結果
問題 | No.1496 不思議な数え上げ |
ユーザー | fastmath |
提出日時 | 2021-04-30 23:12:38 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 127 ms / 3,000 ms |
コード長 | 3,773 bytes |
コンパイル時間 | 1,390 ms |
コンパイル使用メモリ | 130,644 KB |
最終ジャッジ日時 | 2025-01-21 04:32:23 |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 39 |
ソースコード
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cmath> #include <vector> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <queue> #include <ctime> #include <cassert> #include <complex> #include <string> #include <cstring> #include <chrono> #include <random> #include <bitset> #include <fstream> using namespace std; #define int long long #define ii pair <int, int> #define app push_back #define all(a) a.begin(), a.end() #define bp __builtin_popcountll #define ll long long #define mp make_pair #define x first #define y second #define Time (double)clock()/CLOCKS_PER_SEC #define debug(x) std::cerr << #x << ": " << x << '\n'; #define FOR(i, n) for (int i = 0; i < n; ++i) #define FORN(i, n) for (int i = 1; i <= n; ++i) #define pb push_back #define trav(a, x) for (auto& a : x) using vi = vector<int>; template <typename T> std::istream& operator >>(std::istream& input, std::vector<T>& data) { for (T& x : data) input >> x; return input; } template <typename T> std::ostream& operator <<(std::ostream& output, const pair <T, T> & data) { output << "(" << data.x << "," << data.y << ")"; return output; } template <typename T> std::ostream& operator <<(std::ostream& output, const std::vector<T>& data) { for (const T& x : data) output << x << " "; return output; } ll div_up(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up ll div_down(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down ll math_mod(ll a, ll b) { return a - b * div_down(a, b); } #define tcT template<class T #define tcTU tcT, class U tcT> using V = vector<T>; tcT> void re(V<T>& x) { trav(a, x) cin >> a; } tcT> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } // set a = min(a,b) tcT> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll gcd(ll a, ll b) { while (b) { tie(a, b) = mp(b, a % b); } return a; } signed main() { #ifdef LOCAL #else #define endl '\n' ios_base::sync_with_stdio(0); cin.tie(0); #endif int n; cin >> n; vi p(n); cin >> p; vi l(n, -1), r(n, n); vi pos(n + 1); FOR (i, n) { pos[p[i]] = i; } vi s; FOR (i, n) { while (s.size() && p[s.back()] > p[i]) { s.pop_back(); } if (s.size()) { l[i] = s.back(); } s.app(i); } s.clear(); for (int i= n - 1; i >= 0; --i) { while (s.size() && p[s.back()] > p[i]) { s.pop_back(); } if (s.size()) { r[i] = s.back(); } s.app(i); } vi pref(n + 1); FOR (i, n) { pref[i + 1] = pref[i] + p[i]; } FORN (x, n) { int up; cin >> up; int i = pos[x]; int ans = 0; if (i - l[i] < r[i] - i) { for (int L = l[i] + 1; L <= i; ++L) { //pref[r] - pref[l] <= up ans += upper_bound(pref.begin() + i + 1, pref.begin() + r[i] + 1, up + pref[L]) - (pref.begin() + i + 1); } } else { for (int R = i; R < r[i]; ++R) { //pref[r + 1] - pref[l] <= up //pref[r + 1] - up <= pref[l] int lll = l[i]; int rrr = i + 1; while (lll < rrr - 1) { int m = (lll + rrr) / 2; if (pref[R + 1] - pref[m] > up) { lll = m; } else { rrr = m; } } ans += i + 1 - rrr; } } cout << ans << endl; } }