結果

問題 No.1782 ManyCoins
ユーザー koba-e964
提出日時 2021-12-15 01:21:16
言語 Rust
(1.83.0 + proconio)
結果
TLE  
実行時間 -
コード長 2,168 bytes
コンパイル時間 22,281 ms
コンパイル使用メモリ 400,716 KB
実行使用メモリ 42,660 KB
最終ジャッジ日時 2024-07-23 19:45:52
合計ジャッジ時間 30,556 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 11 TLE * 1 -- * 36
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#[allow(unused_imports)]
use std::cmp::*;
use std::collections::*;
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
($($r:tt)*) => {
let stdin = std::io::stdin();
let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
let mut next = move || -> String{
bytes.by_ref().map(|r|r.unwrap() as char)
.skip_while(|c|c.is_whitespace())
.take_while(|c|!c.is_whitespace())
.collect()
};
input_inner!{next, $($r)*}
};
}
macro_rules! input_inner {
($next:expr) => {};
($next:expr,) => {};
($next:expr, $var:ident : $t:tt $($r:tt)*) => {
let $var = read_value!($next, $t);
input_inner!{$next $($r)*}
};
}
macro_rules! read_value {
($next:expr, [ $t:tt ; $len:expr ]) => {
(0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
};
($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}
trait Change { fn chmax(&mut self, x: Self); fn chmin(&mut self, x: Self); }
impl<T: PartialOrd> Change for T {
fn chmax(&mut self, x: T) { if *self < x { *self = x; } }
fn chmin(&mut self, x: T) { if *self > x { *self = x; } }
}
fn main() {
input! {
n: usize, l: i64,
w: [i64; n],
}
let x = w[0] as usize;
let mut rem = vec![0; n];
for i in 0..n {
rem[i] = (w[i] % x as i64) as usize;
}
let mut que = BinaryHeap::new();
for i in 0..n {
que.push((-w[i], rem[i]));
}
const INF: i64 = 1 << 40;
let mut d = vec![INF; x];
while let Some((cost, pos)) = que.pop() {
let cost = -cost;
if d[pos] <= cost {
continue;
}
d[pos] = cost;
for i in 0..n {
let (w, c) = ((pos + rem[i]) % x, w[i]);
let newcost = cost + c;
if d[w] > newcost {
d[w] = newcost + 1;
que.push((-newcost, w));
}
}
}
let mut ans = 0;
for i in 0..x {
if d[i] > l { continue; }
ans += (l - d[i]) / x as i64 + 1;
}
println!("{}", ans);
}
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