i].se);mint cnt2=v.sum(n)-v.sum(b[i].se);s.add(b[i].se,1);t.add(b[i].se,b[i].fi);u.add(b[i].se,sum1+cnt*b[i].fi);v.add(b[i].se,cnt);ans+=sum2+cnt2*b[i].fi;}cout << ans << endl;return 0;}