結果

問題 No.1292 パタパタ三角形
コンテスト
ユーザー manini
提出日時 2021-01-25 17:58:38
言語 PyPy3
(7.3.17)
コンパイル:
pypy3 -mpy_compile _filename_
実行:
pypy3 _filename_
結果
AC  
実行時間 146 ms / 2,000 ms
+ 388µs
コード長 1,393 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 263 ms
コンパイル使用メモリ 96,104 KB
実行使用メモリ 115,712 KB
最終ジャッジ日時 2026-07-27 01:36:45
合計ジャッジ時間 3,516 ms
ジャッジサーバーID
(参考情報)
judge2_0 / judge1_0
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 14
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code

# coding:UTF-8
import sys

MOD = 10 ** 9 + 7
INF = float('inf')

S = input()     # 文字列

mp = {(0, 0)}
pos = [0, 0]
mode = [0, 0]

for s in S:
    if (mode == [0, 0] and s == "c") or (mode == [0, 1] and s == "a") or (mode == [0, 2] and s == "b"):
        pos[1] += 1
        mode[0] = 1
        mp.add((pos[0], pos[1]))
    elif (mode == [0, 0] and s == "b") or (mode == [0, 1] and s == "c") or (mode == [0, 2] and s == "a"):
        pos[0] += 1
        mode[0] = 1
        mode[1] = (mode[1] + 1) % 3
        mp.add((pos[0], pos[1]))
    elif (mode == [0, 0] and s == "a") or (mode == [0, 1] and s == "b") or (mode == [0, 2] and s == "c"):
        pos[0] -= 1
        mode[0] = 1
        mode[1] = (mode[1] - 1) % 3
        mp.add((pos[0], pos[1]))
    elif (mode == [1, 0] and s == "c") or (mode == [1, 1] and s == "a") or (mode == [1, 2] and s == "b"):
        pos[1] -= 1
        mode[0] = 0
        mp.add((pos[0], pos[1]))
    elif (mode == [1, 0] and s == "b") or (mode == [1, 1] and s == "c") or (mode == [1, 2] and s == "a"):
        pos[0] += 1
        mode[0] = 0
        mode[1] = (mode[1] + 1) % 3
        mp.add((pos[0], pos[1]))
    elif (mode == [1, 0] and s == "a") or (mode == [1, 1] and s == "b") or (mode == [1, 2] and s == "c"):
        pos[0] -= 1
        mode[0] = 0
        mode[1] = (mode[1] - 1) % 3
        mp.add((pos[0], pos[1]))

print("{}".format(len(mp)))
0