結果

問題 No.1813 Magical Stones
ユーザー yudedako
提出日時 2022-01-30 23:42:14
言語 Scala(Beta)
(3.6.2)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 2,449 bytes
コンパイル時間 14,321 ms
コンパイル使用メモリ 265,512 KB
実行使用メモリ 103,728 KB
最終ジャッジ日時 2024-06-11 08:31:09
合計ジャッジ時間 92,782 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 4
other AC * 25 TLE * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import scala.collection.mutable
import scala.collection.mutable.ArrayBuffer
import scala.io.StdIn.*
import scala.math.*
import scala.util.chaining.*
object DAG:
def dag(graph: Array[ArrayBuffer[Int]]): Array[Int] =
val n = graph.length
val indices = Array.fill(n){0}
val stack = Array.fill(n){0}
val size = Array.fill(n){0}
var pos = 0
var outPos = n - 1
for i <- 0 until n do
if indices(i) == 0 then
stack(pos) = i
pos += 1
while pos > 0 do
pos -= 1
val top = stack(pos)
val edge = graph(top)
if indices(top) == edge.size then
indices(top) = -1
stack(outPos) = top
outPos -= 1
else
var index = indices(top)
while index < edge.length && indices(edge(index)) != 0 do
size(edge(index)) += 1
index += 1
pos += 1
if index < edge.size then
stack(pos) = edge(index)
pos += 1
size(edge(index)) += 1
index += 1
indices(top) = index
val reverseGraph = Array.tabulate(n){i => Array.fill(size(i)){0}}
for from <- graph.indices do
for to <- graph(from) do
size(to) -= 1
reverseGraph(to)(size(to)) = from
val newStack = size
val result = indices
for i <- stack do
if result(i) < 0 then
outPos += 1
result(i) = outPos
newStack(pos) = i
pos += 1
while pos > 0 do
pos -= 1
val from = newStack(pos)
for to <- reverseGraph(from) do
if result(to) < 0 then
result(to) = outPos
size(pos) = to
pos += 1
result
@main def main =
val Array(n, m) = readLine().split(' ').map(_.toInt)
val edges = Array.fill(m){
val Array(a, b) = readLine().split(' ').map(_.toInt - 1)
a -> b
}
val graph = Array.fill(n){ArrayBuffer[Int]()}
for (a, b) <- edges do
graph(a).append(b)
val dag = DAG.dag(graph)
val inDegree = Array.fill(dag.max + 1){0}
val outDegree = Array.fill(inDegree.length){0}
for (i, j) <- edges do
val a = dag(i)
val b = dag(j)
if a != b then
outDegree(a) += 1
inDegree(b) += 1
val greatest = inDegree.count(_ == 0)
val smallest = outDegree.count(_ == 0)
if inDegree.length == 1 then
println(0)
else
println(max(greatest, smallest))
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0