結果
問題 | No.1435 Mmm...... |
ユーザー |
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提出日時 | 2021-03-20 20:00:34 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 121 ms / 2,000 ms |
コード長 | 2,199 bytes |
コンパイル時間 | 2,018 ms |
コンパイル使用メモリ | 197,812 KB |
最終ジャッジ日時 | 2025-01-19 20:42:29 |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 24 |
ソースコード
#include <bits/stdc++.h>//#include<boost/multiprecision/cpp_int.hpp>//#include<boost/multiprecision/cpp_dec_float.hpp>//#include <atcoder/all>#define rep(i, a) for (int i = (int)0; i < (int)a; ++i)#define rrep(i, a) for (int i = (int)a - 1; i >= 0; --i)#define REP(i, a, b) for (int i = (int)a; i < (int)b; ++i)#define RREP(i, a, b) for (int i = (int)a - 1; i >= b; --i)#define repl(i, a) for (ll i = (ll)0; i < (ll)a; ++i)#define pb push_back#define eb emplace_back#define all(x) x.begin(), x.end()#define rall(x) x.rbegin(), x.rend()#define popcount __builtin_popcount#define fi first#define se secondusing ll = long long;constexpr ll mod = 1e9 + 7;constexpr ll mod_998244353 = 998244353;constexpr ll INF = 1LL << 60;// #pragma GCC target("avx2")// #pragma GCC optimize("O3")// #pragma GCC optimize("unroll-loops")//using lll=boost::multiprecision::cpp_int;//using Double=boost::multiprecision::number<boost::multiprecision::cpp_dec_float<1024>>;//仮数部が1024桁template <class T>inline bool chmin(T &a, T b){if (a > b){a = b;return true;}return false;}template <class T>inline bool chmax(T &a, T b){if (a < b){a = b;return true;}return false;}template <typename T>T mypow(T x, T n, const T &p = -1){ //x^nをmodで割った余りif (p != -1){x %= p;}T ret = 1;while (n > 0){if (n & 1){if (p != -1)ret = (ret * x) % p;elseret *= x;}if (p != -1)x = (x * x) % p;elsex *= x;n >>= 1;}return ret;}using namespace std;//using namespace atcoder;void solve(){int n;cin>>n;vector<int>a(n);rep(i,n)cin>>a[i];int r=0;multiset<int>st;ll ans=0;for(int l=0;l+1<n;++l){//[l,r)if(r-l==0){st.emplace(a[r]);++r;}if(r-l==1){st.emplace(a[r]);++r;}++ans;//r-l=2なら必ず満たすwhile(r<n){st.emplace(a[r]);if(*st.begin()+*next(st.begin())>=*prev(st.end())){++r;}else{st.erase(st.find(a[r]));break;}}ans+=r-l-2;st.erase(st.find(a[l]));}cout<<ans<<"\n";}int main(){ios::sync_with_stdio(false);cin.tie(nullptr);cout << fixed << setprecision(15);solve();return 0;}