結果

問題 No.1312 Snake Eyes
ユーザー ningenMe
提出日時 2020-12-09 04:04:55
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 284 ms / 2,000 ms
コード長 3,716 bytes
コンパイル時間 2,724 ms
コンパイル使用メモリ 206,448 KB
最終ジャッジ日時 2025-01-16 20:34:06
ジャッジサーバーID
（参考情報） 		judge2 / judge5
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ファイルパターン 結果
sample AC * 3
other AC * 85
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define ALL(obj) (obj).begin(),(obj).end()
template<class T> using priority_queue_reverse = priority_queue<T,vector<T>,greater<T>>;
constexpr long long MOD = 1'000'000'000LL + 7; //'
constexpr long long MOD2 = 998244353;
constexpr long long HIGHINF = (long long)1e18;
constexpr long long LOWINF = (long long)1e15;
constexpr long double PI = 3.1415926535897932384626433L;
template <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}
template <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}
template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}
template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x
    .second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj
    .begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != 
    obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << 
    obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}
template <class T> void chmax(T& a, const T b){a=max(a,b);}
template <class T> void chmin(T& a, const T b){a=min(a,b);}
vector<string> split(const string &str, const char delemiter) {vector<string> res;stringstream ss(str);string buffer; while( getline(ss, buffer, 
    delemiter) ) res.push_back(buffer); return res;}
int msb(int x) {return x?31-__builtin_clz(x):-1;}
void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;}
void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;}
void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;}
/*
 * @title NBase - N進数
 * @docs md/util/NBase.md
 */
class NBase{
public:
    inline static vector<long long> translate(long long X,long long N) {
        assert(abs(N)>1);
        vector<long long> res;
        while(1) {
            long long b = (X%abs(N)+abs(N)) % abs(N);
            res.push_back(b);
            (X -= b) /= N;
            if(X==0) break;
        }
        return res;
    }
    //Digit Sum
    inline static constexpr long long digit_sum(long long N, long long K) {
        long long sum = 0;
        for (; N > 0; N /= K) sum += N % K;
        return sum;
    }
};
//divisor O(sqrt(N))
set<long long> Divisor(long long N) {
    set<long long> ret;
    for (long long i = 1; i*i <= N; ++i) {
        if (N%i == 0) {
            ret.insert(i);
            ret.insert(N / i);
        }
    }
    return ret;
}
//verify https://atcoder.jp/contests/abc112/tasks/abc112_d
/**
 * @url 
 * @est
 */ 
int main() {
    cin.tie(0);ios::sync_with_stdio(false);
    ll N; cin >> N;
    corner(N==1,2);
    ll ans = N+1;
    for(ll p=2;p*p<=N;++p) {
        auto v = NBase::translate(N,p);
        int flg=1;
        for(int i=0;i+1<v.size();++i)if(v[i]!=v[i+1])flg=0;
        if(flg) chmin(ans,p);
    }
    auto D = Divisor(N);
    for(ll k:D) {
        ll p = N/k-1;
        if(p>=2 && p>(N/p)) chmin(ans,p);
    }
    cout << ans << endl;
    return 0;
}
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