結果

問題 No.1718 Random Squirrel
ユーザー tokusakurai
提出日時 2021-10-22 23:55:32
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 155 ms / 2,000 ms
コード長 7,515 bytes
コンパイル時間 3,256 ms
コンパイル使用メモリ 221,240 KB
最終ジャッジ日時 2025-01-25 04:37:30
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < n; i++)
#define rep2(i, x, n) for (int i = x; i <= n; i++)
#define rep3(i, x, n) for (int i = x; i >= n; i--)
#define each(e, v) for (auto &e : v)
#define pb push_back
#define eb emplace_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define sz(x) (int)x.size()
using ll = long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;
template <typename T>
bool chmax(T &x, const T &y) {
return (x < y) ? (x = y, true) : false;
}
template <typename T>
bool chmin(T &x, const T &y) {
return (x > y) ? (x = y, true) : false;
}
template <typename T>
int flg(T x, int i) {
return (x >> i) & 1;
}
template <typename T>
void print(const vector<T> &v, T x = 0) {
int n = v.size();
for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');
}
template <typename T>
void printn(const vector<T> &v, T x = 0) {
int n = v.size();
for (int i = 0; i < n; i++) cout << v[i] + x << '\n';
}
template <typename T>
int lb(const vector<T> &v, T x) {
return lower_bound(begin(v), end(v), x) - begin(v);
}
template <typename T>
int ub(const vector<T> &v, T x) {
return upper_bound(begin(v), end(v), x) - begin(v);
}
template <typename T>
void rearrange(vector<T> &v) {
sort(begin(v), end(v));
v.erase(unique(begin(v), end(v)), end(v));
}
template <typename T>
vector<int> id_sort(const vector<T> &v, bool greater = false) {
int n = v.size();
vector<int> ret(n);
iota(begin(ret), end(ret), 0);
sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });
return ret;
}
struct io_setup {
io_setup() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout << fixed << setprecision(15);
}
} io_setup;
const int inf = (1 << 30) - 1;
const ll INF = (1LL << 60) - 1;
const int MOD = 1000000007;
// const int MOD = 998244353;
template <bool directed = false>
struct Graph {
struct edge {
int to, id;
edge(int to, int id) : to(to), id(id) {}
};
vector<vector<edge>> es;
const int n;
int m;
vector<vector<int>> par; // par[i][j] := j2^i
vector<int> depth;
int height;
vector<int> ids, col;
int cnt = 0;
Graph(int n) : es(n), n(n), m(0), depth(n), ids(n), col(n, inf) {
height = 1;
while ((1 << height) < n) height++;
par.assign(height, vector<int>(n));
}
void add_edge(int from, int to) {
es[from].emplace_back(to, m);
if (!directed) es[to].emplace_back(from, m);
m++;
}
void prepare(int now, int pre = -1) {
if (pre == -1) depth[now] = 0;
par[0][now] = pre;
ids[now] = cnt++;
for (auto &e : es[now]) {
if (e.to != pre) {
depth[e.to] = depth[now] + 1;
prepare(e.to, now);
}
}
}
void build(int root = 0) { // root
prepare(root);
for (int j = 0; j < height - 1; j++) {
for (int i = 0; i < n; i++) {
if (par[j][i] == -1) {
par[j + 1][i] = -1;
} else {
par[j + 1][i] = par[j][par[j][i]];
}
}
}
}
int lca(int u, int v) {
if (depth[u] < depth[v]) swap(u, v);
int D = depth[u] - depth[v];
for (int i = 0; i < height; i++) {
if ((D >> i) & 1) u = par[i][u];
}
if (u == v) return u;
for (int i = height - 1; i >= 0; i--) {
if (par[i][u] != par[i][v]) u = par[i][u], v = par[i][v];
}
return par[0][u];
}
int dist(int u, int v) { return depth[u] + depth[v] - 2 * depth[lca(u, v)]; }
void path(int u, int v) {
while (u != v) {
if (depth[u] < depth[v]) swap(u, v);
col[u] = 0;
u = par[0][u];
}
col[u] = 0;
}
vector<int> solve(vector<int> c) {
build();
sort(all(c), [&](int i, int j) { return ids[i] < ids[j]; });
int K = sz(c);
col[c[0]] = 0;
rep(i, K - 1) path(c[i], c[i + 1]);
int T = 0;
queue<int> que;
rep(i, n) {
if (col[i] == 0) T++, que.emplace(i);
}
vector<int> ret(n, 2 * (T - 1));
while (!empty(que)) {
int i = que.front();
que.pop();
each(e, es[i]) {
if (chmin(col[e.to], col[i] + 1)) que.emplace(e.to);
}
}
rep(i, n) ret[i] += 2 * col[i];
return ret;
}
};
template <typename sum_t, typename key_t, bool directed = false>
struct Rerooting {
struct edge {
int to;
key_t data;
sum_t dp, ndp; // todp()fromdp()
edge(int to, key_t data, sum_t dp, sum_t ndp) : to(to), data(data), dp(dp), ndp(ndp) {}
};
using F = function<sum_t(sum_t, sum_t)>;
using G = function<sum_t(sum_t, key_t)>;
vector<vector<edge>> es;
vector<sum_t> subdp, dp; // dpdp
const F f; // 12
const G g; // 1
const sum_t e1; // f
vector<sum_t> base; // 1dp
Rerooting(int n, const F &f, const G &g, const sum_t &e1, const vector<sum_t> &base) : es(n), subdp(base), dp(n), f(f), g(g), e1(e1), base(base)
        {}
void add_edge(int from, int to, const key_t &data) {
es[from].emplace_back(to, data, e1, base[from]);
if (!directed) es[to].emplace_back(from, data, e1, base[to]);
}
void dfs_sub(int now, int pre = -1) {
for (auto &e : es[now]) {
if (e.to == pre) continue;
dfs_sub(e.to, now);
subdp[now] = f(subdp[now], g(subdp[e.to], e.data));
}
}
void dfs_all(int now, const sum_t &top, int pre = -1) {
sum_t S = e1;
for (int i = 0; i < (int)es[now].size(); i++) {
auto &e = es[now][i];
e.ndp = f(e.ndp, S);
e.dp = g(e.to == pre ? top : subdp[e.to], e.data);
S = f(S, e.dp);
}
dp[now] = f(base[now], S);
S = e1;
for (int i = (int)es[now].size() - 1; i >= 0; i--) {
auto &e = es[now][i];
e.ndp = f(e.ndp, S);
if (e.to != pre) dfs_all(e.to, e.ndp, now);
S = f(S, e.dp);
}
}
vector<sum_t> solve() {
dfs_sub(0);
dfs_all(0, e1);
return dp;
}
};
int main() {
int N, K;
cin >> N >> K;
vector<int> u(N - 1), v(N - 1);
rep(i, N - 1) {
cin >> u[i] >> v[i];
u[i]--, v[i]--;
}
vector<int> c(K);
rep(i, K) {
cin >> c[i];
c[i]--;
}
vector<int> base(N, -inf);
rep(i, K) base[c[i]] = 0;
auto f = [](int a, int b) { return max(a, b); };
auto g = [](int a, int b) { return a + b; };
Graph G1(N);
Rerooting<int, int> G2(N, f, g, -inf, base);
rep(i, N - 1) { G2.add_edge(u[i], v[i], 1); }
vector<int> d = G2.solve();
// print(d);
rep(i, N - 1) G1.add_edge(u[i], v[i]);
vector<int> a = G1.solve(c);
rep(i, N) a[i] -= d[i];
printn(a);
}
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