結果
問題 | No.1871 divisXor |
ユーザー |
|
提出日時 | 2022-03-11 21:36:37 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 50 ms / 2,000 ms |
コード長 | 2,666 bytes |
コンパイル時間 | 210 ms |
コンパイル使用メモリ | 82,424 KB |
実行使用メモリ | 58,224 KB |
最終ジャッジ日時 | 2024-09-22 12:53:57 |
合計ジャッジ時間 | 4,127 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 29 |
ソースコード
class SegmentTree:def __init__(self, init_val, segfunc, ide_ele):n = len(init_val)self.segfunc = segfuncself.ide_ele = ide_eleself.num = 1 << (n - 1).bit_length()self.tree = [ide_ele] * 2 * self.numself.size = nfor i in range(n):self.tree[self.num + i] = init_val[i]for i in range(self.num - 1, 0, -1):self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])def update(self, k, x):k += self.numself.tree[k] = xwhile k > 1:k >>= 1self.tree[k] = self.segfunc(self.tree[2*k], self.tree[2*k+1])def query(self, l, r):if r==self.size:r = self.numres = self.ide_elel += self.numr += self.numright = []while l < r:if l & 1:res = self.segfunc(res, self.tree[l])l += 1if r & 1:right.append(self.tree[r-1])l >>= 1r >>= 1for e in right[::-1]:res = self.segfunc(res,e)return resdef bisect(self,l,r,x):if r==self.size:r = self.numl += self.numr += self.numsegment = []segment_r = []while l<r:if l&1:segment.append(l)l += 1if r&1:segment_r.append(r-1)l >>= 1r >>= 1segment += segment_r[::-1]tmp = self.ide_elefor pos in segment:check = self.segfunc(tmp,self.tree[pos])if check > x:breakelse:tmp = checkelse:return -1while pos < self.num:check = self.segfunc(tmp,self.tree[2*pos])if check > x:pos = 2 * poselse:tmp = checkpos = 2 * pos + 1return pos - self.numimport sys,random,bisectfrom collections import deque,defaultdictfrom heapq import heapify,heappop,heappushfrom itertools import permutationsfrom math import log,gcdinput = lambda :sys.stdin.readline().rstrip()mi = lambda :map(int,input().split())li = lambda :list(mi())N = int(input())if N==0:exit(print(-1))cnt = [0 for i in range(40)]for k in range(40):if N>>k & 1:if k==0:cnt[0] ^= 1else:cnt[k] ^= 1cnt[k-1] ^= 1res = [pow(2,i) for i in range(40) if cnt[i]]if sum(res) < 2 * N:print(len(res))print(*res)else:print(-1)