結果

問題 No.1243 約数加算
ユーザー chineristACchineristAC
提出日時 2021-07-09 03:36:22
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 69 ms / 2,000 ms
コード長 3,063 bytes
コンパイル時間 168 ms
コンパイル使用メモリ 81,792 KB
実行使用メモリ 71,552 KB
最終ジャッジ日時 2024-07-01 13:51:59
合計ジャッジ時間 1,435 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys,random,bisect
from collections import deque,defaultdict
from heapq import heapify,heappop,heappush
from itertools import permutations
from math import gcd,log
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
def isPrimeMR(n):
if n==1:
return 0
d = n - 1
d = d // (d & -d)
L = [2, 3, 5, 7, 11, 13, 17]
if n in L:
return True
for a in L:
t = d
y = pow(a, t, n)
if y == 1: continue
while y != n - 1:
y = (y * y) % n
if y == 1 or t == n - 1: return 0
t <<= 1
return 1
def findFactorRho(n):
from math import gcd
m = 1 << n.bit_length() // 8
for c in range(1, 99):
f = lambda x: (x * x + c) % n
y, r, q, g = 2, 1, 1, 1
while g == 1:
x = y
for i in range(r):
y = f(y)
k = 0
while k < r and g == 1:
ys = y
for i in range(min(m, r - k)):
y = f(y)
q = q * abs(x - y) % n
g = gcd(q, n)
k += m
r <<= 1
if g == n:
g = 1
while g == 1:
ys = f(ys)
g = gcd(abs(x - ys), n)
if g < n:
if isPrimeMR(g): return g
elif isPrimeMR(n // g): return n // g
return findFactorRho(g)
def primeFactor(n):
i = 2
ret = {}
rhoFlg = 0
while i*i <= n:
k = 0
while n % i == 0:
n //= i
k += 1
if k: ret[i] = k
i += 1 + i % 2
if i == 101 and n >= 2 ** 20:
while n > 1:
if isPrimeMR(n):
ret[n], n = 1, 1
else:
rhoFlg = 1
j = findFactorRho(n)
k = 0
while n % j == 0:
n //= j
k += 1
ret[j] = k
if n > 1: ret[n] = 1
if rhoFlg: ret = {x: ret[x] for x in sorted(ret)}
return ret
def divisors(n):
res = [1]
prime = primeFactor(n)
for p in prime:
newres = []
for d in res:
for j in range(prime[p]+1):
newres.append(d*p**j)
res = newres
return res
for _ in range(int(input())):
a,b = mi()
A,B = a,b
g = gcd(a,b)
a,b = a//g,b//g
res = []
for i in range(59,-1,-1):
if a>>i & 1 and b>>i & 1:
a -= 2**i
b -= 2**i
elif not (a>>i & 1 == 0 and b>>i & 1 == 0):
break
if a:
while a.bit_length() < b.bit_length():
res.append(a&(-a))
a += a&(-a)
b -= a
for i in range(59,-1,-1):
if b>>i & 1:
res.append(1<<i)
for i in range(len(res)):
res[i] *= g
print(len(res))
print(*res)
for g in res:
assert A%g==0
A += g
assert A==B
assert len(res) <= 120
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