結果
| 問題 |
No.1586 Equal Array
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-07-08 22:28:28 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 14 ms / 1,000 ms |
| コード長 | 2,831 bytes |
| コンパイル時間 | 1,742 ms |
| コンパイル使用メモリ | 172,684 KB |
| 実行使用メモリ | 6,948 KB |
| 最終ジャッジ日時 | 2024-07-01 12:47:18 |
| 合計ジャッジ時間 | 2,796 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 20 |
コンパイルメッセージ
main.cpp: In function 'long long int divisors(long long int)':
main.cpp:70:1: warning: no return statement in function returning non-void [-Wreturn-type]
70 | }
| ^
main.cpp: In function 'int power(long long int, long long int)':
main.cpp:100:1: warning: no return statement in function returning non-void [-Wreturn-type]
100 | }
| ^
main.cpp: In function 'bool isprime(int)':
main.cpp:51:1: warning: control reaches end of non-void function [-Wreturn-type]
51 | }
| ^
ソースコード
#include<bits/stdc++.h>
#define ll long long
#define rep(i,x,y) for(i=x;i<y;i++)
#define f first
#define s second
#define pb push_back
using namespace std;
ll i,j,c=0,x=1,y=1,r=0,result=0,ans=1,temp=0,sum=1,a,b,e,f,g,h,d,n,m,t,cont=1e9+7;
string str,str1,str2,s1,s2,s3=" ";
vector<ll> v,v1,v2;
map<string, int> mp;
//GCD of two number using Euclidean Algorithm
//Time Complexity=O(log(min(a,b))
ll gcd(ll a,ll b)
{
if(b==0)
return a;
else
return gcd(b,a%b);
}
//a*b=gcd(a,b)*lcm(a,b)
//Fastest Way of Finding LCM
ll lcm(ll a,ll b)
{
return a*b/gcd(a,b);
}
//This is also funtion of finding prime numbers but time complexity
//is more.
//Time Complixity: O(n^3/2)
bool isprime(int n)
{
if(n==1)
return 0;
if(n==2||n==3)
return 1;
if(n%2==0 || n%3==0)
return 0;
for(ll i=5; i*i<=n; i+=6)
{
if(n%i==0 || n%(i+2)==0)
return 0;
return 1;
}
}
ll divisors(ll n)
{
ll i;
rep(i,1,sqrt(n))
{
if (n%i == 0)
{
// If divisors are equal, print only one
if (n/i == i)
cout<<i<<" ";
else // Otherwise print both
cout<<i<<" "<<n/i<<" ";
}
}
}
//Sieve of Eratosthenes
//it will print all the prime numbers
//Time Complexity :O(log log n)
void sieve (int n)
{
vector<bool>isprime(n+1,true );
{
for(i=2; i<=n; i++)
{
if(isprime[i])
{
cout<<i<<" ";
for(j=i*i; j<=n; j+=i)
{
isprime[j]=false;
}
}
}
}
}
int power(ll n,ll m)
{
for(i=0; i<m; i++)
{
sum=sum*n;
}
cout<<sum;
}
//calculating the Power of the number using itreative
//Time Complexity O(log n)
//Space Complexity O(1)
ll powe(ll n, ll m)
{
while(m>0)
{
if(m&1)
ans*=n;
n*=n;
m=m>>1;
}
return ans;
}
int power(long long x, unsigned int y, int p)
{
int res = 1; // Initialize result
x = x % p; // Update x if it is more than or
// equal to p
if (x == 0) return 0; // In case x is divisible by p;
while (y > 0)
{
// If y is odd, multiply x with result
if (y & 1)
res = (res*x) % p;
// y must be even now
y = y>>1; // y = y/2
x = (x*x) % p;
}
return res;
}
/**************** MAINCODE *************************/
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> t;
c=0;
d=t;
while(t--)
{
cin >> b;
c+=b;
}
if(c%d==0)
cout << "Yes\n";
else
cout << "No\n";
return 0;
}