結果

問題 No.1532 Different Products
ユーザー leaf_1415leaf_1415
提出日時 2021-06-04 21:40:46
言語 C++11
(gcc 11.4.0)
結果
AC  
実行時間 455 ms / 4,000 ms
コード長 5,845 bytes
コンパイル時間 935 ms
コンパイル使用メモリ 85,840 KB
実行使用メモリ 317,412 KB
最終ジャッジ日時 2023-08-12 12:15:19
合計ジャッジ時間 22,063 ms
ジャッジサーバーID
(参考情報)
judge11 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 4 ms
9,528 KB
testcase_01 AC 190 ms
160,880 KB
testcase_02 AC 7 ms
19,724 KB
testcase_03 AC 3 ms
9,544 KB
testcase_04 AC 5 ms
13,572 KB
testcase_05 AC 3 ms
7,504 KB
testcase_06 AC 23 ms
25,152 KB
testcase_07 AC 33 ms
34,608 KB
testcase_08 AC 37 ms
38,624 KB
testcase_09 AC 75 ms
71,460 KB
testcase_10 AC 153 ms
134,308 KB
testcase_11 AC 134 ms
120,700 KB
testcase_12 AC 284 ms
207,868 KB
testcase_13 AC 143 ms
123,488 KB
testcase_14 AC 455 ms
314,008 KB
testcase_15 AC 33 ms
34,660 KB
testcase_16 AC 282 ms
235,924 KB
testcase_17 AC 128 ms
112,664 KB
testcase_18 AC 93 ms
83,900 KB
testcase_19 AC 221 ms
189,216 KB
testcase_20 AC 382 ms
293,700 KB
testcase_21 AC 312 ms
258,028 KB
testcase_22 AC 168 ms
145,184 KB
testcase_23 AC 101 ms
90,644 KB
testcase_24 AC 365 ms
284,516 KB
testcase_25 AC 267 ms
225,164 KB
testcase_26 AC 105 ms
95,968 KB
testcase_27 AC 373 ms
289,016 KB
testcase_28 AC 248 ms
214,084 KB
testcase_29 AC 399 ms
307,752 KB
testcase_30 AC 414 ms
317,152 KB
testcase_31 AC 400 ms
309,300 KB
testcase_32 AC 411 ms
314,152 KB
testcase_33 AC 389 ms
301,496 KB
testcase_34 AC 390 ms
301,516 KB
testcase_35 AC 397 ms
309,296 KB
testcase_36 AC 412 ms
317,180 KB
testcase_37 AC 392 ms
307,840 KB
testcase_38 AC 400 ms
307,780 KB
testcase_39 AC 392 ms
304,632 KB
testcase_40 AC 394 ms
303,148 KB
testcase_41 AC 411 ms
310,876 KB
testcase_42 AC 407 ms
309,332 KB
testcase_43 AC 406 ms
307,776 KB
testcase_44 AC 423 ms
317,152 KB
testcase_45 AC 421 ms
317,152 KB
testcase_46 AC 437 ms
317,304 KB
testcase_47 AC 416 ms
317,216 KB
testcase_48 AC 418 ms
317,176 KB
testcase_49 AC 423 ms
317,148 KB
testcase_50 AC 419 ms
317,288 KB
testcase_51 AC 422 ms
317,140 KB
testcase_52 AC 422 ms
317,144 KB
testcase_53 AC 421 ms
317,300 KB
testcase_54 AC 423 ms
317,292 KB
testcase_55 AC 422 ms
317,136 KB
testcase_56 AC 420 ms
317,412 KB
testcase_57 AC 421 ms
317,284 KB
testcase_58 AC 420 ms
317,128 KB
testcase_59 AC 423 ms
317,132 KB
testcase_60 AC 418 ms
317,128 KB
testcase_61 AC 3 ms
7,508 KB
testcase_62 AC 2 ms
7,556 KB
testcase_63 AC 421 ms
317,156 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <iostream>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#define rep(x, s, t) for(llint (x) = (s); (x) <= (t); (x)++)
#define per(x, s, t) for(llint (x) = (s); (x) >= (t); (x)--)
#define reps(x, s) for(llint (x) = 0; (x) < (llint)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define ceil(x, y) (((x)+(y)-1) / (y))
#define all(x) (x).begin(),(x).end()
#define outl(...) dump_func(__VA_ARGS__)
#define inf 1e18

using namespace std;

typedef long long llint;
typedef long long ll;
typedef pair<ll, ll> P;

struct edge{
	ll to, cost;
	edge(){}
	edge(ll a, ll b){ to = a, cost = b;}
};
const ll dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};

//const ll mod = 1000000007;
const ll mod = 998244353;

struct mint{
	ll x = 0;
	mint(ll y = 0){x = y; if(x < 0 || x >= mod) x = (x%mod+mod)%mod;}
	mint(const mint &ope) {x = ope.x;}
	
	mint operator-(){return mint(-x);}
	mint operator+(const mint &ope){return mint(x) += ope;}
	mint operator-(const mint &ope){return mint(x) -= ope;}
	mint operator*(const mint &ope){return mint(x) *= ope;}
	mint operator/(const mint &ope){return mint(x) /= ope;}
	mint& operator+=(const mint &ope){
		x += ope.x;
		if(x >= mod) x -= mod;
		return *this;
	}
	mint& operator-=(const mint &ope){
		x += mod - ope.x;
		if(x >= mod) x -= mod;
		return *this;
	}
	mint& operator*=(const mint &ope){
		x *= ope.x, x %= mod;
		return *this;
	}
	mint& operator/=(const mint &ope){
		ll n = mod-2; mint mul = ope;
		while(n){
			if(n & 1) *this *= mul;
			mul *= mul;
			n >>= 1;
		}
		return *this;
	}
	mint inverse(){return mint(1) / *this;}
	bool operator ==(const mint &ope){return x == ope.x;}
	bool operator !=(const mint &ope){return x != ope.x;}
};
mint modpow(mint a, ll n){
	if(n == 0) return mint(1);
	if(n % 2) return a * modpow(a, n-1);
	else return modpow(a*a, n/2);
}
istream& operator >>(istream &is, mint &ope){
	ll t; is >> t, ope.x = t;
	return is;
}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}

bool exceed(ll x, ll y, ll m){return x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "YES" << endl; }
void no(){ cout << "NO" << endl; }
ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;}
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll lcm(ll a, ll b){return a/gcd(a, b)*b;}
ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;}
ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;}
string lltos(ll x){string ret; for(;x;x/=10) ret += x % 10 + '0'; reverse(ret.begin(), ret.end()); return ret;}
ll stoll(string &s){ll ret = 0; for(auto c : s) ret *= 10, ret += c - '0'; return ret;}
template<typename T>
void uniq(T &vec){ sort(vec.begin(), vec.end()); vec.erase(unique(vec.begin(), vec.end()), vec.end());}

template<typename T>
ostream& operator << (ostream& os, vector<T>& vec) {
	for(int i = 0; i < vec.size(); i++) os << vec[i] << (i + 1 == vec.size() ? "" : " ");
	return os;
}
template<typename T>
ostream& operator << (ostream& os, deque<T>& deq) {
	for(int i = 0; i < deq.size(); i++) os << deq[i] << (i + 1 == deq.size() ? "" : " ");
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, pair<T, U>& pair_var) {
	os << "(" << pair_var.first << ", " << pair_var.second << ")";
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, const pair<T, U>& pair_var) {
	os << "(" << pair_var.first << ", " << pair_var.second << ")";
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, map<T, U>& map_var) {
	for(typename map<T, U>::iterator itr = map_var.begin(); itr != map_var.end(); itr++) {
		os << "(" << itr->first << ", " << itr->second << ")";
		itr++; if(itr != map_var.end()) os << ","; itr--;
	}
	return os;
}
template<typename T>
ostream& operator << (ostream& os, set<T>& set_var) {
	for(typename set<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
		os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
	}
	return os;
}
template<typename T>
ostream& operator << (ostream& os, multiset<T>& set_var) {
	for(typename multiset<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
		os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
	}
	return os;
}
template<typename T>
void outa(T a[], ll s, ll t){
	for(ll i = s; i <= t; i++){ cout << a[i]; if(i < t) cout << " ";}
	cout << endl;
}
void dump_func() {cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail) {
	cout << head;
	if(sizeof...(Tail) > 0) cout << " ";
	dump_func(std::move(tail)...);
}

ll n, k;
ll ldp[205][100005], rdp[205][100005];

int main(void)
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cin >> n >> k;
	if(n == 1){
		outl(1);
		return 0;
	}
	
	ldp[1][1] = 1;
	rep(i, 1, n-1){
		rep(j, 1, 100000){
			ldp[i+1][j] += ldp[i][j];
			if(j*(i+1) <= 100000) ldp[i+1][j*(i+1)] += ldp[i][j];
		}
	}
	if(k <= 100000){
		ll ans = 0;
		rep(j, 1, k) ans += ldp[n][j];
		ans *= 2, ans--;
		outl(ans);
		return 0;
	}
	
	rdp[n+1][1] = 1;
	per(i, n+1, 3){
		rep(j, 1, 100000){
			rdp[i-1][j] += rdp[i][j];
			if(j*(i-1) <= 100000) rdp[i-1][j*(i-1)] += rdp[i][j];
		}
	}
	rep(i, 2, n+1) rep(j, 2, 100000) rdp[i][j] += rdp[i][j-1];
	
	ll ans = 0;
	rep(j, 1, 100000) ans += ldp[n][j];
	rep(i, 2, n){
		rep(j, 1, 100000) if(i*j > 100000) ans += rdp[i+1][k/(i*j)] * ldp[i-1][j];
	}
	ans *= 2, ans--;
	outl(ans);
	
	return 0;
}
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