結果

問題 No.1665 quotient replace
ユーザー 👑 obakyan
提出日時 2022-01-09 00:11:14
言語 Lua
(LuaJit 2.1.1734355927)
結果
TLE  
実行時間 -
コード長 2,203 bytes
コンパイル時間 157 ms
コンパイル使用メモリ 6,688 KB
実行使用メモリ 42,732 KB
最終ジャッジ日時 2024-11-14 09:57:33
合計ジャッジ時間 181,029 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample TLE * 3
other TLE * 41
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ソースコード

diff #
プレゼンテーションモードにする

local bxor = bit.bxor
local mce, mfl, msq, mmi, mma, mab = math.ceil, math.floor, math.sqrt, math.min, math.max, math.abs
local function getprimes(x)
local primes = {}
local allnums = {}
for i = 1, x do allnums[i] = true end
for i = 2, x do
if allnums[i] then
table.insert(primes, i)
local lim = mfl(x / i)
for j = 2, lim do
allnums[j * i] = false
end
end
end
return primes
end
local function getdivisorparts(x, primes)
local prime_num = #primes
local tmp = {}
local lim = mce(msq(x))
local primepos = 1
local dv = primes[primepos]
while primepos <= prime_num and dv <= lim do
if x % dv == 0 then
local t = {}
t.p = dv
t.cnt = 1
x = mfl(x / dv)
while x % dv == 0 do
x = mfl(x / dv)
t.cnt = t.cnt + 1
end
table.insert(tmp, t)
lim = mce(msq(x))
end
if primepos == prime_num then break end
primepos = primepos + 1
dv = primes[primepos]
end
if x ~= 1 then
local t = {}
t.p, t.cnt = x, 1
table.insert(tmp, t)
end
return tmp
end
local function getdivisorCore(divisorparts)
local t = {}
local pat = 1
local len = #divisorparts
local allpat = 1
for i = 1, len do
allpat = allpat * (1 + divisorparts[i].cnt)
end
for t_i_pat = 0, allpat - 1 do
local div = allpat
local i_pat = t_i_pat
local ret = 1
for i = 1, len do
div = mfl(div / (divisorparts[i].cnt + 1))
local mul = mfl(i_pat / div)
i_pat = i_pat % div
for j = 1, mul do
ret = ret * divisorparts[i].p
end
end
table.insert(t, ret)
end
table.remove(t)
return t
end
local function getdivisor(x, primes)
local dvp = getdivisorparts(x, primes)
return getdivisorCore(dvp)
end
local primes = getprimes(1000)
local t = {0}
for i = 2, 1000 * 1000 do
local dv = getdivisor(i, primes)
local m = {}
for j = 1, #dv do m[t[dv[j]]] = true end
for j = 0, 1000 * 1000 do
if not m[j] then t[i] = j break end
end
end
-- print(os.clock())
-- os.exit()
local n = io.read("*n")
local ret = 0
for i = 1, n do
local a = io.read("*n")
ret = bxor(ret, t[a])
end
print(ret == 0 and "black" or "white")
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0