結果
問題 | No.144 エラトステネスのざる |
ユーザー |
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提出日時 | 2020-12-10 21:55:53 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 484 ms / 2,000 ms |
コード長 | 3,435 bytes |
コンパイル時間 | 1,614 ms |
コンパイル使用メモリ | 176,436 KB |
実行使用メモリ | 13,500 KB |
最終ジャッジ日時 | 2024-09-19 20:44:19 |
合計ジャッジ時間 | 5,695 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 17 |
ソースコード
#include <bits/stdc++.h>using namespace std;// #define int long long#define rep(i, n) for (long long i = (long long)(0); i < (long long)(n); ++i)#define reps(i, n) for (long long i = (long long)(1); i <= (long long)(n); ++i)#define rrep(i, n) for (long long i = ((long long)(n)-1); i >= 0; i--)#define rreps(i, n) for (long long i = ((long long)(n)); i > 0; i--)#define irep(i, m, n) for (long long i = (long long)(m); i < (long long)(n); ++i)#define ireps(i, m, n) for (long long i = (long long)(m); i <= (long long)(n); ++i)#define irreps(i, m, n) for (long long i = ((long long)(n)-1); i > (long long)(m); ++i)#define SORT(v, n) sort(v, v + n);#define REVERSE(v, n) reverse(v, v+n);#define vsort(v) sort(v.begin(), v.end());#define all(v) v.begin(), v.end()#define mp(n, m) make_pair(n, m);#define cinline(n) getline(cin,n);#define replace_all(s, b, a) replace(s.begin(),s.end(), b, a);#define PI (acos(-1))#define FILL(v, n, x) fill(v, v + n, x);#define sz(x) (long long)(x.size())using ll = long long;using vi = vector<int>;using vvi = vector<vi>;using vll = vector<ll>;using vvll = vector<vll>;using pii = pair<int, int>;using pll = pair<ll, ll>;using vs = vector<string>;using vpll = vector<pair<ll, ll>>;using vtp = vector<tuple<ll,ll,ll>>;using vb = vector<bool>;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }template<class t> using vc=vector<t>;template<class t> using vvc=vc<vc<t>>;const ll INF = 1e9+10;const ll MOD = 1e9+7;const ll LINF = 1e18;const ll maxn_eratosthenes = 1000005;bool _is_prime[maxn_eratosthenes];vector<ll> P;vector<ll> min_prime_can_divide_i;void eratosthenes(const ll N){P.clear();min_prime_can_divide_i = vll(maxn_eratosthenes+1, 1);for (ll i = 0; i <= N; i++) {_is_prime[i] = true;}_is_prime[0]=_is_prime[1]=false;for (ll i = 2; i <= N; i++) {if (_is_prime[i]) {for (ll j = 2 * i; j <= N; j += i) {_is_prime[j] = false;if(min_prime_can_divide_i[j]==1) min_prime_can_divide_i[j] = i;}P.emplace_back(i);min_prime_can_divide_i[i] = i;}}}signed main(){cin.tie( 0 ); ios::sync_with_stdio( false );ll n; double p; cin>>n>>p;eratosthenes(maxn_eratosthenes-1);ll two[21];two[0]=1;rep(i,20) two[i+1]=two[i]*2;// min_prime_can_divide_i:=その数xを割ることができる最小の素数// min_prime_can_divide_iの素数の個数をmapで記録しつつ、now/min_prime_can_divide_i[now]へ遷移// 約数の数は素因数から求めるなら、例えば20=2^2*5^1 ... (2+1)*(1+1)=6 .. +1はその数を使わない通り数// この通り数から自身の数と1を除外するために-2する// 各i1個ずつをそれぞれ独立に見れば、sum(そのiが残る確率*1) = 全iを通して残る個数の期待値double ans=0;irep(i,2,n+1){ll now=i;map<ll,ll> m;while(min_prime_can_divide_i[now]!=1){m[min_prime_can_divide_i[now]]++;now/=min_prime_can_divide_i[now];}ll cnt=1;for(auto e: m){cnt*=e.second+1;}cnt-=2;ans+=powl((1-p), cnt);// cout<<cnt<<' ';}// cout<<endl;// irep(i,2,n+1){// cout<<min_prime_can_divide_i[i]<<' ';// }// cout<<endl;printf("%.15lf\n", ans);}