結果
問題 | No.1580 I like Logarithm! |
ユーザー |
|
提出日時 | 2021-08-01 21:38:10 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 17 ms / 2,000 ms |
コード長 | 3,883 bytes |
コンパイル時間 | 1,615 ms |
コンパイル使用メモリ | 136,624 KB |
最終ジャッジ日時 | 2025-01-23 13:28:55 |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 6 |
other | AC * 39 |
ソースコード
#include <iostream>#include <vector>#include <algorithm>#include <cmath>#include <queue>#include <string>#include <map>#include <set>#include <stack>#include <tuple>#include <deque>#include <array>#include <numeric>#include <bitset>#include <iomanip>#include <cassert>#include <chrono>#include <random>#include <limits>#include <iterator>#include <functional>#include <sstream>#include <fstream>#include <complex>#include <cstring>#include <unordered_map>#include <unordered_set>using namespace std;// #pragma GCC optimize("O3")// #pragma GCC optimize("unroll-loops")// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")// #pragma GCC target("avx512f,avx512dq,avx512cd,avx512bw,avx512vl")using ll = long long;constexpr int INF = 1001001001;constexpr int mod = 1000000007;// constexpr int mod = 998244353;template<class T>inline bool chmax(T& x, T y){if(x < y){x = y;return true;}return false;}template<class T>inline bool chmin(T& x, T y){if(x > y){x = y;return true;}return false;}struct mint {int x;mint() : x(0) {}mint(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}mint& operator+=(const mint& p){if((x += p.x) >= mod) x -= mod;return *this;}mint& operator-=(const mint& p){if((x -= p.x) < 0) x += mod;return *this;}mint& operator*=(const mint& p){x = (int)(1LL * x * p.x % mod);return *this;}mint& operator/=(const mint& p){*this *= p.inverse();return *this;}mint operator-() const { return mint(-x); }mint operator+(const mint& p) const { return mint(*this) += p; }mint operator-(const mint& p) const { return mint(*this) -= p; }mint operator*(const mint& p) const { return mint(*this) *= p; }mint operator/(const mint& p) const { return mint(*this) /= p; }bool operator==(const mint& p) const { return x == p.x; }bool operator!=(const mint& p) const { return x != p.x; }mint pow(int64_t n) const {mint res = 1, mul = x;while(n > 0){if(n & 1) res *= mul;mul *= mul;n >>= 1;}return res;}// x^(a^b)// warning : x と mod は互いに素// x != 0 かつ x % mod == 0 かつ a > 0 はこれを呼び出さずに 0 を返すように処理mint pow2(int64_t a, int64_t b) const {if(b == 0) return *this;if((a %= mod - 1) == 0) return mint(1);int64_t n = 1;while(b > 0){if(b & 1) (n *= a) %= mod - 1;(a *= a) %= mod - 1;b >>= 1;}return pow(n);}mint inverse() const { return pow(mod - 2); }friend ostream& operator<<(ostream& os, const mint& p){return os << p.x;}friend istream& operator>>(istream& is, mint& p){int64_t val;is >> val;p = mint(val);return is;}};int main(){ios::sync_with_stdio(false);cin.tie(nullptr);int A;string s;cin >> A >> s;int n = s.length();vector<mint> powa(n + 1, 1);for(int i = 0; i < n; ++i) powa[i + 1] = powa[i] * A;int msd = s[0] - '0';mint ans = powa[n - 1] * (msd - 1) * (n - 1);vector dp(n + 1, vector<mint>(2));dp[1][0] = 1;for(int i = 1; i < n; ++i){int num = s[i] - '0';ans += powa[n - i - 1] * (A - 1) * (n - i - 1);for(int j = 0; j < 2; ++j){if(dp[i][j] == 0) continue;for(int x = 0; x <= (j ? A - 1 : num); ++x){int nj = j | (x < num);dp[i + 1][nj] += dp[i][j];}}}ans += (dp[n][0] + dp[n][1]) * (n - 1);cout << ans << endl;return 0;}