#712120 (C++17) No.1708 Quality of Contest

提出ソース

結果

問題	No.1708 Quality of Contest
ユーザー	stoq
提出日時	2021-11-01 05:48:33
言語	C++17 (gcc 12.3.0 + boost 1.83.0)
結果	AC
実行時間	95 ms / 2,000 ms
コード長	5,129 bytes
コンパイル時間	4,627 ms
コンパイル使用メモリ	274,824 KB
実行使用メモリ	17,024 KB
最終ジャッジ日時	2024-10-09 15:53:32
合計ジャッジ時間	8,845 ms
ジャッジサーバーID （参考情報）	judge5 / judge3

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	15 ms 9,088 KB
testcase_01	AC	16 ms 9,088 KB
testcase_02	AC	16 ms 9,216 KB
testcase_03	AC	17 ms 9,216 KB
testcase_04	AC	17 ms 9,344 KB
testcase_05	AC	17 ms 9,088 KB
testcase_06	AC	17 ms 9,344 KB
testcase_07	AC	17 ms 9,216 KB
testcase_08	AC	16 ms 9,088 KB
testcase_09	AC	82 ms 16,896 KB
testcase_10	AC	92 ms 17,024 KB
testcase_11	AC	92 ms 14,720 KB
testcase_12	AC	92 ms 15,104 KB
testcase_13	AC	92 ms 14,336 KB
testcase_14	AC	92 ms 15,360 KB
testcase_15	AC	95 ms 16,896 KB
testcase_16	AC	95 ms 16,720 KB
testcase_17	AC	93 ms 15,616 KB
testcase_18	AC	94 ms 15,744 KB
testcase_19	AC	94 ms 16,128 KB
testcase_20	AC	93 ms 15,488 KB
testcase_21	AC	93 ms 15,744 KB
testcase_22	AC	92 ms 15,360 KB
testcase_23	AC	94 ms 16,896 KB
testcase_24	AC	89 ms 13,824 KB
testcase_25	AC	88 ms 13,952 KB

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ソースコード

raw source code

#define MOD_TYPE 1

#include <bits/stdc++.h>
using namespace std;

#include <atcoder/all>
//#include <atcoder/modint>
//#include <atcoder/lazysegtree>

using namespace atcoder;

#if 0
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif

#if 0
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
template <typename T>
using extset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#endif

#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif

#pragma region Macros

using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;

#if MOD_TYPE == 1
constexpr ll MOD = ll(1e9 + 7);
#else
#if MOD_TYPE == 2
constexpr ll MOD = 998244353;
#else
constexpr ll MOD = 1000003;
#endif
#endif

using mint = static_modint<MOD>;
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr double PI = acos(-1.0);
constexpr double EPS = 1e-11;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};

#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";
#define UNIQUE(v) v.erase(unique(all(v)), v.end())

struct io_init {
  io_init() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    cout << setprecision(30) << setiosflags(ios::fixed);
  };
} io_init;
template <typename T>
inline bool chmin(T& a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
inline bool chmax(T& a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; }
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T& val) {
  fill((T*)array, (T*)(array + N), val);
}
template <typename T>
vector<T> compress(vector<T>& v) {
  vector<T> val = v;
  sort(all(val)), val.erase(unique(all(val)), val.end());
  for (auto&& vi : v) vi = lower_bound(all(val), vi) - val.begin();
  return val;
}
template <typename T, typename U>
constexpr istream& operator>>(istream& is, pair<T, U>& p) noexcept {
  is >> p.first >> p.second;
  return is;
}
template <typename T, typename U>
constexpr ostream& operator<<(ostream& os, pair<T, U> p) noexcept {
  os << p.first << " " << p.second;
  return os;
}
ostream& operator<<(ostream& os, mint m) {
  os << m.val();
  return os;
}
ostream& operator<<(ostream& os, modint m) {
  os << m.val();
  return os;
}

random_device seed_gen;
mt19937_64 engine(seed_gen());

struct BiCoef {
  vector<mint> fact_, inv_, finv_;
  BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {
    fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);
    for (int i = 2; i < n; i++) {
      fact_[i] = fact_[i - 1] * i;
      inv_[i] = -inv_[MOD % i] * (MOD / i);
      finv_[i] = finv_[i - 1] * inv_[i];
    }
  }
  mint C(ll n, ll k) const noexcept {
    if (n < k || n < 0 || k < 0) return 0;
    return fact_[n] * finv_[k] * finv_[n - k];
  }
  mint P(ll n, ll k) const noexcept { return C(n, k) * fact_[k]; }
  mint H(ll n, ll k) const noexcept { return C(n + k - 1, k); }
  mint Ch1(ll n, ll k) const noexcept {
    if (n < 0 || k < 0) return 0;
    mint res = 0;
    for (int i = 0; i < n; i++)
      res += C(n, i) * mint(n - i).pow(k) * (i & 1 ? -1 : 1);
    return res;
  }
  mint fact(ll n) const noexcept {
    if (n < 0) return 0;
    return fact_[n];
  }
  mint inv(ll n) const noexcept {
    if (n < 0) return 0;
    return inv_[n];
  }
  mint finv(ll n) const noexcept {
    if (n < 0) return 0;
    return finv_[n];
  }
};

BiCoef bc(500010);

// -------------------------------

void solve() {
  int n, m, x;
  cin >> n >> m >> x;
  vector<ll> a(n), b(n);
  rep(i, n) cin >> a[i] >> b[i], b[i]--;
  vector<pll> maxa(m, pll{-1, -1});
  rep(i, n) { chmax(maxa[b[i]], pll{a[i], i}); }
  rep(i, n) {
    if (maxa[b[i]].second == i) a[i] += x;
  }
  sort(all(a), greater<ll>());
  vector<ll> csum(n + 1);
  rep(i, n) csum[i + 1] = csum[i] + a[i];
  int k;
  cin >> k;
  ll ans = 0;
  rep(i, k) {
    int c;
    cin >> c;
    ans += csum[c];
  }
  cout << ans << "\n";
}

int main() { solve(); }

yukicoder

結果

テストケース

ソースコード