結果
問題 | No.649 ここでちょっとQK! |
ユーザー |
|
提出日時 | 2021-10-24 12:00:03 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 755 ms / 3,000 ms |
コード長 | 3,627 bytes |
コンパイル時間 | 3,267 ms |
コンパイル使用メモリ | 195,784 KB |
最終ジャッジ日時 | 2025-01-25 05:06:57 |
ジャッジサーバーID (参考情報) |
judge5 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 32 |
ソースコード
#include<bits/stdc++.h>using namespace std;#define rep(i,n) for(ll i=0;i<n;i++)#define repl(i,l,r) for(ll i=(l);i<(r);i++)#define per(i,n) for(ll i=(n)-1;i>=0;i--)#define perl(i,r,l) for(ll i=r-1;i>=l;i--)#define fi first#define se second#define pb push_back#define ins insert#define pqueue(x) priority_queue<x,vector<x>,greater<x>>#define all(x) (x).begin(),(x).end()#define CST(x) cout<<fixed<<setprecision(x)#define rev(x) reverse(x);using ll=long long;using vl=vector<ll>;using vvl=vector<vector<ll>>;using pl=pair<ll,ll>;using vpl=vector<pl>;using vvpl=vector<vpl>;const ll MOD=1000000007;const ll MOD9=998244353;const int inf=2e9+1;const ll INF=4e18;const ll dy[8]={-1,0,1,0,1,1,-1,-1};const ll dx[8]={0,-1,0,1,1,-1,1,-1};template <typename T> inline bool chmax(T &a, T b) {return ((a < b) ? (a = b, true) : (false));}template <typename T> inline bool chmin(T &a, T b) {return ((a > b) ? (a = b, true) : (false));}template<typename U = unsigned, int B = 32>class binary_trie {struct node {int cnt;node *ch[2];node() : cnt(0), ch{ nullptr, nullptr } {}};node* add(node* t, U val, int b = B - 1) {if (!t) t = new node;t->cnt += 1;if (b < 0) return t;bool f = (val >> (U)b) & (U)1;t->ch[f] = add(t->ch[f], val, b - 1);return t;}node* sub(node* t, U val, int b = B - 1) {assert(t);t->cnt -= 1;if (t->cnt == 0) return nullptr;if (b < 0) return t;bool f = (val >> (U)b) & (U)1;t->ch[f] = sub(t->ch[f], val, b - 1);return t;}U get_min(node* t, U val, int b = B - 1) const {assert(t);if (b < 0) return 0;bool f = (val >> (U)b) & (U)1; f ^= !t->ch[f];return get_min(t->ch[f], val, b - 1) | ((U)f << (U)b);}U get(node* t, int k, int b = B - 1) const {if (b < 0) return 0;int m = t->ch[0] ? t->ch[0]->cnt : 0;return k < m ? get(t->ch[0], k, b - 1) : get(t->ch[1], k - m, b - 1) | ((U)1 << (U)b);}int count_lower(node* t, U val, int b = B - 1) {if (!t || b < 0) return 0;bool f = (val >> (U)b) & (U)1;return (f && t->ch[0] ? t->ch[0]->cnt : 0) + count_lower(t->ch[f], val, b - 1);}node *root;public:binary_trie() : root(nullptr) {}int size() const {return root ? root->cnt : 0;}bool empty() const {return !root;}void insert(U val) {root = add(root, val);}void erase(U val) {root = sub(root, val);}U max_element(U bias = 0) const {return get_min(root, ~bias);}U min_element(U bias = 0) const {return get_min(root, bias);}int lower_bound(U val) { // return idreturn count_lower(root, val);}int upper_bound(U val) { // return idreturn count_lower(root, val + 1);}U operator[](int k) const {assert(0 <= k && k < size());return get(root, k);}int count(U val) const {if (!root) return 0;node *t = root;for (int i = B - 1; i >= 0; i--) {t = t->ch[(val >> (U)i) & (U)1];if (!t) return 0;}return t->cnt;}};int main(){ll q,k;cin >> q >> k;binary_trie<ll,62> bt;while(q--){ll t;cin >> t;if(t==1){ll x;cin >> x;bt.insert(x);}else{ll p=bt.size();if(p<k)cout << -1 << endl;else{ll ans=bt[k-1];cout << ans << endl;bt.erase(ans);}}}}