結果
問題 | No.876 Range Compress Query |
ユーザー | koba-e964 |
提出日時 | 2021-09-17 01:49:35 |
言語 | Rust (1.77.0 + proconio) |
結果 |
AC
|
実行時間 | 116 ms / 2,000 ms |
コード長 | 3,480 bytes |
コンパイル時間 | 12,243 ms |
コンパイル使用メモリ | 395,028 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-06-29 17:19:26 |
合計ジャッジ時間 | 13,220 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 0 ms
6,812 KB |
testcase_01 | AC | 1 ms
6,812 KB |
testcase_02 | AC | 1 ms
6,816 KB |
testcase_03 | AC | 1 ms
6,944 KB |
testcase_04 | AC | 1 ms
6,944 KB |
testcase_05 | AC | 1 ms
6,940 KB |
testcase_06 | AC | 1 ms
6,944 KB |
testcase_07 | AC | 1 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,940 KB |
testcase_09 | AC | 2 ms
6,944 KB |
testcase_10 | AC | 1 ms
6,940 KB |
testcase_11 | AC | 116 ms
6,940 KB |
testcase_12 | AC | 97 ms
6,940 KB |
testcase_13 | AC | 99 ms
6,940 KB |
testcase_14 | AC | 116 ms
6,940 KB |
testcase_15 | AC | 82 ms
6,940 KB |
testcase_16 | AC | 110 ms
6,944 KB |
testcase_17 | AC | 107 ms
6,944 KB |
testcase_18 | AC | 114 ms
6,940 KB |
ソースコード
#[allow(unused_imports)] use std::cmp::*; #[allow(unused_imports)] use std::collections::*; use std::io::Read; fn get_word() -> String { let stdin = std::io::stdin(); let mut stdin=stdin.lock(); let mut u8b: [u8; 1] = [0]; loop { let mut buf: Vec<u8> = Vec::with_capacity(16); loop { let res = stdin.read(&mut u8b); if res.unwrap_or(0) == 0 || u8b[0] <= b' ' { break; } else { buf.push(u8b[0]); } } if buf.len() >= 1 { let ret = String::from_utf8(buf).unwrap(); return ret; } } } #[allow(dead_code)] fn get<T: std::str::FromStr>() -> T { get_word().parse().ok().unwrap() } /** * Segment Tree. This data structure is useful for fast folding on intervals of an array * whose elements are elements of monoid I. Note that constructing this tree requires the identity * element of I and the operation of I. * Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581) * AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001) */ struct SegTree<I, BiOp> { n: usize, dat: Vec<I>, op: BiOp, e: I, } impl<I, BiOp> SegTree<I, BiOp> where BiOp: Fn(I, I) -> I, I: Copy { pub fn new(n_: usize, op: BiOp, e: I) -> Self { let mut n = 1; while n < n_ { n *= 2; } // n is a power of 2 SegTree {n: n, dat: vec![e; 2 * n - 1], op: op, e: e} } /* ary[k] <- v */ pub fn update(&mut self, idx: usize, v: I) { let mut k = idx + self.n - 1; self.dat[k] = v; while k > 0 { k = (k - 1) / 2; self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]); } } /* [a, b) (note: half-inclusive) * http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */ pub fn query(&self, mut a: usize, mut b: usize) -> I { let mut left = self.e; let mut right = self.e; a += self.n - 1; b += self.n - 1; while a < b { if (a & 1) == 0 { left = (self.op)(left, self.dat[a]); } if (b & 1) == 0 { right = (self.op)(self.dat[b - 1], right); } a = a / 2; b = (b - 1) / 2; } (self.op)(left, right) } } fn main() { let n: usize = get(); let q: usize = get(); let a: Vec<i64> = (0..n).map(|_| get()).collect(); let mut st = SegTree::new(n - 1, |x, y| x + y, 0); let mut dif = vec![0; n - 1]; for i in 0..n - 1 { dif[i] = a[i + 1] - a[i]; if dif[i] != 0 { st.update(i, 1); } } for _ in 0..q { let ty: i32 = get(); let l = get::<usize>() - 1; let r: usize = get(); if ty == 1 { let x: i64 = get(); if l > 0 { let old = dif[l - 1]; dif[l - 1] += x; if (old != 0) != (dif[l - 1] != 0) { st.update(l - 1, if dif[l - 1] != 0 { 1 } else { 0 }); } } if r < n { let old = dif[r - 1]; dif[r - 1] -= x; if (old != 0) != (dif[r - 1] != 0) { st.update(r - 1, if dif[r - 1] != 0 { 1 } else { 0 }); } } } else { println!("{}", st.query(l, r - 1) + 1); } } }