結果
| 問題 |
No.1304 あなたは基本が何か知っていますか?私は知っています.
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-12-02 10:25:39 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 3,663 bytes |
| コンパイル時間 | 991 ms |
| コンパイル使用メモリ | 107,276 KB |
| 実行使用メモリ | 7,844 KB |
| 最終ジャッジ日時 | 2025-06-22 02:55:17 |
| 合計ジャッジ時間 | 6,373 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 45 RE * 29 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:81:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
81 | scanf("%d %d %d %d", &n, &k, &x, &y);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
main.cpp:84:21: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
84 | int b; scanf("%d", &b);
| ~~~~~^~~~~~~~~~
ソースコード
#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <numeric>
#include <bitset>
#include <cmath>
static const int MOD = 998244353;
using ll = long long;
using u32 = unsigned;
using u64 = unsigned long long;
using namespace std;
template<class T> constexpr T INF = ::numeric_limits<T>::max() / 32 * 15 + 208;
template <u32 M>
struct modint {
u32 val;
public:
static modint raw(int v) { modint x; x.val = v; return x; }
modint() : val(0) {}
template <class T>
modint(T v) { ll x = (ll)(v%(ll)(M)); if (x < 0) x += M; val = u32(x); }
modint(bool v) { val = ((unsigned int)(v) % M); }
modint& operator++() { val++; if (val == M) val = 0; return *this; }
modint& operator--() { if (val == 0) val = M; val--; return *this; }
modint operator++(int) { modint result = *this; ++*this; return result; }
modint operator--(int) { modint result = *this; --*this; return result; }
modint& operator+=(const modint& b) { val += b.val; if (val >= M) val -= M; return *this; }
modint& operator-=(const modint& b) { val -= b.val; if (val >= M) val += M; return *this; }
modint& operator*=(const modint& b) { u64 z = val; z *= b.val; val = (u32)(z % M); return *this; }
modint& operator/=(const modint& b) { return *this = *this * b.inv(); }
modint operator+() const { return *this; }
modint operator-() const { return modint() - *this; }
modint pow(long long n) const { modint x = *this, r = 1; while (n) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; }
modint inv() const { return pow(M-2); }
friend modint operator+(const modint& a, const modint& b) { return modint(a) += b; }
friend modint operator-(const modint& a, const modint& b) { return modint(a) -= b; }
friend modint operator*(const modint& a, const modint& b) { return modint(a) *= b; }
friend modint operator/(const modint& a, const modint& b) { return modint(a) /= b; }
friend bool operator==(const modint& a, const modint& b) { return a.val == b.val; }
friend bool operator!=(const modint& a, const modint& b) { return a.val != b.val; }
};
using mint = modint<MOD>;
template<class T>
void fwht(vector<T> &v){
int sz = 1;
while(sz < v.size()) sz <<= 1;
v.resize(sz);
for (int i = 1; i < sz; i <<= 1) {
for (int j = 0; j < sz; j += (i<<1)) {
for (int k = 0; k < i; ++k) {
T x = v[j+k], y = v[j+k+i];
v[j+k] = (x+y), v[j+k+i] = (x-y);
}
}
}
}
template<class T>
void ifwht(vector<T> &v){
int sz = 1;
while(sz < v.size()) sz <<= 1;
v.resize(sz);
for (int i = 1; i < sz; i <<= 1) {
for (int j = 0; j < sz; j += (i<<1)) {
for (int k = 0; k < i; ++k) {
T x = v[j+k], y = v[j+k+i];
v[j+k] = (x+y)*499122177, v[j+k+i] = (x-y)*499122177;
}
}
}
}
int main() {
int n, k, x, y;
scanf("%d %d %d %d", &n, &k, &x, &y);
vector<mint> a(1024);
for (int i = 0; i < k; ++i) {
int b; scanf("%d", &b);
a[b] = 1;
}
fwht(a);
vector<vector<mint>> dp(n+1, vector<mint>(1024));
dp[0][0] = 1;
fwht(dp[0]);
for (int i = 1; i <= n; ++i) {
dp[i] = dp[i-1];
for (int j = 0; j < 1024; ++j) dp[i][j] *= a[j];
if(i >= 2) for (int j = 0; j < 1024; ++j) dp[i][j] -= dp[i-2][j]*k;
if(i >= 3) for (int j = 0; j < 1024; ++j) dp[i][j] += dp[i-2][j];
}
ifwht(dp.back());
mint ans = 0;
for (int i = x; i <= min(y, 1023); ++i) {
ans += dp.back()[i];
}
printf("%d\n", ans.val);
return 0;
}