結果
| 問題 |
No.1136 Four Points Tour
|
| ユーザー |
tanimani364
|
| 提出日時 | 2021-03-08 21:30:50 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 4 ms / 2,000 ms |
| コード長 | 6,157 bytes |
| コンパイル時間 | 3,550 ms |
| コンパイル使用メモリ | 200,628 KB |
| 最終ジャッジ日時 | 2025-01-19 12:58:39 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 41 |
ソースコード
#include <bits/stdc++.h>
//#include<boost/multiprecision/cpp_int.hpp>
//#include<boost/multiprecision/cpp_dec_float.hpp>
//#include <atcoder/all>
#define rep(i, a) for (int i = (int)0; i < (int)a; ++i)
#define rrep(i, a) for (int i = (int)a - 1; i >= 0; --i)
#define REP(i, a, b) for (int i = (int)a; i < (int)b; ++i)
#define RREP(i, a, b) for (int i = (int)a - 1; i >= b; --i)
#define pb push_back
#define eb emplace_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define popcount __builtin_popcount
using ll = long long;
constexpr ll mod = 1e9 + 7;
constexpr ll INF = 1LL << 60;
// #pragma GCC target("avx2")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")
//using lll=boost::multiprecision::cpp_int;
//using Double=boost::multiprecision::number<boost::multiprecision::cpp_dec_float<1024>>;//仮数部が1024桁
template <class T>
inline bool chmin(T &a, T b)
{
if (a > b)
{
a = b;
return true;
}
return false;
}
template <class T>
inline bool chmax(T &a, T b)
{
if (a < b)
{
a = b;
return true;
}
return false;
}
template <typename T>
T mypow(T x, T n, const T &p = -1)
{ //x^nをmodで割った余り
if(p!=-1){
x%=p;
}
T ret = 1;
while (n > 0)
{
if (n & 1)
{
if (p != -1)
ret = (ret * x) % p;
else
ret *= x;
}
if (p != -1)
x = (x * x) % p;
else
x *= x;
n >>= 1;
}
return ret;
}
using namespace std;
//using namespace atcoder;
template<int mod>
struct Modint{
int x;
Modint():x(0){}
Modint(int64_t y):x((y%mod+mod)%mod){}
Modint &operator+=(const Modint &p){
if((x+=p.x)>=mod)
x -= mod;
return *this;
}
Modint &operator-=(const Modint &p){
if((x+=mod-p.x)>=mod)
x -= mod;
return *this;
}
Modint &operator*=(const Modint &p){
x = (1LL * x * p.x) % mod;
return *this;
}
Modint &operator/=(const Modint &p){
*this *= p.inverse();
return *this;
}
Modint operator-() const { return Modint(-x); }
Modint operator+(const Modint &p) const{
return Modint(*this) += p;
}
Modint operator-(const Modint &p) const{
return Modint(*this) -= p;
}
Modint operator*(const Modint &p) const{
return Modint(*this) *= p;
}
Modint operator/(const Modint &p) const{
return Modint(*this) /= p;
}
bool operator==(const Modint &p) const { return x == p.x; }
bool operator!=(const Modint &p) const{return x != p.x;}
Modint inverse() const{//非再帰拡張ユークリッド
int a = x, b = mod, u = 1, v = 0;
while(b>0){
int t = a / b;
swap(a -= t * b, b);
swap(u -= t * v, v);
}
return Modint(u);
}
Modint pow(int64_t n) const{//繰り返し二乗法
Modint ret(1), mul(x);
while(n>0){
if(n&1)
ret *= mul;
mul *= mul;
n >>= 1;
}
return ret;
}
friend ostream &operator<<(ostream &os,const Modint &p){
return os << p.x;
}
};
using modint = Modint<mod>;
template< class T >
struct Matrix {
vector< vector< T > > A;
Matrix() {}
Matrix(size_t n, size_t m) : A(n, vector< T >(m, 0)) {}
Matrix(size_t n) : A(n, vector< T >(n, 0)) {};
size_t height() const {
return (A.size());
}
size_t width() const {
return (A[0].size());
}
inline const vector< T > &operator[](int k) const {
return (A.at(k));
}
inline vector< T > &operator[](int k) {
return (A.at(k));
}
static Matrix I(size_t n) {
Matrix mat(n);
for(int i = 0; i < n; i++) mat[i][i] = 1;
return (mat);
}
Matrix &operator+=(const Matrix &B) {
size_t n = height(), m = width();
assert(n == B.height() && m == B.width());
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
(*this)[i][j] += B[i][j];
return (*this);
}
Matrix &operator-=(const Matrix &B) {
size_t n = height(), m = width();
assert(n == B.height() && m == B.width());
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
(*this)[i][j] -= B[i][j];
return (*this);
}
Matrix &operator*=(const Matrix &B) {
size_t n = height(), m = B.width(), p = width();
assert(p == B.height());
vector< vector< T > > C(n, vector< T >(m, 0));
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
for(int k = 0; k < p; k++)
C[i][j] = (C[i][j] + (*this)[i][k] * B[k][j]);
A.swap(C);
return (*this);
}
Matrix &operator^=(long long k) {
Matrix B = Matrix::I(height());
while(k > 0) {
if(k & 1) B *= *this;
*this *= *this;
k >>= 1LL;
}
A.swap(B.A);
return (*this);
}
Matrix operator+(const Matrix &B) const {
return (Matrix(*this) += B);
}
Matrix operator-(const Matrix &B) const {
return (Matrix(*this) -= B);
}
Matrix operator*(const Matrix &B) const {
return (Matrix(*this) *= B);
}
Matrix operator^(const long long k) const {
return (Matrix(*this) ^= k);
}
friend ostream &operator<<(ostream &os, Matrix &p) {
size_t n = p.height(), m = p.width();
for(int i = 0; i < n; i++) {
os << "[";
for(int j = 0; j < m; j++) {
os << p[i][j] << (j + 1 == m ? "]\n" : ",");
}
}
return (os);
}
T determinant() {
Matrix B(*this);
assert(width() == height());
T ret = 1;
for(int i = 0; i < width(); i++) {
int idx = -1;
for(int j = i; j < width(); j++) {
if(B[j][i] != 0) idx = j;
}
if(idx == -1) return (0);
if(i != idx) {
ret *= -1;
swap(B[i], B[idx]);
}
ret *= B[i][i];
T vv = B[i][i];
for(int j = 0; j < width(); j++) {
B[i][j] /= vv;
}
for(int j = i + 1; j < width(); j++) {
T a = B[j][i];
for(int k = 0; k < width(); k++) {
B[j][k] -= B[i][k] * a;
}
}
}
return (ret);
}
};
void solve()
{
ll n;
cin>>n;
Matrix<modint>mat(2,2);
mat[0][0]=modint(-1)/modint(3),mat[0][1]=modint(1)/modint(3);
mat[1][1]=1;
mat^=n;
modint x=3;
x=x.pow(n);
modint ans=(mat[0][0]+mat[0][1])*x;
cout<<ans<<"\n";
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout << fixed << setprecision(180);
solve();
return 0;
}
tanimani364