#606504 (C++17(clang)) No.1352 Three Coins

• 問題: No.1352 Three Coins
• ユーザー: 🐬hec
• 提出日時: 2021-01-17 13:41:03
• 言語: C++17(clang) (17.0.6 + boost 1.87.0)
• 結果: AC
• 実行時間: 28 ms / 2,000 ms
• コード長: 1,873 bytes
• コンパイル時間: 5,737 ms
• コンパイル使用メモリ: 138,552 KB
• 実行使用メモリ: 19,072 KB
• 最終ジャッジ日時: 2024-12-23 09:31:31
• 合計ジャッジ時間: 2,590 ms
• ジャッジサーバーID （参考情報）: judge2 / judge4

ファイルパターン	結果
sample	AC * 2
other	AC * 34

ソースコード

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#include <algorithm>
#include <bitset>
#include <cmath>
#include <complex>
#include <cstdio>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <sys/types.h>
#include <unistd.h>
#include <vector>
#pragma region macros
#define _overload(_1, _2, _3, name, ...) name
#define _rep(i, n) _range(i, 0, n)
#define _range(i, a, b) for (int i = int(a); i < int(b); ++i)
#define rep(...) _overload(__VA_ARGS__, _range, _rep, )(__VA_ARGS__)
#define _rrep(i, n) _rrange(i, n, 0)
#define _rrange(i, a, b) for (int i = int(a) - 1; i >= int(b); --i)
#define rrep(...) _overload(__VA_ARGS__, _rrange, _rrep, )(__VA_ARGS__)
#pragma endregion macros
using namespace std;
template <class T> bool chmax(T &a, const T &b) {
    return (a < b) ? (a = b, 1) : 0;
}
template <class T> bool chmin(T &a, const T &b) {
    return (b < a) ? (a = b, 1) : 0;
}
using ll    = long long;
using R     = long double;
const R EPS = 1e-9L;  // [-1000,1000]->EPS=1e-8 [-10000,10000]->EPS=1e-7
inline int sgn(const R &r) {
    return (r > EPS) - (r < -EPS);
}
inline R sq(R x) {
    return sqrt(max(x, 0.0L));
}
const int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};
const int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};
const pid_t pid = getpid();
// Problem Specific Parameter:
const int limit = 4000010;
int memo[limit];
int main(void) {
    int a, b, c;
    cin >> a >> b >> c;
    const ll g = gcd(gcd(a, b), c);
    if (g != 1) {
        puts("INF");
        return 0;
    }
    memo[0] = 1;
    int ans = 0;
    rep(i, limit) {
        if (i - a >= 0) {
            memo[i] |= memo[i - a];
        }
        if (i - b >= 0) {
            memo[i] |= memo[i - b];
        }
        if (i - c >= 0) {
            memo[i] |= memo[i - c];
        }
        ans += (memo[i] == 0);
    }
    cout << ans << endl;
    return 0;
}
 
 
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