結果
問題 | No.197 手品 |
ユーザー |
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提出日時 | 2015-11-25 00:15:04 |
言語 | C++11 (gcc 13.3.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,732 bytes |
コンパイル時間 | 596 ms |
コンパイル使用メモリ | 83,076 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-27 13:11:25 |
合計ジャッジ時間 | 1,796 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 41 WA * 2 |
ソースコード
// Standard I/O #include <iostream> #include <sstream> #include <cstdio> // Standard Library #include <cstdlib> #include <cstring> #include <ctime> #include <cmath> // Template Class #include <complex> #include <string> #include <vector> #include <list> #include <set> #include <map> #include <queue> #include <stack> // Container Control #include <algorithm> using namespace std; #define rep( i, n ) for( int i = 0; i < n; ++i ) #define irep( i, n ) for( int i = n-1; i >= 0; --i ) #define reep( i, s, n ) for ( int i = s; i < n; ++i ) #define ireep( i, n, s ) for ( int i = n-1; i >= s; --i ) #define foreach(itr, x) for( typeof(x.begin()) itr = x.begin(); itr != x.end(); ++itr) #define mp( a, b ) make_pair( a, b ) #define pb( a ) push_back( a ) #define all( v ) v.begin(), v.end() #define fs first #define sc second #define vc vector // for visualizer.html double SCALE = 1.0; double OFFSET_X = 0.0; double OFFSET_Y = 0.0; #define LINE(x,y,a,b) cerr << "line(" << SCALE*(x) + OFFSET_X << "," \ << SCALE*(y) + OFFSET_Y << "," \ << SCALE*(a) + OFFSET_X << "," \ << SCALE*(b) + OFFSET_Y << ")" << endl; #define CIRCLE(x,y,r) cerr << "circle(" << SCALE*(x) + OFFSET_X << "," \ << SCALE*(y) + OFFSET_Y << "," \ << SCALE*(r) << ")" << endl; typedef long long ll; typedef complex<double> Point; typedef pair<int, int> pii; typedef pair<int, pii> ipii; typedef vector<int> vi; typedef vector<double> vd; typedef vector< vector<int> > vii; typedef vector< vector<double> > vdd; typedef vector<int>::iterator vi_itr; const int IINF = 1 << 28; const double INF = 1e30; const double EPS = 1e-10; const double PI = acos(-1.0); // Direction : L U R D const int dx[] = { -1, 0, 1, 0}; const int dy[] = { 0, -1, 0, 1 }; int main() { ll N; string S[2]; cin >> S[0] >> N >> S[1]; int num[2][2] = { 0 }; rep(i, 2) rep(j, 3){ num[i][(S[i][j] == 'o')]++; } if( num[0][0] != num[1][0] || num[0][1] != num[1][1] ){ cout << "SUCCESS" << endl; return 0; } bool isdone = false; // abc if( S[0] == S[1] && N%2 == 0 ){ isdone |= true; } // acb if( (S[0][0] == S[1][0] && S[0][1] == S[0][2] && S[0][2] == S[1][1]) && (N-1)%2 == 0 ){ isdone |= true; } // bac if( (S[0][0] == S[1][1] && S[0][1] == S[1][0] && S[0][2] == S[1][2]) && (N-1)%2 == 0 ){ isdone |= true; } // bca if( (S[0][0] == S[1][2] && S[0][1] == S[1][0] && S[0][2] == S[1][1]) && N%2 == 0 ){ isdone |= true; } // cab if( (S[0][0] == S[1][1] && S[0][1] == S[1][2] && S[0][2] == S[1][0]) && N%2 == 0 ){ isdone |= true; } // cba if( (S[0][0] == S[1][2] && S[0][1] == S[1][1] && S[0][2] == S[1][0]) && N >= 3 && (N-3)%2 == 0 ){ isdone |= true; } cout << (isdone ? "FAILURE" : "SUCCESS") << endl; }