結果

問題 No.1339 循環小数
ユーザー rniyarniya
提出日時 2021-01-15 21:52:53
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 28 ms / 2,000 ms
コード長 4,439 bytes
コンパイル時間 2,716 ms
コンパイル使用メモリ 195,072 KB
最終ジャッジ日時 2025-01-17 19:13:49
ジャッジサーバーID
(参考情報)
judge2 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
const long long MOD=1000000007;
// const long long MOD=998244353;
#define LOCAL
#pragma region Macros
typedef long long ll;
typedef __int128_t i128;
typedef unsigned int uint;
typedef unsigned long long ull;
#define ALL(x) (x).begin(),(x).end()
const int INF=1e9;
const long long IINF=1e18;
const int dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};
const char dir[4]={'D','R','U','L'};

template<typename T>
istream &operator>>(istream &is,vector<T> &v){
    for (T &x:v) is >> x;
    return is;
}
template<typename T>
ostream &operator<<(ostream &os,const vector<T> &v){
    for (int i=0;i<v.size();++i){
        os << v[i] << (i+1==v.size()?"": " ");
    }
    return os;
}
template<typename T,typename U>
ostream &operator<<(ostream &os,const pair<T,U> &p){
    os << '(' << p.first << ',' << p.second << ')';
    return os;
}
template<typename T,typename U,typename V>
ostream&operator<<(ostream &os,const tuple<T,U,V> &t){
    os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ')';
    return os;
}
template<typename T,typename U,typename V,typename W>
ostream&operator<<(ostream &os,const tuple<T,U,V,W> &t){
    os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ',' << get<3>(t) << ')';
    return os;
}
template<typename T,typename U>
ostream &operator<<(ostream &os,const map<T,U> &m){
    os << '{';
    for (auto itr=m.begin();itr!=m.end();){
        os << '(' << itr->first << ',' << itr->second << ')';
        if (++itr!=m.end()) os << ',';
    }
    os << '}';
    return os;
}
template<typename T,typename U>
ostream &operator<<(ostream &os,const unordered_map<T,U> &m){
    os << '{';
    for (auto itr=m.begin();itr!=m.end();){
        os << '(' << itr->first << ',' << itr->second << ')';
        if (++itr!=m.end()) os << ',';
    }
    os << '}';
    return os;
}
template<typename T>
ostream &operator<<(ostream &os,const set<T> &s){
    os << '{';
    for (auto itr=s.begin();itr!=s.end();){
        os << *itr;
        if (++itr!=s.end()) os << ',';
    }
    os << '}';
    return os;
}
template<typename T>
ostream &operator<<(ostream &os,const multiset<T> &s){
    os << '{';
    for (auto itr=s.begin();itr!=s.end();){
        os << *itr;
        if (++itr!=s.end()) os << ',';
    }
    os << '}';
    return os;
}
template<typename T>
ostream &operator<<(ostream &os,const unordered_set<T> &s){
    os << '{';
    for (auto itr=s.begin();itr!=s.end();){
        os << *itr;
        if (++itr!=s.end()) os << ',';
    }
    os << '}';
    return os;
}
template<typename T>
ostream &operator<<(ostream &os,const deque<T> &v){
    for (int i=0;i<v.size();++i){
        os << v[i] << (i+1==v.size()?"": " ");
    }
    return os;
}

void debug_out(){cerr << '\n';}
template<class Head,class... Tail>
void debug_out(Head&& head,Tail&&... tail){
    cerr << head;
    if (sizeof...(Tail)>0) cerr << ", ";
    debug_out(move(tail)...);
}
#ifdef LOCAL
#define debug(...) cerr << " ";\
cerr << #__VA_ARGS__ << " :[" << __LINE__ << ":" << __FUNCTION__ << "]" << '\n';\
cerr << " ";\
debug_out(__VA_ARGS__)
#else
#define debug(...) 42
#endif

template<typename T> T gcd(T x,T y){return y!=0?gcd(y,x%y):x;}
template<typename T> T lcm(T x,T y){return x/gcd(x,y)*y;}

template<class T1,class T2> inline bool chmin(T1 &a,T2 b){
    if (a>b){a=b; return true;} return false;
}
template<class T1,class T2> inline bool chmax(T1 &a,T2 b){
    if (a<b){a=b; return true;} return false;
}
#pragma endregion

template<typename T>
T euler_phi(T n){
    T res=n;
    for (T i=2;i*i<=n;++i) if (n%i==0){
        res-=res/i;
        while (n%i==0) n/=i;
    }
    if (n!=1) res-=res/n;
    return res;
}

template<typename T> vector<T> divisor(T n){
    vector<T> res;
    for (T i=1;i*i<=n;++i) if (n%i==0){
        res.emplace_back(i);
        if (i!=n/i) res.emplace_back(n/i);
    }
    return res;
}

long long modpow(long long x,long long n,long long mod){
    long long res=1;
    while (n>0){
        if (n&1LL) res=res*x%mod;
        x=x*x%mod; n>>=1LL;
    }
    return res;
}

int solve(int N){
    while (N%2==0) N/=2;
    while (N%5==0) N/=5;
    int ans=N;
    for (int d:divisor(euler_phi(N))){
        if (modpow(10,d,N)==1){
            ans=min(ans,d);
        }
    }
    return ans;
}

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    int t; cin >> t;
    for (;t--;){
        int N; cin >> N;
        cout << solve(N) << '\n';
    }
}
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