結果

問題 No.1779 Magical Swap
ユーザー mkawa2mkawa2
提出日時 2021-12-08 01:08:56
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 270 ms / 2,000 ms
コード長 3,255 bytes
コンパイル時間 171 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 127,104 KB
最終ジャッジ日時 2024-07-16 07:38:38
合計ジャッジ時間 3,683 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 60 ms
63,232 KB
testcase_01 AC 56 ms
63,488 KB
testcase_02 AC 165 ms
78,828 KB
testcase_03 AC 89 ms
77,808 KB
testcase_04 AC 90 ms
90,240 KB
testcase_05 AC 72 ms
82,272 KB
testcase_06 AC 73 ms
84,736 KB
testcase_07 AC 90 ms
89,856 KB
testcase_08 AC 58 ms
65,152 KB
testcase_09 AC 144 ms
85,248 KB
testcase_10 AC 270 ms
119,680 KB
testcase_11 AC 183 ms
98,688 KB
testcase_12 AC 131 ms
82,328 KB
testcase_13 AC 216 ms
110,976 KB
testcase_14 AC 258 ms
127,104 KB
testcase_15 AC 185 ms
79,488 KB
testcase_16 AC 97 ms
92,800 KB
testcase_17 AC 208 ms
78,336 KB
testcase_18 AC 55 ms
63,488 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys

sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = 18446744073709551615
inf = 4294967295
md = 10**9+7
# md = 998244353

class Sieve:
    def __init__(self, n):
        self.plist = [2]  # n以下の素数のリスト
        min_prime_factor = [2, 0]*(n//2+1)
        for x in range(3, n+1, 2):
            if min_prime_factor[x] == 0:
                min_prime_factor[x] = x
                self.plist.append(x)
                if x**2 > n: continue
                for y in range(x**2, n+1, 2*x):
                    if min_prime_factor[y] == 0:
                        min_prime_factor[y] = x
        self.min_prime_factor = min_prime_factor

    def isprime(self, x):
        return self.min_prime_factor[x] == x

    # これが素因数分解(prime factorization)
    def pfct(self, x):
        pp, ee = [], []
        while x > 1:
            mpf = self.min_prime_factor[x]
            if pp and mpf == pp[-1]:
                ee[-1] += 1
            else:
                pp.append(mpf)
                ee.append(1)
            x //= mpf
        return [(p, e) for p, e in zip(pp, ee)]

class UnionFind:
    def __init__(self, n):
        self.table = [-1]*n
        self.mem = [[u] for u in range(n)]
        self.cnt = n

    def root(self, u):
        stack = []
        while self.table[u] >= 0:
            stack.append(u)
            u = self.table[u]
        for v in stack: self.table[v] = u
        return u

    def same(self, u, v):
        return self.root(u) == self.root(v)

    def merge(self, u, v):
        u = self.root(u)
        v = self.root(v)
        if u == v: return False
        su = -self.table[u]
        sv = -self.table[v]
        if su < sv: u, v = v, u
        self.table[u] = -su-sv
        self.table[v] = u
        self.mem[u] += self.mem[v]
        self.mem[v].clear()
        self.cnt -= 1
        return True

    def member(self, u):
        return self.mem[self.root(u)]

    # グループの要素数
    def size(self, u):
        return -self.table[self.root(u)]

from collections import Counter

def solve():
    n = II()
    aa = [0]+LI()
    bb = [0]+LI()
    if aa[1] != bb[1]:
        print("No")
        return

    uf = UnionFind(n+1)
    for p in sv.plist:
        if p*2 > n: break
        for a in range(p*2, n+1, p):
            uf.merge(p, a)

    for ii in uf.mem:
        if not ii or ii[0] == 0: continue
        ca = Counter()
        cb = Counter()
        for i in ii:
            ca[aa[i]] += 1
            cb[bb[i]] += 1
        if ca != cb:
            print("No")
            return

    print("Yes")
    return

sv = Sieve(100005)

for case in range(II()):
    solve()
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