結果
| 問題 |
No.1988 Divisor Tiling
|
| コンテスト | |
| ユーザー |
mikam
|
| 提出日時 | 2022-06-24 21:50:29 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 4 ms / 2,000 ms |
| コード長 | 2,920 bytes |
| コンパイル時間 | 4,614 ms |
| コンパイル使用メモリ | 259,768 KB |
| 最終ジャッジ日時 | 2025-01-30 00:17:16 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 32 |
ソースコード
#include <atcoder/all>
using namespace atcoder;
#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define rep2(i,a,b) for (int i = (int)(a); i <= (int)(b); i++)
#define all(v) v.begin(),v.end()
#define inc(x,l,r) ((l)<=(x)&&(x)<(r))
#define Unique(x) sort(all(x)), x.erase(unique(all(x)), x.end())
typedef long long ll;
#define int ll
using ld = long double;
using vi = vector<int>;
using vs = vector<string>;
using P = pair<int,int>;
using vp = vector<P>;
template<typename T> using priority_queue_greater = priority_queue<T, vector<T>, greater<T>>;
template<typename T> ostream &operator<<(ostream &os,const vector<T> &v){rep(i,v.size())os<<v[i]<<(i+1!=v.size()?" ":"");return os;}
template<typename T> istream &operator>>(istream& is,vector<T> &v){for(T &in:v)is>>in;return is;}
template<class... T> void IN(T&... a){(cin>> ... >> a);}
template<class T> void OUT(T& a){cout <<a<< '\n';}
template<class T,class... Ts> void OUT(const T&a, const Ts&... b){cout<< a;(cout<<...<<(cout<<' ',b));cout<<'\n';}
#define INT(...) int __VA_ARGS__; IN(__VA_ARGS__)
#define STR(...) string __VA_ARGS__; IN(__VA_ARGS__)
#define pcnt __builtin_popcount
int ceil(int x,int y){return x/y+!!(x%y);}
bool ins(string s,string t){return s.find(t)!=string::npos;}
P operator+ (const P &p, const P &q){ return P{p.first+q.first,p.second+q.second};}
P operator- (const P &p, const P &q){ return P{p.first-q.first,p.second-q.second};}
ostream &operator<< (ostream &os, const P &p){os << p.first <<" "<<p.second;return os;}
ostream &operator<< (ostream &os, const modint1000000007 &m){os << m.val();return os;}
ostream &operator<< (ostream &os, const modint998244353 &m){os << m.val();return os;}
template<typename T> bool chmax(T &a, const T b) {if (a < b) {a = b; return true;} else return false; }
template<typename T> bool chmin(T &a, const T b) {if (a > b) {a = b; return true;} else return false; }
void yesno(bool ok,string y="Yes",string n="No"){ cout<<(ok?y:n)<<endl;}
vector<P> dxdy{{1,0},{0,1},{-1,0},{0,-1}};
int di[]={-1,0,1,0};
int dj[]={0,1,0,-1};
const int INF = 1e18;
//using mint = modint1000000007;
//using mint = modint998244353;
vi divisor(int n){
vi ret;
for(int i=1;i*i<=n;i++){
if(n%i==0){
ret.push_back(i);
if(i*i!=n)ret.push_back(n/i);
}
}
sort(all(ret));
return ret;
}
signed main() {
cin.tie(0);
ios_base::sync_with_stdio(false);
cout << fixed << setprecision(20);
INT(n,h);
int H = min(h,n/h);
int W = n/H;
vector ans(H,vi(W));
auto div = divisor(n);
div.pop_back();
int cu = 0;
for(auto d:div){
rep(i,d){
// cout<<cu/W<<" "<<cu%W<<endl;
ans[cu/W][cu%W]=d;
cu++;
}
}
if(h!=H)rep(j,W)rep(i,H)cout<<ans[i][j]<<" \n"[i==H-1];
else rep(i,H)rep(j,W)cout << ans[i][j] <<" \n"[j==W-1];
return 0;
}
mikam