結果
問題 | No.1688 Veterinarian |
ユーザー | suta28407928 |
提出日時 | 2021-09-24 21:52:26 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 51 ms / 3,000 ms |
コード長 | 3,589 bytes |
コンパイル時間 | 2,028 ms |
コンパイル使用メモリ | 179,768 KB |
実行使用メモリ | 99,300 KB |
最終ジャッジ日時 | 2024-07-05 10:27:39 |
合計ジャッジ時間 | 2,790 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 8 ms
32,484 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 2 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 21 ms
85,952 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 51 ms
99,300 KB |
testcase_09 | AC | 48 ms
98,276 KB |
testcase_10 | AC | 24 ms
86,960 KB |
testcase_11 | AC | 16 ms
61,776 KB |
testcase_12 | AC | 3 ms
7,760 KB |
testcase_13 | AC | 15 ms
65,604 KB |
testcase_14 | AC | 5 ms
22,172 KB |
testcase_15 | AC | 27 ms
87,592 KB |
testcase_16 | AC | 5 ms
20,072 KB |
ソースコード
#pragma GCC ta g("avx2") #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") #include <bits/stdc++.h> using namespace std; #define DEBUG #ifdef DEBUG template <class T, class U> ostream &operator<<(ostream &os, const pair<T, U> &p) { os << '(' << p.first << ',' << p.second << ')'; return os; } template <class T> ostream &operator<<(ostream &os, const vector<T> &v) { os << '{'; for(int i = 0; i < (int)v.size(); i++) { if(i) { os << ','; } os << v[i]; } os << '}'; return os; } void debugg() { cerr << endl; } template <class T, class... Args> void debugg(const T &x, const Args &... args) { cerr << " " << x; debugg(args...); } #define debug(...) \ cerr << __LINE__ << " [" << #__VA_ARGS__ << "]: ", debugg(__VA_ARGS__) #define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl #else #define debug(...) (void(0)) #define dump(x) (void(0)) #endif using namespace std; typedef long long ll; typedef vector<ll> vl; typedef vector<vl> vvl; typedef vector<char> vc; typedef vector<string> vs; typedef vector<bool> vb; typedef vector<double> vd; typedef pair<ll,ll> P; typedef pair<int,int> pii; typedef vector<P> vpl; typedef tuple<ll,ll,ll> tapu; #define rep(i,n) for(int i=0; i<(n); i++) #define REP(i,a,b) for(int i=(a); i<(b); i++) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() const int inf = (1<<30)-1; const ll linf = 1LL<<61; const int MAX = 510000; int dy[8] = {0,1,0,-1,1,-1,-1,1}; int dx[8] = {-1,0,1,0,1,-1,1,-1}; const double pi = acos(-1); const double eps = 1e-7; template<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){ if(a>b){ a = b; return true; } else return false; } template<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){ if(a<b){ a = b; return true; } else return false; } template<typename T> inline void print(T &a){ int sz = a.size(); for(auto itr = a.begin(); itr != a.end(); itr++){ cout << *itr; sz--; if(sz) cout << " "; } cout << "\n"; } template<typename T1,typename T2> inline void print2(T1 a, T2 b){ cout << a << " " << b << "\n"; } template<typename T1,typename T2,typename T3> inline void print3(T1 a, T2 b, T3 c){ cout << a << " " << b << " " << c << "\n"; } void mark() {cout << "#" << "\n";} ll pcount(ll x) {return __builtin_popcountll(x);} //#include <atcoder/maxflow> //using namespace atcoder; //const int mod = 1e9 + 7; const int mod = 998244353; using tud = tuple<double,double,double>; array<double,3> dp[55][55][55][55]; bool v[55][55][55][55]; array<double,3> f(int n, int a, int b, int c){ if(n == 0) return {0,0,0}; if(v[n][a][b][c]) return dp[n][a][b][c]; v[n][a][b][c] = true; if(a == 1 && b == 1 && c == 1) return dp[n][a][b][c] = {0,0,0}; array<double,3> res = {0,0,0}; ll s = a+b+c; ll al = s * (s-1) / 2; if(a >= 2){ auto r = f(n-1,a-1,b,c); r[0] += 1; rep(i,3) res[i] += r[i] * a * (a-1) / 2 / al; } if(b >= 2){ auto r = f(n-1,a,b-1,c); r[1] += 1; rep(i,3) res[i] += r[i] * b * (b-1) / 2 / al; } if(c >= 2){ auto r = f(n-1,a,b,c-1); r[2] += 1; rep(i,3) res[i] += r[i] * c * (c-1) / 2 / al; } auto r = f(n-1,a,b,c); rep(i,3) res[i] += r[i] * (al - a*(a-1)/2 - b*(b-1)/2 - c*(c-1)/2) / al; return dp[n][a][b][c] = res; } int main(){ int a,b,c,n; cin >> a >> b >> c >> n; auto res = f(n,a,b,c); printf("%.10f %.10f %.10f\n",res[0],res[1],res[2]); }