結果

問題 No.1718 Random Squirrel
ユーザー leaf_1415
提出日時 2021-10-26 13:48:48
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
AC  
実行時間 280 ms / 2,000 ms
コード長 9,383 bytes
コンパイル時間 1,569 ms
コンパイル使用メモリ 115,372 KB
実行使用メモリ 30,116 KB
最終ジャッジ日時 2024-10-05 08:33:19
合計ジャッジ時間 7,687 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#include <unordered_set>
#include <unordered_map>
#define rep(x, s, t) for(ll x = (s); (x) <= (t); (x)++)
#define per(x, s, t) for(ll x = (s); (x) >= (t); (x)--)
#define reps(x, s) for(ll x = 0; (x) < (ll)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define all(x) (x).begin(),(x).end()
#define outl(...) dump_func(__VA_ARGS__)
#define outf(x) cout << fixed << setprecision(16) << (x) << endl
#define inf 2e18
#define eps 1e-9
const double PI = 3.1415926535897932384626433;
using namespace std;
typedef long long llint;
typedef long long ll;
typedef pair<ll, ll> P;
struct edge{
ll to, cost;
edge(){}
edge(ll a, ll b){ to = a, cost = b;}
};
const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};
int mod = 1000000007;
//int mod = 998244353;
struct mint{
int x;
mint(ll y = 0){if(y < 0 || y >= mod) y = (y%mod+mod)%mod; x = y;}
mint(const mint &ope) {x = ope.x;}
mint operator-(){return mint(-x);}
mint operator+(const mint &ope){return mint(x) += ope;}
mint operator-(const mint &ope){return mint(x) -= ope;}
mint operator*(const mint &ope){return mint(x) *= ope;}
mint operator/(const mint &ope){return mint(x) /= ope;}
mint& operator+=(const mint &ope){
x += ope.x;
if(x >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint &ope){
x += mod - ope.x;
if(x >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint &ope){
ll tmp = x;
tmp *= ope.x, tmp %= mod;
x = tmp;
return *this;
}
mint& operator/=(const mint &ope){
ll n = mod-2; mint mul = ope;
while(n){
if(n & 1) *this *= mul;
mul *= mul;
n >>= 1;
}
return *this;
}
mint inverse(){return mint(1) / *this;}
bool operator ==(const mint &ope){return x == ope.x;}
bool operator !=(const mint &ope){return x != ope.x;}
bool operator <(const mint &ope){return x < ope.x;}
};
mint modpow(mint a, ll n){
if(n == 0) return mint(1);
if(n % 2) return a * modpow(a, n-1);
else return modpow(a*a, n/2);
}
istream& operator >>(istream &is, mint &ope){
ll t; is >> t, ope.x = t;
return is;
}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}
vector<mint> fact, fact_inv;
void make_fact(int n){
fact.resize(n+1), fact_inv.resize(n+1);
fact[0] = mint(1); rep(i, 1, n) fact[i] = fact[i-1] * mint(i);
fact_inv[n] = fact[n].inverse(); per(i, n-1, 0) fact_inv[i] = fact_inv[i+1] * mint(i+1);
}
mint comb(int n, int k){ if(n < 0 || k < 0 || n < k) return mint(0); return fact[n] * fact_inv[k] * fact_inv[n-k];}
mint perm(int n, int k){ return comb(n, k) * fact[k]; }
vector<int> prime, pvec;
void make_prime(int n){
prime.resize(n+1);
rep(i, 2, n){
if(prime[i]) continue;
for(int j = i; j <= n; j+=i) prime[j] = i;
}
rep(i, 2, n) if(prime[i] == i) pvec.push_back(i);
}
bool exceed(ll x, ll y, ll m){return x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "YES" << endl; }
void no(){ cout << "NO" << endl; }
ll floor(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return a/b; else return -((-a+b-1)/b); }
ll ceil(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return (a+b-1)/b; else return -((-a)/b); }
ll modulo(ll a, ll b){ b = abs(b); return a - floor(a, b) * b; }
ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;}
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll lcm(ll a, ll b){return a/gcd(a, b)*b;}
ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;}
ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;}
string lltos(ll x){string ret; for(;x;x/=10) ret += x % 10 + '0'; reverse(ret.begin(), ret.end()); return ret;}
ll stoll(string &s){ll ret = 0; for(auto c : s) ret *= 10, ret += c - '0'; return ret;}
template<typename T>
void uniq(T &vec){ sort(vec.begin(), vec.end()); vec.erase(unique(vec.begin(), vec.end()), vec.end());}
template<class S, class T> pair<S, T>& operator+=(pair<S,T> &s, const pair<S,T> &t){
s.first += t.first, s.second += t.second;
return s;
}
template<class S, class T> pair<S, T>& operator-=(pair<S,T> &s, const pair<S,T> &t){
s.first -= t.first, s.second -= t.second;
return s;
}
template<class S, class T> pair<S, T> operator+(const pair<S,T> &s, const pair<S,T> &t){
return pair<S,T>(s.first+t.first, s.second+t.second);
}
template<class S, class T> pair<S, T> operator-(const pair<S,T> &s, const pair<S,T> &t){
return pair<S,T>(s.first-t.first, s.second-t.second);
}
template<typename T>
ostream& operator << (ostream& os, vector<T>& vec) {
reps(i, vec) os << vec[i] << (i + 1 == vec.size() ? "" : " "); return os;
}
template<typename T>
ostream& operator << (ostream& os, const vector<T>& vec) {
reps(i, vec) os << vec[i] << (i + 1 == vec.size() ? "" : " "); return os;
}
template<typename T>
ostream& operator << (ostream& os, deque<T>& deq) {
reps(i, deq) os << deq[i] << (i + 1 == deq.size() ? "" : " "); return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, pair<T, U>& pair_var) {
os << "(" << pair_var.first << ", " << pair_var.second << ")";
return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, const pair<T, U>& pair_var) {
os << "(" << pair_var.first << ", " << pair_var.second << ")";
return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, map<T, U>& map_var) {
for(typename map<T, U>::iterator itr = map_var.begin(); itr != map_var.end(); itr++) {
os << "(" << itr->first << ", " << itr->second << ")";
itr++; if(itr != map_var.end()) os << ","; itr--;
}
return os;
}
template<typename T>
ostream& operator << (ostream& os, set<T>& set_var) {
for(typename set<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
}
return os;
}
template<typename T>
ostream& operator << (ostream& os, multiset<T>& set_var) {
for(typename multiset<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
}
return os;
}
template<typename T>
void outa(T a[], ll s, ll t){rep(i, s, t){ cout << a[i]; if(i < t) cout << " ";}cout << endl;}
void dump_func(){cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail) {
cout << head;
if(sizeof...(Tail) > 0) cout << " ";
dump_func(std::move(tail)...);
}
ll n, k;
vector<ll> G[100005];
ll sum[100005], dif[100005], ans[100005];
bool b[100005];
void dfs(int v, int p)
{
for(auto u : G[v]){
if(u == p) continue;
dfs(u, v);
sum[v] += sum[u];
}
if(b[v]) sum[v]++;
}
void dfs2(int v, int p)
{
for(auto u : G[v]){
if(u == p) continue;
if(sum[u] < k) dif[u] += 2;
if(sum[u]) dif[1] += 2, dif[u] -= 2;
dfs2(u, v);
}
}
void dfs3(int v, int p, ll s)
{
s += dif[v], ans[v] = s;
for(auto u : G[v]){
if(u == p) continue;
dfs3(u, v, s);
}
}
struct Rerooting{
typedef ll T;
struct edge{
int to;
edge(){}
edge(int a){to = a;}
};
int n;
vector<vector<edge> > G;
vector<int> parent;
vector<T> dp, dp2, ans;
vector<T> lsum, rsum;
Rerooting(){};
Rerooting(int n){
this->n = n;
init();
}
void init(){
G.clear(), G.resize(n+1);
parent.resize(n+1);
dp.resize(n+1), dp2.resize(n+1);
lsum.resize(n+1), rsum.resize(n+1);
ans.resize(n+1);
}
void add_edge(int u, int v){
G[u].push_back(edge(v));
G[v].push_back(edge(u));
}
T Ident(){ //
return -inf;
}
T ope(T &a, T &b){ //
return max(a, b);
}
T ope2(int v, T sum){ //
ll ret = sum + 1;
if(b[v]) chmax(ret, 0LL);
return ret;
}
T& get(int u, int v){
if(parent[u] == v) return dp2[u];
else return dp[v];
}
void dfs(int v, int p)
{
parent[v] = p;
for(auto e : G[v]) if(e.to != p) dfs(e.to, v);
T sum = Ident();
for(auto e : G[v]) if(e.to != p) sum = ope(sum, get(v, e.to));
dp[v] = ope2(v, sum);
}
void dfs2(int v, int p)
{
ll m = sz(G[v]); T sum;
sum = lsum[0] = Ident();
rep(i, 0, m-1){
sum = ope(sum, get(v, G[v][i].to));
lsum[i+1] = sum;
}
sum = rsum[m+1] = Ident();
per(i, m-1, 0){
sum = ope(sum, get(v, G[v][i].to));
rsum[i+1] = sum;
}
reps(i, G[v]){
int u = G[v][i].to;
if(u == p) continue;
T sum = ope(lsum[i], rsum[i+2]);
dp2[u] = ope2(v, sum);
}
for(auto e : G[v]) if(e.to != p) dfs2(e.to, v);
}
void calc(){
dfs(1, -1), dfs2(1, -1);
rep(i, 1, n){
T sum = Ident();
for(auto e : G[i]) sum = ope(sum, get(i, e.to));
ans[i] = ope2(i, sum);
}
}
void print(){
rep(i, 1, n) for(auto e : G[i]) outl(i, "->", e.to, ":", get(i, e.to));
}
};
int main(void)
{
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n >> k;
Rerooting rt(n);
ll u, v;
rep(i, 1, n-1){
cin >> u >> v;
G[u].push_back(v);
G[v].push_back(u);
rt.add_edge(u, v);
}
rep(i, 1, k) cin >> v, b[v] = true;
dfs(1, -1);
dfs2(1, -1);
dfs3(1, -1, 0);
rt.calc();
rep(i, 1, n) ans[i] -= rt.ans[i];
rep(i, 1, n) outl(ans[i]);
return 0;
}
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