結果

問題 No.1871 divisXor
ユーザー chineristAC
提出日時 2022-03-11 21:36:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 50 ms / 2,000 ms
コード長 2,666 bytes
コンパイル時間 210 ms
コンパイル使用メモリ 82,424 KB
実行使用メモリ 58,224 KB
最終ジャッジ日時 2024-09-22 12:53:57
合計ジャッジ時間 4,127 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class SegmentTree:
def __init__(self, init_val, segfunc, ide_ele):
n = len(init_val)
self.segfunc = segfunc
self.ide_ele = ide_ele
self.num = 1 << (n - 1).bit_length()
self.tree = [ide_ele] * 2 * self.num
self.size = n
for i in range(n):
self.tree[self.num + i] = init_val[i]
for i in range(self.num - 1, 0, -1):
self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])
def update(self, k, x):
k += self.num
self.tree[k] = x
while k > 1:
k >>= 1
self.tree[k] = self.segfunc(self.tree[2*k], self.tree[2*k+1])
def query(self, l, r):
if r==self.size:
r = self.num
res = self.ide_ele
l += self.num
r += self.num
right = []
while l < r:
if l & 1:
res = self.segfunc(res, self.tree[l])
l += 1
if r & 1:
right.append(self.tree[r-1])
l >>= 1
r >>= 1
for e in right[::-1]:
res = self.segfunc(res,e)
return res
def bisect(self,l,r,x):
if r==self.size:
r = self.num
l += self.num
r += self.num
segment = []
segment_r = []
while l<r:
if l&1:
segment.append(l)
l += 1
if r&1:
segment_r.append(r-1)
l >>= 1
r >>= 1
segment += segment_r[::-1]
tmp = self.ide_ele
for pos in segment:
check = self.segfunc(tmp,self.tree[pos])
if check > x:
break
else:
tmp = check
else:
return -1
while pos < self.num:
check = self.segfunc(tmp,self.tree[2*pos])
if check > x:
pos = 2 * pos
else:
tmp = check
pos = 2 * pos + 1
return pos - self.num
import sys,random,bisect
from collections import deque,defaultdict
from heapq import heapify,heappop,heappush
from itertools import permutations
from math import log,gcd
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
N = int(input())
if N==0:
exit(print(-1))
cnt = [0 for i in range(40)]
for k in range(40):
if N>>k & 1:
if k==0:
cnt[0] ^= 1
else:
cnt[k] ^= 1
cnt[k-1] ^= 1
res = [pow(2,i) for i in range(40) if cnt[i]]
if sum(res) < 2 * N:
print(len(res))
print(*res)
else:
print(-1)
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