結果

問題 No.1339 循環小数
ユーザー 👑 obakyan
提出日時 2022-04-14 09:36:37
言語 Lua
(LuaJit 2.1.1734355927)
結果
WA  
実行時間 -
コード長 2,572 bytes
コンパイル時間 267 ms
コンパイル使用メモリ 5,376 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-12-24 05:37:20
合計ジャッジ時間 2,113 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge5
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 1
other AC * 27 WA * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

local mce, mfl, msq, mmi, mma, mab = math.ceil, math.floor, math.sqrt, math.min, math.max, math.abs
local function getprimes(x)
  local primes = {}
  local allnums = {}
  for i = 1, x do allnums[i] = true end
  for i = 2, x do
    if allnums[i] then
      table.insert(primes, i)
      local lim = mfl(x / i)
      for j = 2, lim do
        allnums[j * i] = false
      end
    end
  end
  return primes
end
local function getdivisorparts(x, primes)
  local prime_num = #primes
  local tmp = {}
  local lim = mce(msq(x))
  local primepos = 1
  local dv = primes[primepos]
  while primepos <= prime_num and dv <= lim do
    if x % dv == 0 then
      local t = {}
      t.p = dv
      t.cnt = 1
      x = mfl(x / dv)
      while x % dv == 0 do
        x = mfl(x / dv)
        t.cnt = t.cnt + 1
      end
      table.insert(tmp, t)
      lim = mce(msq(x))
    end
    if primepos == prime_num then break end
    primepos = primepos + 1
    dv = primes[primepos]
  end
  if x ~= 1 then
    local t = {}
    t.p, t.cnt = x, 1
    table.insert(tmp, t)
  end
  return tmp
end
local function getdivisorCore(divisorparts)
  local t = {}
  local pat = 1
  local len = #divisorparts
  local allpat = 1
  for i = 1, len do
    allpat = allpat * (1 + divisorparts[i].cnt)
  end
  for t_i_pat = 0, allpat - 1 do
    local div = allpat
    local i_pat = t_i_pat
    local ret = 1
    for i = 1, len do
      div = mfl(div / (divisorparts[i].cnt + 1))
      local mul = mfl(i_pat / div)
      i_pat = i_pat % div
      for j = 1, mul do
        ret = ret * divisorparts[i].p
      end
    end
    table.insert(t, ret)
  end
  table.sort(t)
  return t
end
local function getdivisor(x, primes)
  local dvp = getdivisorparts(x, primes)
  return getdivisorCore(dvp)
end
local primes = getprimes(mce(msq(1000000007)))
local function modpow(src, pow, mod)
  local res = 1LL
  src = src * 1LL
  while 0 < pow do
    if pow % 2 == 1 then
      res = (res * src) % mod
      pow = pow - 1
    end
    src = (src * src) % mod
    pow = mfl(pow / 2)
  end
  return res
end
local q = io.read("*n")
local function solve(n)
  while n % 2 == 0 do
    n = mfl(n / 2)
  end
  while n % 5 == 0 do
    n = mfl(n / 5)
  end
  if n == 1 then return 1 end
  local dvp = getdivisorparts(n, primes)
  local euler = n
  for i = 1, #dvp do
    local v = dvp[i].p
    euler = mfl(euler * (v - 1) / v)
  end
  local dv = getdivisor(euler, primes)
  for i = 1, #dv do
    if modpow(10, dv[i], n) == 1LL then
      return dv[i]
    end
  end
end
for iq = 1, q do
  local n = io.read("*n")
  print(solve(n))
end
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0