結果
問題 | No.1861 Required Number |
ユーザー | mikam |
提出日時 | 2022-03-04 22:03:49 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
RE
|
実行時間 | - |
コード長 | 2,746 bytes |
コンパイル時間 | 4,452 ms |
コンパイル使用メモリ | 267,004 KB |
実行使用メモリ | 82,640 KB |
最終ジャッジ日時 | 2024-07-18 22:57:42 |
合計ジャッジ時間 | 29,213 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | RE | - |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | RE | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | RE | - |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | RE | - |
testcase_08 | RE | - |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | RE | - |
testcase_11 | RE | - |
testcase_12 | AC | 2 ms
6,944 KB |
testcase_13 | RE | - |
testcase_14 | RE | - |
testcase_15 | WA | - |
testcase_16 | AC | 2 ms
6,944 KB |
testcase_17 | WA | - |
testcase_18 | RE | - |
testcase_19 | RE | - |
testcase_20 | RE | - |
testcase_21 | WA | - |
testcase_22 | RE | - |
testcase_23 | WA | - |
testcase_24 | RE | - |
testcase_25 | RE | - |
testcase_26 | RE | - |
testcase_27 | RE | - |
testcase_28 | RE | - |
testcase_29 | RE | - |
testcase_30 | WA | - |
testcase_31 | RE | - |
testcase_32 | WA | - |
testcase_33 | RE | - |
testcase_34 | RE | - |
testcase_35 | RE | - |
testcase_36 | RE | - |
testcase_37 | RE | - |
testcase_38 | RE | - |
testcase_39 | RE | - |
testcase_40 | RE | - |
testcase_41 | RE | - |
testcase_42 | RE | - |
testcase_43 | RE | - |
testcase_44 | RE | - |
04_evil_1.txt | RE | - |
04_evil_2.txt | RE | - |
04_evil_3.txt | RE | - |
04_evil_4.txt | RE | - |
ソースコード
#include <atcoder/all> using namespace atcoder; #include <bits/stdc++.h> using namespace std; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define all(v) v.begin(),v.end() #define inc(x,l,r) ((l)<=(x)&&(x)<(r)) #define Unique(x) sort(all(x)), x.erase(unique(all(x)), x.end()) typedef long long ll; #define int ll using ld = long double; using vi = vector<int>; using vs = vector<string>; using P = pair<int,int>; using vp = vector<P>; template<typename T> using priority_queue_greater = priority_queue<T, vector<T>, greater<T>>; template<typename T> ostream &operator<<(ostream &os,const vector<T> &v){rep(i,v.size())os<<v[i]<<(i+1!=v.size()?" ":"");return os;} template<typename T> istream &operator>>(istream& is,vector<T> &v){for(T &in:v)is>>in;return is;} template<class... T> void in(T&... a){(cin>> ... >> a);} template<class T> void out(T& a){cout <<a<< '\n';} template<class T,class... Ts> void out(const T&a, const Ts&... b){cout<< a;(cout<<...<<(cout<<' ',b));cout<<'\n';} #define INT(...) int __VA_ARGS__; in(__VA_ARGS__) #define STR(...) string __VA_ARGS__; in(__VA_ARGS__) #define pcnt __builtin_popcount int ceil(int x,int y){return x/y+!!(x%y);} bool ins(string s,string t){return s.find(t)!=string::npos;} P operator+ (const P &p, const P &q){ return P{p.first+q.first,p.second+q.second};} P operator- (const P &p, const P &q){ return P{p.first-q.first,p.second-q.second};} ostream &operator<< (ostream &os, const P &p){os << p.first <<" "<<p.second;return os;} ostream &operator<< (ostream &os, const modint1000000007 &m){os << m.val();return os;} ostream &operator<< (ostream &os, const modint998244353 &m){os << m.val();return os;} template<typename T> bool chmax(T &a, const T b) {if (a < b) {a = b; return true;} else return false; } template<typename T> bool chmin(T &a, const T b) {if (a > b) {a = b; return true;} else return false; } void yesno(bool ok){ cout<<(ok?"Yes":"No")<<endl;} vector<P> dxdy{{1,0},{0,1},{-1,0},{0,-1}}; const int INF = 1e18; //using mint = modint1000000007; //using mint = modint998244353; int dp[10010][1010]; signed main() { cin.tie(0); ios_base::sync_with_stdio(false); cout << fixed << setprecision(20); int n,k;cin>>n>>k; vi a(n);cin>>a; sort(all(a)); dp[0][0]=1; rep(i,n)rep(j,k+1){ dp[i+1][j]+=dp[i][j]; if(j+a[i]<=k)dp[i+1][j+a[i]]+=dp[i][j]; } if(dp[n][k]==0){ cout<<-1<<endl;return 0; } int ans = 0; int t = k; for(int i=n;i>0;i--){ if(dp[i][t]==dp[i-1][t-a[i]]){ ans++; } t-=a[i]; // cout<<t<<endl; } // rep(j,k+1)cout<<j<<" ";cout<<endl; // rep(i,n+1)rep(j,k+1)cout<<dp[i][j]<<" \n"[j==k]; cout<<ans<<endl; return 0; }