結果

問題 No.1621 Sequence Inversions
ユーザー heno239
提出日時 2021-07-22 21:47:59
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 40 ms / 3,000 ms
コード長 4,082 bytes
コンパイル時間 2,490 ms
コンパイル使用メモリ 153,768 KB
最終ジャッジ日時 2025-01-23 06:29:46
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 26
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 998244353;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acosl(-1.0);
ll mod_pow(ll x, ll n, ll m = mod) {
if (n < 0) {
ll res = mod_pow(x, -n, m);
return mod_pow(res, m - 2, m);
}
if (abs(x) >= m)x %= m;
if (x < 0)x += m;
ll res = 1;
while (n) {
if (n & 1)res = res * x % m;
x = x * x % m; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n % mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
if (n == 0)return modint(1);
modint res = (a * a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
ll inv(ll a, ll p) {
return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 18;
modint fact[max_n], factinv[max_n];
void init_f() {
fact[0] = modint(1);
for (int i = 0; i < max_n - 1; i++) {
fact[i + 1] = fact[i] * modint(i + 1);
}
factinv[max_n - 1] = modint(1) / fact[max_n - 1];
for (int i = max_n - 2; i >= 0; i--) {
factinv[i] = factinv[i + 1] * modint(i + 1);
}
}
modint comb(int a, int b) {
if (a < 0 || b < 0 || a < b)return 0;
return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
if (a < 0 || b < 0 || a < b)return 0;
return fact[a] * factinv[a - b];
}
modint dp[105][10005];
void solve() {
int n, k; cin >> n >> k;
assert(n <= 100);
vector<ll> a(n);
rep(i, n) {
cin >> a[i];
assert(a[i] <= 1000000000);
}
//rep(i, n - 1)assert(a[i] <= a[i + 1]);
vector<int> c;
sort(all(a));
rep(i, n) {
int le = i;
while (i + 1 < n && a[i] == a[i + 1])i++;
c.push_back(i - le + 1);
}
vector<modint> cdp = { 1 };
int sum = c[0];
for (int i = 1; i < c.size(); i++) {
rep(j, c[i] + 1)rep(k, sum * c[i] + 1)dp[j][k] = 0;
dp[0][0] = 1;
for (int num = 0; num <= sum; num++) {
rep(j, c[i])rep(k, sum * c[i] + 1) {
if (dp[j][k] == (modint)0)continue;
assert(k + num <= sum * c[i]);
dp[j + 1][k + num] += dp[j][k];
}
}
vector<modint> ndp(cdp.size() + sum * c[i]);
rep(j, cdp.size())rep(k, sum * c[i] + 1) {
modint val = cdp[j] * dp[c[i]][k];
ndp[j + k] += val;
}
swap(cdp, ndp);
sum += c[i];
}
modint ans = 0;
if (k < cdp.size())ans = cdp[k];
cout << ans << "\n";
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
//cout << fixed << setprecision(12);
//init_f();
//init();
//expr();
//int t; cin >> t; rep(i, t)
solve();
return 0;
}
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