結果
問題 | No.1530 Permutation and Popcount |
ユーザー |
![]() |
提出日時 | 2021-06-04 22:56:18 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 44 ms / 2,000 ms |
コード長 | 3,005 bytes |
コンパイル時間 | 3,036 ms |
コンパイル使用メモリ | 222,496 KB |
最終ジャッジ日時 | 2025-01-22 03:00:46 |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 41 |
ソースコード
#pragma GCC optimize("O3")//#pragma GCC target("avx2")//#pragma GCC optimize("unroll-loops")#include <bits/stdc++.h>using namespace std;typedef long long ll;typedef unsigned long long ull;typedef long double ld;typedef vector<int> vi;typedef vector<ll> vll;typedef vector<ld> vld;typedef vector<bool> vb;typedef pair<ll,ll> Pll;typedef pair<int,int> Pin;ll INF = 1e16;int inf = 1e9;#define ALL(x) (x).begin(), (x).end()#define FOR(i, m, n) for (ll i = (m); i < (n); ++i)#define REVFOR(i, m, n) for (ll i = ((n) - 1); i >= (m); --i)#define REP(i, n) FOR(i, 0, n)#define REVREP(i, n) REVFOR(i, 0, n)#define fi first#define se second#define pb push_back#define mp make_pair#define eb emplace_back#define bcnt __builtin_popcountll// inputs#define VLLIN(x, n) vll x(n); REP(i, n) cin >> x[i];#define VIIN(x, n) vi x(n); REP(i, n) cin >> x[i];#define VLDIN(x, n) vld x(n); REP(i, n) cin >> x[i];#define SIN(s, n) string s; cin >> s;#ifdef LOCAL#include <prettyprint.hpp>#define debug(...) cerr << "[" << #__VA_ARGS__ << "]: ", d_err(__VA_ARGS__);#else#define debug(...) 83;#endifvoid d_err() {cerr << endl;}template <typename H, typename... T>void d_err(H h, T... t) {cerr << h << " ";d_err(t...);}template <typename T>void print(T x) {cout << x << "\n";}template <typename T>void print(vector<T>& x) {int N = x.size();REP(i, N) {if (i > 0) cout << " ";cout << x[i];}cout << "\n";}int main(){cin.tie(0);ios_base::sync_with_stdio(false);cout << fixed << setprecision(20);int n, k; cin >> n >> k;vll cost(n, 0);REP(i, n) {int a = i + 1;REP(j, n) {int b = j + 1;int c = ~bcnt(a * b) & 1;cost[i] += c * 2;}}ll all = accumulate(ALL(cost), 0LL) / 2;if (all == k) {vll ans;REP(i, n) ans.eb(i + 1);vi first = {n, 0};print(first);print(ans);print("");return 0;}if (all < k) {print(-1);return 0;}int MX = all - k;vector<vi> dp(MX + 1);REP(i, n) {REVREP(j, MX + 1) {if (dp[j].empty()) continue;ll c = cost[i] + j;if (c > MX) continue;if (dp[c].size()) continue;dp[c] = dp[j];dp[c].eb(i + 1);}ll c = cost[i];if (c <= MX && dp[c].empty()) dp[c].eb(i + 1);}auto &y = dp[MX];if (y.empty()) {print(-1);} else {int q = y.size();int p = n - q;vll x;REP(i, n) {int a = i + 1;bool f = true;for(auto &e: y) {if (e == a) {f = false;break;}}if (f) x.eb(a);}vll first = {p, q};print(first);print(x);print(y);}}