結果
問題 | No.1685 One by One |
ユーザー | Sumitacchan |
提出日時 | 2021-08-03 17:52:08 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
RE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 6,228 bytes |
コンパイル時間 | 2,183 ms |
コンパイル使用メモリ | 206,992 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-29 19:21:36 |
合計ジャッジ時間 | 7,298 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | RE | - |
testcase_04 | RE | - |
testcase_05 | RE | - |
testcase_06 | RE | - |
testcase_07 | RE | - |
testcase_08 | RE | - |
testcase_09 | AC | 7 ms
5,376 KB |
testcase_10 | RE | - |
testcase_11 | AC | 5 ms
5,376 KB |
testcase_12 | RE | - |
testcase_13 | RE | - |
testcase_14 | AC | 20 ms
5,376 KB |
testcase_15 | RE | - |
testcase_16 | RE | - |
testcase_17 | RE | - |
testcase_18 | RE | - |
testcase_19 | RE | - |
testcase_20 | RE | - |
testcase_21 | RE | - |
testcase_22 | RE | - |
testcase_23 | RE | - |
testcase_24 | RE | - |
testcase_25 | RE | - |
testcase_26 | RE | - |
testcase_27 | RE | - |
testcase_28 | RE | - |
testcase_29 | RE | - |
testcase_30 | RE | - |
testcase_31 | RE | - |
testcase_32 | RE | - |
testcase_33 | RE | - |
testcase_34 | RE | - |
testcase_35 | RE | - |
testcase_36 | RE | - |
testcase_37 | RE | - |
testcase_38 | RE | - |
testcase_39 | RE | - |
testcase_40 | RE | - |
testcase_41 | RE | - |
testcase_42 | AC | 2 ms
5,376 KB |
testcase_43 | AC | 2 ms
5,376 KB |
testcase_44 | AC | 2 ms
5,376 KB |
testcase_45 | AC | 2 ms
5,376 KB |
testcase_46 | RE | - |
testcase_47 | RE | - |
testcase_48 | RE | - |
testcase_49 | RE | - |
ソースコード
#include <bits/stdc++.h> using namespace std; //using namespace atcoder; using ll = long long; struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define FOR(i, begin, end) for(int i=(begin);i<(end);i++) #define REP(i, n) FOR(i,0,n) #define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--) #define IREP(i, n) IFOR(i,0,n) #define Sort(v) sort(v.begin(), v.end()) #define Reverse(v) reverse(v.begin(), v.end()) #define all(v) v.begin(),v.end() #define SZ(v) ((int)v.size()) #define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x)) #define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x)) #define chmax(a, b) a = max(a, b) #define chmin(a, b) a = min(a, b) #define bit(n) (1LL<<(n)) #define debug(x) cout << #x << "=" << x << endl; #define vdebug(v) { cout << #v << "=" << endl; REP(i_debug, v.size()){ cout << v[i_debug] << ","; } cout << endl; } #define mdebug(m) { cout << #m << "=" << endl; REP(i_debug, m.size()){ REP(j_debug, m[i_debug].size()){ cout << m[i_debug][j_debug] << ","; } cout << endl;} } #define pb push_back #define fi first #define se second #define int long long #define INF 1000000000000000000 template<typename T> istream &operator>>(istream &is, vector<T> &v){ for (auto &x : v) is >> x; return is; } template<typename T> ostream &operator<<(ostream &os, vector<T> &v){ for(int i = 0; i < v.size(); i++) { cout << v[i]; if(i != v.size() - 1) cout << endl; }; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p){ cout << '(' << p.first << ',' << p.second << ')'; return os; } template<typename T> void Out(T x) { cout << x << endl; } template<typename T1, typename T2> void chOut(bool f, T1 y, T2 n) { if(f) Out(y); else Out(n); } using vec = vector<int>; using mat = vector<vec>; using Pii = pair<int, int>; using v_bool = vector<bool>; using v_Pii = vector<Pii>; //int dx[4] = {1,0,-1,0}; //int dy[4] = {0,1,0,-1}; //char d[4] = {'D','R','U','L'}; const int mod = 1000000007; //const int mod = 998244353; template<long long MOD> struct ModInt{ using ll = long long; ll val; void setval(ll v) { val = v % MOD; }; ModInt(): val(0) {} ModInt(ll v) { setval(v); }; ModInt operator+(const ModInt &x) const { return ModInt(val + x.val); } ModInt operator-(const ModInt &x) const { return ModInt(val - x.val + MOD); } ModInt operator*(const ModInt &x) const { return ModInt(val * x.val); } ModInt operator/(const ModInt &x) const { return *this * x.inv(); } ModInt operator-() const { return ModInt(MOD - val); } ModInt operator+=(const ModInt &x) { return *this = *this + x; } ModInt operator-=(const ModInt &x) { return *this = *this - x; } ModInt operator*=(const ModInt &x) { return *this = *this * x; } ModInt operator/=(const ModInt &x) { return *this = *this / x; } bool operator==(const ModInt &x) const { return (*this).val == x.val; } friend ostream& operator<<(ostream &os, const ModInt &x) { os << x.val; return os; } friend istream& operator>>(istream &is, ModInt &x) { is >> x.val; x.val = (x.val % MOD + MOD) % MOD; return is; } ModInt pow(ll n) const { ModInt a = 1; if(n == 0) return a; int i0 = 64 - __builtin_clzll(n); for(int i = i0 - 1; i >= 0; i--){ a = a * a; if((n >> i) & 1) a *= (*this); } return a; } ModInt inv() const { return this->pow(MOD - 2); } }; using mint = ModInt<mod>; mint pow(mint x, long long n) { return x.pow(n); } //using mint = double; //for debug using mvec = vector<mint>; using mmat = vector<mvec>; struct Combination{ vector<mint> fact, invfact; Combination(int N){ fact = vector<mint>({mint(1)}); invfact = vector<mint>({mint(1)}); fact_initialize(N); } void fact_initialize(int N){ int i0 = fact.size(); if(i0 >= N + 1) return; fact.resize(N + 1); invfact.resize(N + 1); for(int i = i0; i <= N; i++) fact[i] = fact[i - 1] * i; invfact[N] = (mint)1 / fact[N]; for(int i = N - 1; i >= i0; i--) invfact[i] = invfact[i + 1] * (i + 1); } mint nCr(int n, int r){ if(n < 0 || r < 0 || r > n) return mint(0); if(fact.size() < n + 1) fact_initialize(n); return fact[n] * invfact[r] * invfact[n - r]; } mint nPr(int n, int r){ if(n < 0 || r < 0 || r > n) return mint(0); if(fact.size() < n + 1) fact_initialize(n); return fact[n] * invfact[n - r]; } mint Catalan(int n){ if(n < 0) return 0; else if(n == 0) return 1; if(fact.size() < 2 * n + 1) fact_initialize(2 * n); return fact[2 * n] * invfact[n + 1] * invfact[n]; } }; signed main(){ int N, M; cin >> N >> M; assert(2 <= N && N <= 2000); assert(0 <= M && M <= 2000); Combination C(N + M); int center = (N - 1) / 2; mint ans = 0; FOR(n0, 1, N){ int n1 = N - n0; //n1項の正の数でmを作る場合の数 mvec comb(M + 1, 0); FOR(m, n1, M + 1){ /*if(m == 0 && n1 == 0) comb[m] = 1; else comb[m] = C.nCr(m - 1, n1 - 1);*/ assert(n1 > 0); comb[m] = C.nCr(m - 1, n1 - 1); } //2個ずつ累積和 FOR(m, 2, M + 1) comb[m] += comb[m - 2]; REP(np, n1 + 1){ int nm = n1 - np; //標準系かどうか if(!(nm <= center && center <= nm + n0 - 1)) continue; //0,+,-の配置 mint c_0pm = C.nCr(N, n1) * C.nCr(n1, np); //Mと偶奇が一致する分 ans += c_0pm * comb[M]; //Mと偶奇が一致しない分 if(N % 2){ //標準系から1ずらしたときのコストの増え方の最小値、必ず奇数 int add = min(np, nm) + n0 - max(np, nm); if(add <= M) ans += c_0pm * comb[M - add]; } } } if(M % 2 == 0) ans += 1; else if(N % 2 == 1 && N <= M) ans += 1; cout << ans << endl; return 0; }