結果

問題 No.1621 Sequence Inversions
ユーザー tamato
提出日時 2021-07-22 23:13:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 2,977 ms / 3,000 ms
コード長 1,445 bytes
コンパイル時間 134 ms
コンパイル使用メモリ 82,696 KB
実行使用メモリ 129,660 KB
最終ジャッジ日時 2024-07-17 19:58:37
合計ジャッジ時間 22,494 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 26
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

mod = 998244353
eps = 10**-9
def main():
    import sys
    from collections import Counter
    input = sys.stdin.readline
    def calc_k(x, y):
        res = [0] * (x * y + 1)
        dp = [[[0] * (x * y + 1) for _ in range(x+1)] for _ in range(y + 1)]
        dp[0][0][0] = 1
        for i in range(y):
            for j in range(x+1):
                for k in range(j, x+1):
                    for lv in range(x*y+1):
                        lv_new = lv + k
                        if lv_new <= x*y:
                            dp[i+1][k][lv_new] = (dp[i+1][k][lv_new] + dp[i][j][lv])%mod
        for j in range(x+1):
            for lv in range(x*y+1):
                res[lv] = (res[lv] + dp[-1][j][lv]) % mod
        return res
    N, K = map(int, input().split())
    A = list(map(int, input().split()))
    A.sort(reverse=True)
    C = Counter(A)
    D = {}
    for a in C:
        D[a] = 0
    inv_max = N * (N - 1) // 2
    dp = [[0] * (inv_max+1) for _ in range(N+1)]
    dp[0][0] = 1
    for i in range(N):
        a = A[i]
        if D[a]:
            dp[i+1] = dp[i]
            continue
        R = calc_k(i, C[a])
        for inv in range(inv_max + 1):
            for j, r in enumerate(R):
                inv_new = inv + j
                if inv_new <= inv_max:
                    dp[i+1][inv_new] = (dp[i+1][inv_new] + dp[i][inv] * r)%mod
        D[a] += 1
    print(dp[-1][K])
if __name__ == '__main__':
    main()
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