結果
問題 | No.1715 Dinner 2 |
ユーザー | Sumitacchan |
提出日時 | 2021-10-22 23:57:17 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 95 ms / 2,000 ms |
コード長 | 2,834 bytes |
コンパイル時間 | 2,203 ms |
コンパイル使用メモリ | 205,924 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-24 07:19:11 |
合計ジャッジ時間 | 3,988 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,812 KB |
testcase_01 | AC | 1 ms
6,944 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 2 ms
6,940 KB |
testcase_05 | AC | 1 ms
6,944 KB |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | AC | 2 ms
6,944 KB |
testcase_08 | AC | 1 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,944 KB |
testcase_11 | AC | 75 ms
6,940 KB |
testcase_12 | AC | 61 ms
6,944 KB |
testcase_13 | AC | 52 ms
6,940 KB |
testcase_14 | AC | 61 ms
6,944 KB |
testcase_15 | AC | 62 ms
6,940 KB |
testcase_16 | AC | 59 ms
6,940 KB |
testcase_17 | AC | 38 ms
6,940 KB |
testcase_18 | AC | 3 ms
6,940 KB |
testcase_19 | AC | 4 ms
6,940 KB |
testcase_20 | AC | 3 ms
6,944 KB |
testcase_21 | AC | 3 ms
6,940 KB |
testcase_22 | AC | 3 ms
6,944 KB |
testcase_23 | AC | 4 ms
6,940 KB |
testcase_24 | AC | 3 ms
6,940 KB |
testcase_25 | AC | 10 ms
6,944 KB |
testcase_26 | AC | 7 ms
6,940 KB |
testcase_27 | AC | 7 ms
6,940 KB |
testcase_28 | AC | 9 ms
6,940 KB |
testcase_29 | AC | 9 ms
6,944 KB |
testcase_30 | AC | 9 ms
6,940 KB |
testcase_31 | AC | 9 ms
6,944 KB |
testcase_32 | AC | 95 ms
6,940 KB |
testcase_33 | AC | 94 ms
6,940 KB |
testcase_34 | AC | 94 ms
6,944 KB |
testcase_35 | AC | 95 ms
6,940 KB |
testcase_36 | AC | 2 ms
6,940 KB |
testcase_37 | AC | 1 ms
6,944 KB |
testcase_38 | AC | 4 ms
6,940 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; //using namespace atcoder; struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define FOR(i, begin, end) for(int i=(begin);i<(end);i++) #define REP(i, n) FOR(i,0,n) #define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--) #define IREP(i, n) IFOR(i,0,n) #define Sort(v) sort(v.begin(), v.end()) #define Reverse(v) reverse(v.begin(), v.end()) #define all(v) v.begin(),v.end() #define SZ(v) ((int)v.size()) #define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x)) #define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x)) #define chmax(a, b) a = max(a, b) #define chmin(a, b) a = min(a, b) #define bit(n) (1LL<<(n)) #define debug(x) cout << #x << "=" << x << endl; #define vdebug(v) { cout << #v << "=" << endl; REP(i_debug, (int)v.size()){ cout << v[i_debug] << ","; } cout << endl; } #define mdebug(m) { cout << #m << "=" << endl; REP(i_debug, (int)m.size()){ REP(j_debug, (int)m[i_debug].size()){ cout << m[i_debug][j_debug] << ","; } cout << endl;} } #define pb push_back #define fi first #define se second #define int long long #define INF 1000000000000000000 template<typename T> istream &operator>>(istream &is, vector<T> &v){ for (auto &x : v) is >> x; return is; } template<typename T> ostream &operator<<(ostream &os, vector<T> &v){ for(int i = 0; i < (int)v.size(); i++) { cout << v[i]; if(i != (int)v.size() - 1) cout << endl; }; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p){ cout << '(' << p.first << ',' << p.second << ')'; return os; } template<typename T> void Out(T x) { cout << x << endl; } template<typename T1, typename T2> void chOut(bool f, T1 y, T2 n) { if(f) Out(y); else Out(n); } using vec = vector<int>; using mat = vector<vec>; using Pii = pair<int, int>; using v_bool = vector<bool>; using v_Pii = vector<Pii>; //int dx[4] = {1,0,-1,0}; //int dy[4] = {0,1,0,-1}; //char d[4] = {'D','R','U','L'}; const int mod = 1000000007; //const int mod = 998244353; signed main(){ int N, D; cin >> N >> D; vec P(N), Q(N); REP(i, N) cin >> P[i] >> Q[i]; int ng = 0, ok = 1000000000; while(ok - ng > 1){ int mid = (ok + ng) / 2; vec dp(N, mid); REP(d, D){ vec ml(N + 1, -1), mr(N + 1, -1); REP(i, N) ml[i + 1] = max(ml[i], dp[i]); IREP(i, N) mr[i] = max(mr[i + 1], dp[i]); REP(i, N){ int mm = max(ml[i], mr[i + 1]); if(mm >= P[i]) dp[i] = mm - P[i] + Q[i]; else dp[i] = -1; } } bool f = false; REP(i, N) if(dp[i] >= 0) f = true; if(f) ok = mid; else ng = mid; } Out(-ok); return 0; }