結果
| 問題 |
No.1558 Derby Live
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-10-14 17:15:49 |
| 言語 | Rust (1.83.0 + proconio) |
| 結果 |
AC
|
| 実行時間 | 200 ms / 2,000 ms |
| コード長 | 4,044 bytes |
| コンパイル時間 | 13,159 ms |
| コンパイル使用メモリ | 387,112 KB |
| 実行使用メモリ | 7,936 KB |
| 最終ジャッジ日時 | 2024-09-17 16:34:08 |
| 合計ジャッジ時間 | 21,965 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 33 |
ソースコード
#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::Read;
#[allow(dead_code)]
fn getline() -> String {
let mut ret = String::new();
std::io::stdin().read_line(&mut ret).ok().unwrap();
ret
}
fn get_word() -> String {
let stdin = std::io::stdin();
let mut stdin=stdin.lock();
let mut u8b: [u8; 1] = [0];
loop {
let mut buf: Vec<u8> = Vec::with_capacity(16);
loop {
let res = stdin.read(&mut u8b);
if res.unwrap_or(0) == 0 || u8b[0] <= b' ' {
break;
} else {
buf.push(u8b[0]);
}
}
if buf.len() >= 1 {
let ret = String::from_utf8(buf).unwrap();
return ret;
}
}
}
#[allow(dead_code)]
fn get<T: std::str::FromStr>() -> T { get_word().parse().ok().unwrap() }
/**
* Segment Tree. This data structure is useful for fast folding on intervals of an array
* whose elements are elements of monoid I. Note that constructing this tree requires the identity
* element of I and the operation of I.
* Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581)
* AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001)
* yukicoder No. 833 (https://yukicoder.me/submissions/703521)
*/
struct SegTree<I, BiOp> {
n: usize,
dat: Vec<I>,
op: BiOp,
e: I,
}
impl<I, BiOp> SegTree<I, BiOp>
where BiOp: Fn(I, I) -> I,
I: Clone {
pub fn new(n_: usize, op: BiOp, e: I) -> Self {
let mut n = 1;
while n < n_ { n *= 2; } // n is a power of 2
SegTree {n: n, dat: vec![e.clone(); 2 * n - 1], op: op, e: e}
}
/* ary[k] <- v */
pub fn update(&mut self, idx: usize, v: I) {
let mut k = idx + self.n - 1;
self.dat[k] = v;
while k > 0 {
k = (k - 1) / 2;
self.dat[k] = (self.op)(self.dat[2 * k + 1].clone(), self.dat[2 * k + 2].clone());
}
}
/* [a, b) (note: half-inclusive)
* http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */
#[allow(unused)]
pub fn query(&self, mut a: usize, mut b: usize) -> I {
let mut left = self.e.clone();
let mut right = self.e.clone();
a += self.n - 1;
b += self.n - 1;
while a < b {
if (a & 1) == 0 {
left = (self.op)(left, self.dat[a].clone());
}
if (b & 1) == 0 {
right = (self.op)(self.dat[b - 1].clone(), right);
}
a = a / 2;
b = (b - 1) / 2;
}
(self.op)(left, right)
}
}
fn solve() {
let n: usize = get();
let m: usize = get();
let q: usize = get();
let mut st = SegTree::new(m, |a, b| {
let mut c = vec![0; n];
for i in 0..n {
c[i] = b[a[i]];
}
c
}, (0..n).collect::<Vec<_>>());
for _ in 0..q {
let ty: i32 = get();
if ty == 1 {
let d = get::<usize>() - 1;
let p: Vec<_> = (0..n).map(|_| get::<usize>() - 1).collect();
st.update(d, p);
} else if ty == 2 {
let s: usize = get();
let k = st.query(0, s);
let mut v = vec![0; n];
for i in 0..n {
v[k[i]] = i;
}
for i in 0..n {
print!("{}{}", v[i] + 1, if i + 1 == n { "\n" } else { " " });
}
} else {
let l = get::<usize>() - 1;
let r: usize = get();
let k = st.query(l, r);
let mut ans = 0;
for i in 0..n {
ans += (i as i32 - k[i] as i32).abs();
}
println!("{}", ans);
}
}
}
fn main() {
// In order to avoid potential stack overflow, spawn a new thread.
let stack_size = 104_857_600; // 100 MB
let thd = std::thread::Builder::new().stack_size(stack_size);
thd.spawn(|| solve()).unwrap().join().unwrap();
}